question_id string | question string | question_images list | option_1 string | option_2 string | option_3 string | option_4 string | correct_option int64 | numerical_answer string | solution string | solution_images list | subject string | topic string | subtopic string | difficulty string | question_type string | has_image bool | exam string | source_paper string |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
CH-09-Q24 | The maximum number of NO_2 groups that can be introduced by
nitration in benzene is usually | [] | null | 3 | [IMAGE] 3- nitro group can be introduced. | [
"images/image52.jpeg"
] | Chemistry | Organic Chemistry | Organic compounds containing Nitrogen | Moderate | numerical | true | JEE Main | CH-09 Chemistry Paper 26 October.docx | ||||
CH-20-Q15 | Which of the following does not represent the correct order of
the property indicated | [] | $Sc^{3 +} > Cr^{3 +} > Fe^{3 +} > Mn^{3 +}$ionic radii | $Sc < Ti < C < Mn$ Density | $Mn^{2 +} > Ni^{2 +} < CO^{2 +} < Fe^{2 +}$ionic radii | $FeO < CaO > MnO > CuO$Basic nature | 1 | null | $Sc^{3 +} > Cr^{3 +} > Fe^{3 +} > Mn^{3 +}$the correct order
is${Cr}^{+ 3} > {Mn}^{+ 3} > {Fe}^{+ 3} > {Sc}^{+ 3}$ | [] | Chemistry | Inorganic Chemistry | Periodic properties | Tough | single_correct | false | JEE Main | CH-20 Chemistry Paper 12 Dec..docx |
CH-06-Q18 | The quantum numbers of for the electron spin
represent | [] | Rotation of the electron in clockwise and anticlockwise direction
respectively | Rotation of the electron in anticlockwise and clockwise direction
respectively | Magnetic moment of the electron pointing up and down respectively | Two quantum mechanical spin states which have no classical
analogue. | 4 | null | Spin quantum numbers are not solution of Schrodinger's wave
equation. It is a an arbitrary number which has no physical meaning. | [] | Chemistry | Physical Chemistry | Atomic Structure | Moderate | single_correct | false | JEE Main | CH-06 Chemistry Paper 14 October.docx |
CH-19-Q11 | ${CH}_{3}{CH}_{2}{CH}_{2}CN + 2H_{2}\overset{Pd}{\longrightarrow}$
Which of the following compound is formed in the above reaction? | [] | ${CH}_{3}{CH}_{2}{CH}_{2}{CH}_{2}{NH}_{2}$ | ${CH}_{3}{CH}_{2}{CH}_{2}{NH}_{2}$ | ${CH}_{3}{CH}_{2}{CH}_{2}{CH}_{2}{CH}_{2}{NH}_{2}$ | None of the above | 2 | null | Alkyl nitriles are reduced using a metal like palladium,
platinum or nickel as a catalyst.
So,
${CH}_{3}{CH}_{2}{CH}_{2}CN + 2H_{2}\overset{Pd}{\longrightarrow}{CH}_{3}{CH}_{2}{CH}_{2}{CH}_{2}{NH}_{2}$ | [] | Chemistry | Amines | Chemical Reactions of Amines | Moderate | single_correct | false | JEE Main | CH-19 Chemistry Paper 28 Nov. Fourth.docx |
CH-16-Q13 | Among the species, which has the weakest carbon- oxygen bond | [] | CO_2 | CH_3COO^ | CO | CO_3^2 | 4 | null | (1) CO_2 = 2
(2) CH_3COO^-= 1.5
(3) CO = 3
(4) CO_3^2- = 1.33 | [] | Chemistry | Chemical Bonding | Resonance and Bond order Calculation | Easy | single_correct | false | JEE Main | CH-16 Chemistry Paper 25 Nov. Fisrt.docx |
CH-15-Q14 | The number of unpaired electrons in d6, low spin, octahedral
complex is | [] | 4 | 2 | 1 | 0 | 4 | null | In d6, octahedral complex all electron will be
paired because of higher CFSE. | [] | Chemistry | Coordination Compounds | Valence Bond Theory + Crystal Field Theory (Part-II) | Moderate | single_correct | false | JEE Main | CH-15 Chemistry Paper 11 Nov..docx |
CH-28-Q2 | Which is/are correct for real gases? | [] | [IMAGE] constant at constant high temperature | [IMAGE] constant at constant low temperature | [IMAGE] at high temperature | 1 | null | Low P and high temperature gas behaves as an ideal gas.
$\therefore$ PV= constant and $\frac{PV_{m}}{RT} = 1$ | [] | Chemistry | Physical Chemistry | Real Gases | Moderate | single_correct | false | JEE Main | CH-28 Chemistry Paper FST 16 Jan.docx | |
CH-07-Q4 | The compressibility factor of a gas is less than unity at 273 K
and $V_{m}$ = 22.4 L therefore, | [] | P > 1 atm | P = 1 atm | P < 1 atm | P = 2atm | 3 | null | $Z = \frac{\left( PV_{m} \right)_{\text{real }}}{\left( PV_{\text{m }} \right)_{\text{ideal }}} = \frac{P_{\text{real }} \times 22.4}{1 \times 22.4} < 1$
$P_{\text{real }} < 1\text{ atm.}$ | [] | Chemistry | Physical Chemistry | Gaseous state | Moderate | single_correct | false | JEE Main | CH-07 Chemistry Paper 17 October.docx |
CH-25-Q8 | Which of the following compounds on hydrolysis gives acetylene | [] | 1 | null | [
"images/image25.png"
] | Chemistry | Organic Chemistry | Hydrocarbon] | Easy] | single_correct | true | JEE Main | CH-25 Chemistry Paper 7 Jan.docx | |||||
CH-12-Q14 | Benzene reacts with chlorine to form benzene hexachloride in
presence of | [] | Nickel | AlCl_3 | Bright Sunlight | Zinc | 3 | null | [
"images/image1.png"
] | Chemistry | Organic Chemistry | HALOALKANES & HALOARENES | Easy | single_correct | true | JEE Main | CH-12 Chemistry Paper 2 Nov..docx | |
CH-13-Q11 | Which of the following is in the increasing order of the ionic
character? | [] | PbCl_4 < PbCl_2 < CaCl_2 < NaCl | PbCl_2 < PbCl_4 < CaCl_2 < NaCl | PbCl_2 < PbCl_4 < NaCl < CaCl_2 | PbCl_4 < PbCl_2 < NaCl < CaCl_2 | 1 | null | PbCl_4 < PbCl_2 < CaCl_2 < NaCl is the increasing
order of ionic character. | [] | Chemistry | Inorganic Chemistry | P-Block Element | Moderate | single_correct | false | JEE Main | CH-13 Chemistry Paper 4 Nov..docx |
CH-13-Q20 | [IMAGE] In the above reaction A, B and C are the following compounds | [
"images/image31.png"
] | C_6 H_6, C_6 H_5 NO_2 and aniline | C_6 H_6, dinitrobenzene and metanitroaniline | Toluene, metanitrobenzene and metatoluedine | C_6 H_6, C_6 H_5 NO_2 and hydrazobenzene | 4 | null | [
"images/image32.png"
] | Chemistry | Organic Chemistry | Alcohols, Phenols and Ethers | Tough | single_correct | true | JEE Main | CH-13 Chemistry Paper 4 Nov..docx | |
CH-15-Q8 | Graph between concentration of the product and time of the
reaction A→B is of the
Hence graph between $- \frac{d\lbrack A\rbrack}{dt}$ and time will be
of the type | [
"images/image8.png"
] | 3 | null | From given graph x = Kt
i.e. it is a zero order | [
"images/image13.png"
] | Chemistry | Chemical Kinetics | Integrated Rate law : Second Order & Pseudo first order | Moderate | single_correct | true | JEE Main | CH-15 Chemistry Paper 11 Nov..docx | ||||
CH-27-Q5 | Which of the following statement is wrong? | [] | The stability of hydrides increase from NH3 to BiH3 in group 15 of
the periodic table | Nitrogen cannot form dp-pp bond. | Single N - N bond is weaker than the single P - P bond. | N2O4 has two resonance structure | 1 | null | The stability of hydrides decreases from NH3 to BiH3 which can
be observed from their bond dissociation enthalpy. The correct order is
NH3 < PH3 < AsH3 < SbH3 < BiH | [] | Chemistry | Inorganic Chemistry | P-block nitrogen | Moderate | single_correct | false | JEE Main | CH-27 Chemistry Paper 2 15 Jan.docx |
CH-28-Q15 | Which one of the following aqueous solutions will exhibit
highest boiling point? | [] | $0.01M{Na}_{2}{SO}_{4}$ | $0.01M{KNO}_{3}$ | 0.015 M urea | 0.015 M glucose | 1 | null | Elevation in boiling point is a colligative property which
depends upon the number of solute particles. Greater the number of
solute particles in a solution, higher the extent of elevation in
boiling point.
${Na}_{2}{SO}_{4} \rightarrow 2{Na}^{+} + {SO}_{4}^{2 -}$ | [] | Chemistry | Physical Chemistry | Moderate | single_correct | false | JEE Main | CH-28 Chemistry Paper FST 16 Jan.docx | |
CH-14-Q14 | Which of the following compound gives a ketone with Grignard
reagent | [] | Formaldehyde | Ethyl alcohol | Methyl cyanide | Methyl iodide | 3 | null | [
"images/image65.png"
] | Chemistry | Organic Chemistry | Aldehydes, Ketones & Carboxylic Acids | Moderate | single_correct | true | JEE Main | CH-14 Chemistry Paper 7 Nov..docx | |
CH-01-Q20 | Which among the following detergents is nonionic in character ? | [] | Sodium lauryl sulphate | Pentaerythrityl stearate | Cetyltrimethyl ammonium chloride | Sodium n-dodecyl benzene sulphonate20. Identify the product formed
in the reaction | null | null | (2) Pentaerythrityl stearate | [] | Chemistry | single_correct | false | JEE Main | CH-01 Chemistry Paper 1.docx | |||
CH-18-Q23 | When 100 ml of a O2 - O3 mixture was passed through turpentine,
there was reduction of volume by 20 ml. If 100 ml of such a mixture is
heated, what will be the increase in volume? [Hint: O3 is absorbed by | [] | null | 10 | In the mix., volume of O3 = 20 ml, Volume of O2 = 80 ml
on heating 2O3 → 3O2
20 ml O3 will give × 20 = 30 ml O2
total volume = 80 + 30 = 110 ml
increase in volume = 110 - 100 = 10 ml. | [] | Chemistry | Ideal Gas | Eudiometry | Tough | numerical | false | JEE Main | CH-18 Chemistry Paper 27 Nov. Third.docx | ||||
CH-19-Q16 | Total number of atom in one molecule or formula unit of
is? | [
"images/image14.png"
] | 7 | 3 | 4 | 5 | 1 | null | X = CaH2, Y = Ca(OH)2, Z = H2 | [] | Chemistry | S-block | Miscellaneous (Hydrides, Carbides, Nitrates) | Moderate | single_correct | true | JEE Main | CH-19 Chemistry Paper 28 Nov. Fourth.docx |
CH-06-Q22 | How many alkenes give 2-methylbutane on catalytic hydrogenation? | [] | null | 3 | [
"images/image34.png"
] | Chemistry | Organic Chemistry | Hydrocarbons | Moderate | numerical | true | JEE Main | CH-06 Chemistry Paper 14 October.docx | |||||
CH-13-Q13 | Salicylaldehyde can be prepared from
(a) Phenol and chloroform
(b) Phenol, chloroform and sodium hydroxide
(c) Phenol, carbon tetrachloride and NaOH
(d) None of these | [] | 2 | null | [
"images/image24.png"
] | Chemistry | Organic Chemistry | Alcohols, Phenols and Ethers | Moderate | single_correct | true | JEE Main | CH-13 Chemistry Paper 4 Nov..docx | |||||
CH-04-Q5 | Which of the following is correct statement?
(A) The ratio of e/m value for H^+ & He^+ is 1: 2.
(B) The ratio of e/m value for He^+ & Li^2+ is 7: 8.
(C) The ratio of e/m value for Li^2+ & Be^3+ is 9: 8.
(D) The ratio of e/m value for [IMAGE] &
[IMAGE] is 1: 2.
? | [
"images/image6.png",
"images/image7.png"
] | H^+ He^+ e/m 1: 2
(2) He^+ Li^2+ e/m 7: 8 | Li^2+ Be^3+ e/m 9: 8 | 2: 1 | null | 2 | Ratio of e/m value for H^+ & He^+ = 4: 1
Ratio of e/m value for He^+ & Li^2+ = 7: 8
Ratio of e/m value for Li^2+ & Be^3+= 16: 21
Ratio of e/m value for [IMAGE] & [IMAGE] = 2: 1
H^+ He^+ e/m = 4: 1
He^+ Li^2+ e/m = 7: 8
Li^2+ Be^3+ e/m = 16: 21
= 2: 1 | [
"images/image6.png",
"images/image7.png",
"images/image8.png",
"images/image9.png"
] | Chemistry | Physical Chemistry | Atomic Structure | Moderate | numerical | true | JEE Main | CH-04 Paper 02 Chemistry with Hindi 22-8-2020.docx | |
CH-10-Q3 | Which one of the following reactions does not involve either
oxidation or reduction? | [] | 3 | null | [IMAGE] In this reaction oxidation and reduction are not involved because
there is no change in oxidation number. | [
"images/image10.png",
"images/image11.png"
] | Chemistry | Physical Chemistry | Redox Reaction | Moderate | single_correct | true | JEE Main | CH-10 Chemistry Paper-1 30 Oct New Jee main.docx | ||||
CH-06-Q16 | [IMAGE] Final product is | [
"images/image27.png"
] | 1 | null | [
"images/image32.png"
] | Chemistry | Organic Chemistry | Hydrocarbons | Easy | single_correct | true | JEE Main | CH-06 Chemistry Paper 14 October.docx | |||||
CH-15-Q17 | The reaction A(s) → 2 B(g) + C(g) is first order. The pressure
after 20 min and after very long time are 150 mm Hg and 225 mm Hg. The
value of rate constant and pressure after 40 min are | [] | 0.05 In 1.5 min-1,200 mm | 0.5 In 2 min-1,300 mm | 0.05 In 3 min-1, 300 mm | 0.05 In 3 min-1, 200 mm | 4 | null | A(s) → 2 B(g) + C(g)
$K = \frac{1}{t}{In}\left( \frac{P_{\infty} - P_{0}}{P_{\infty} - P_{t}} \right){\ \ \ \ \ \ \ \ P}_{0} = 0\ \ \ {\ \ \ \ \ \ \ \ \ \ \ P}_{t} = 150\ {\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ P}_{\infty} = 225$
$\frac{1}{20}In\lbrack\frac{225}{225 - 150}\rbrack \Rightarrow \frac{1}{20}In(\fr... | [] | Chemistry | Chemical Kinetics | Experimental Method to calculate order and rate law of | Tough | single_correct | false | JEE Main | CH-15 Chemistry Paper 11 Nov..docx |
CH-02-Q7 | [IMAGE] X is | [
"images/image44.png"
] | NO | null | null | [
"images/image48.png"
] | Chemistry | single_correct | true | JEE Main | CH-02 Chemistry paper 2.docx | |||||||
CH-14-Q1 | The passage of current liberates [IMAGE] at cathode
and [IMAGE] at anode. The solution is | [
"images/image1.png",
"images/image2.png"
] | Copper chloride in water | NaCl in water | Water | 2 | null | Since discharge potential of water is greater than that of
sodium so water is reduced at
cathode instead of [IMAGE] Cathode: [IMAGE] Anode: [IMAGE] | [
"images/image4.png",
"images/image5.png",
"images/image6.png"
] | Chemistry | Physical Chemistry | Electrochemistry | Moderate | single_correct | true | JEE Main | CH-14 Chemistry Paper 7 Nov..docx | |
CH-02-Q8 | When a metal sulphate is heated in dry test tube, the colour changes
from blue to white. Then metal sulphate may be | [] | None of these | null | null | [IMAGE] (due to no crystal field splitting)
Blue White | [
"images/image52.png"
] | Chemistry | single_correct | true | JEE Main | CH-02 Chemistry paper 2.docx | ||||||
CH-28-Q25 | Which one of the following statements regarding helium is
incorrect? | [] | It is used to fill gas balloons instead of hydrogen because it is
lighter and non-inflammable | It is used as a cryogenic agent for carrying out experiments at
low temperatures | It is used to produce and sustain powerful superconducting magnets | It is used in gas-cooled nuclear reactors | 1 | null | RNA and DNA has ribose and deoxyribose sugars, which differs in
absence of hydroxy group at $2^{nd\ }$ carbon | [] | Chemistry | Physical Chemistry | Ideal Gases | Moderate | single_correct | false | JEE Main | CH-28 Chemistry Paper FST 16 Jan.docx |
CH-02-Q14 | [IMAGE] Reagent for the above reaction will be | [
"images/image89.png"
] | Hot acidic [IMAGE] | dil | null | null | Mild oxidizing agent like PCC can oxidize only alcohols into
carbonyl compounds. | [] | Chemistry | single_correct | true | JEE Main | CH-02 Chemistry paper 2.docx | |||||
CH-12-Q7 | Ferrous oxide has a cubic structure and each edge of the unit
cell is 5.0 Assuming density of the oxide as 4.0 g - cm^-3, then
the number of Fe^2+ and O^2- ions present in each unit cell will be | [] | Four Fe^2+ and four O^2 | Two Fe^2+ and four O^2 | Four Fe^2+ and two O^2 | Three Fe^2+ and three O^2 | 1 | null | Let the units of ferrous oxide in a unit cell = n, molecular
weight of ferrous oxide
$\left( F_{e}O \right) = 56 + 16 = 72gmol^{- 1}$
weight of n units $= \frac{72 \times n}{6.023 \times 10^{23}}$
Volume of one unit = (length of corner )^3
$= (5A)^{3} = 125 \times 10^{- 24}{cm}^{3}$
$\ Density\ = \frac{\ wt.\ of\ cel... | [] | Chemistry | Physical Chemistry | Tough | single_correct | false | JEE Main | CH-12 Chemistry Paper 2 Nov..docx | |
CH-21-Q10 | The carbon-based reduction method is NOT used for the
extraction of | [] | tin from SnO2 | iron from Fe2O3 | aluminium from Al2O3 | magnesium from MgCO3, CaCO3
èkkrqvks ds fu"d"kZ.k cZu vkèkkfjr vip;d fofèk | 3 | null | SnO2 and Fe2O3 are reduced by C reduction method.
Al2O3 andMgCO | [] | Chemistry | Inorganic Chemistry | Metallurgy | Easy | single_correct | false | JEE Main | CH-21 Chemistry Paper 19 Dec. Eng Hindi.docx |
CH-26-Q33 | The total number of electrons present in 4th shell of Astatatine
(85At) are:,LVsjhu (_85At) ds 4^th dks'k es mifLFkr bysDVªkWu | [] | null | 32 | Electronic configuration of
[IMAGE] _85At | [
"images/image51.png",
"images/image51.png"
] | Chemistry | Inorganic Chemistry | P-block Halogen | Moderate | numerical | true | JEE Main | CH-26 Chemistry Paper 1 15 Jan.docx | ||||
CH-24-Q2 | The figure show the change in concentration of species A and B as
a functional of time. The equilibrium constant K_C for the reaction
$A(g) \rightleftharpoons 2B(g)$ is | [
"images/image1.png"
] | K_c > 1 | K < 1 | K = 1 | Data insufficie | 1 | null | $K_{c} = \frac{\lbrack B\rbrack^{2}}{\lbrack A\rbrack} = \frac{(0.4)^{2}}{0.1} = 1.6$ | [] | Chemistry | Physical Chemistry | Chemical Equilibrium | Moderate | single_correct | true | JEE Main | CH-24 Chemistry Paper 31 Dec..docx |
CH-25-Q18 | [IMAGE] ([X] gks ldrk | [
"images/image74.png",
"images/image75.png",
"images/image76.png"
] | None of these | 1 | null | [
"images/image80.png"
] | Chemistry | Organic Chemistry | Hydrocarbon | Moderate | single_correct | true | JEE Main | CH-25 Chemistry Paper 7 Jan.docx | ||||
CH-11-Q16 | Joule-Thomson expansion is | [] | Isobaric | Isenthalpic | Isothermal | None of these | 2 | null | Joule-Thomson expansion is isenthalpic. | [] | Chemistry | Physical Chemistry | Thermodynamics | Easy | single_correct | false | JEE Main | CH-11 Chemistry Paper-2 1Nov New Jee main.docx |
CH-13-Q21 | 0.6 g of a solute is dissolved in 0.1 litre of a solvent,
which develops an osmotic pressure of 1.23 atm at 27ºC. The
molecular mass of the substance is | [] | null | 120 | [
"images/image33.png"
] | Chemistry | Physical Chemistry | Moderate | numerical | true | JEE Main | CH-13 Chemistry Paper 4 Nov..docx | ||||||
CH-21-Q7 | Acetylene may be prepared by electrolysis of | [] | potassium oxalate | potassium acetate | potassium maleate | potassium succinate,lhVyhu | 3 | null | [
"images/image4.png",
"images/image5.png",
"images/image6.png",
"images/image4.png",
"images/image5.png",
"images/image6.png"
] | Chemistry | Hydrocarbon | Hydrocarbon | Moderate | single_correct | true | JEE Main | CH-21 Chemistry Paper 19 Dec. Eng Hindi.docx | |
CH-26-Q7 | The set with correct order of acidity is:
vEyh;rk | [] | HClO < HClO2 < HClO3 < HClO4 | HClO4 < HClO3 < HClO2 < HClO | HClO < HClO4 < HClO3 < HClO2 | HClO4 < HClO2 < HClO3 < HClO | 1 | null | As charge dispersion increases, the stability of conjugated
base increases and thus acidity increases.
vkos'k | [] | Chemistry | Inorganic Chemistry | P-block Halogen | Moderate | single_correct | false | JEE Main | CH-26 Chemistry Paper 1 15 Jan.docx |
CH-08-Q7 | For preparing a buffer solution of pH 6 by mixing sodium
acetate and acetic acid, the ratio of the concentration of salt and acid
should be (K_a = 10^-5). | [] | 1: 10 | 10: 1 | 100: 1 | 1: 100 | 2 | null | CaOCl_2 has two anions Cl^- and OCl^- along with
Ca^2+ ions. | [] | Chemistry | Physical Chemistry | Chemical and Ionic Equilibrium | Moderate | single_correct | false | JEE Main | CH-08 Chemistry Paper 23 October.docx |
CH-23-Q28 | What volume of 98 sulphuric acid (in ml) should be mixed with
water to obtain 200 mL of 15 solution of sulphuric acid by weight ?
Given density of H2O = 1.00 g cm^-3, sulphuric acid (98 ) = 1.88 g
cm-3 and sulphuric acid (15 ) = 1.12 g cm-3. | [] | null | 18 | It is a case of dilution, simplest way is to determine
normality of the 98 and 15 H2SO4.
(i) For 98 H2SO4: 100 g H2SO4 solution $= \frac{100}{1.88}{cm}^{3}$
solution has H2SO4 = 98 g
$N_{1}(98\%) = \frac{1000w_{1}}{E_{1}V} = \frac{1000 \times 98}{49 \times \frac{100}{1.88}} = 37.6N$
where w1 is the weight of solute of ... | [] | Chemistry | Physical Chemistry | Moderate | numerical | false | JEE Main | CH-23 Chemistry Paper 31 Dec. FST.docx | |||||
CH-02-Q4 | The passage of current liberates [IMAGE] at cathode
and [IMAGE] at anode. The solution is | [
"images/image26.png",
"images/image27.png"
] | Copper chloride in water | [IMAGE] in water | Mercuric chloride in water | [IMAGE] in water | null | null | [
"images/image30.png",
"images/image31.png",
"images/image32.png",
"images/image33.png"
] | Chemistry | single_correct | true | JEE Main | CH-02 Chemistry paper 2.docx | ||||
CH-12-Q24 | How many molecules are there in the unit cell of sodium
chloride? | [] | null | 4 | In NaCl (rock salt): Number of Na^+ ions = 12
(at edge centers) $x\frac{1}{4} + 1$ (at body centre) × 1 = | [] | Chemistry | Physical Chemistry | Easy | numerical | false | JEE Main | CH-12 Chemistry Paper 2 Nov..docx | |||||
CH-16-Q23 | How many of the following oxides are acidic? | [] | null | 5 | ${Mn}_{2}O_{7},{SO}_{2},{NO}_{2},{CrO}_{3},{SiO}_{2}$ = acidic | [] | Chemistry | Chemical Bonding | Oxy Acids | Moderate | numerical | false | JEE Main | CH-16 Chemistry Paper 25 Nov. Fisrt.docx | ||||
CH-27-Q17 | Which of the following is most soluble in water ? Assume no
reaction of cation/anion.
dksbZ vfHkfØ;k u ekusaA | [] | MnS (Ksp = 2.5 × 10-13 ) | ZnS (Ksp = 1.6 × 10-24) | Bi2S3 (Ksp =1.6 × 10-72) | Ag2S (Ksp = 10-51) | 1 | null | Find solubility for each separately by s2 = Ksp for MnS and
ZnS, 108s5 = Ksp for Bi2S3 and 4s3 = Ksp for Ag2S.
MnS rFkk ZnS ds fy, s2 = Ksp, Bi2S3 ds fy, 108s5 = Ksp rFkk Ag2S ds
fy, 4s3 = Ksp | [] | Chemistry | Physical Chemistry | Ionic Equilibrium | Moderate | single_correct | false | JEE Main | CH-27 Chemistry Paper 2 15 Jan.docx |
CH-02-Q2 | A following mechanism has been proposed for a reaction
The rate law expression for the reaction is | [
"images/image15.png",
"images/image16.png",
"images/image17.png"
] | null | null | Slowest step is rate determining.
Hence r = | [] | Chemistry | single_correct | true | JEE Main | CH-02 Chemistry paper 2.docx | |||||||
CH-06-Q7 | Among the following groupings which represents the collection of
isoelectronic species ? | [] | $NO,{CN}^{-},N_{2},O_{2}^{-}$ | ${NO}^{+},C_{2}^{2 -},O_{2} - CO$ | $N_{2},C_{2}^{2 -},CO,NO$ | $CO,{NO}^{+},{CN}^{-},C_{2}^{2 -}$ | 4 | null | Substance CO NO^+ CN^- $C_{2}^{2 -}$ N_2 NO $O_{1}^{-}$
No. of electrons 14 14 14 14 14 14 15 17 | [] | Chemistry | Inorganic Chemistry | Chemical Bonding | Moderate | single_correct | false | JEE Main | CH-06 Chemistry Paper 14 October.docx |
CH-07-Q22 | $1ml\text{ of }H_{2}O_{2}$solution gives$10ml\text{ of }O_{2}$
at NTP. It is | [] | null | 10 | 10 volume of $H_{2}O_{2}$ means 10 mlof $O_{2}$ is obtained from 1
ml of $H_{2}O_{2}$. | [] | Chemistry | Inorganic Chemistry | Hydrogen And Its Compound | Easy | numerical | false | JEE Main | CH-07 Chemistry Paper 17 October.docx | ||||
CH-21-Q25 | What amount of bromine will be required to convert 2 g of phenol
into 2, 4, 6 -tribromophenol
fQuksy dh 2 xzke dks esa cnyus | [] | null | 10.22 | [IMAGE] 94 grams of phenol reacts with 480 gms. of$Br_{2}$.
$2\ gm.\ of\ phenol\ - \frac{480}{94} \times 2 = 10.22gms$
Qsuksy dk 94 xzke $Br_{2}$ ds 480 xzke ds lkFk
Qsuksy dk 2 xzke & $\frac{480}{94} \times 2 = 10.22$ xzke | [
"images/image14.png"
] | Chemistry | Alcohol, Phenol and Ethers | Properties of alcohol, Phenol and Ethers | Moderate | numerical | true | JEE Main | CH-21 Chemistry Paper 19 Dec. Eng Hindi.docx | ||||
CH-04-Q24 | The total number of lone pairs in chlorate ion is | [] | null | 08 | [
"images/image55.png"
] | Chemistry | Physical Chemistry | Chemical Bonding | Easy | numerical | true | JEE Main | CH-04 Paper 02 Chemistry with Hindi 22-8-2020.docx | |||||
CH-11-Q21 | Molar heat of vaporization of a liquid is $6\ k{mol}^{- 1}$, If
the entropy change is $16{Jmol}^{- 1}K^{- 1}$, the boiling point of the
liquid is _______________ K | [] | null | 375 | $S = 16\ J\ {mole}^{- 1}K^{- 1}$
$T_{b}, = \frac{\Delta H_{vapour\ }}{\Delta S_{vapour\ }} = \frac{6 \times 1000}{16} = 375K$ | [] | Chemistry | Physical Chemistry | Thermodynamics | Moderate | numerical | false | JEE Main | CH-11 Chemistry Paper-2 1Nov New Jee main.docx | ||||
CH-27-Q38 | The solubility product of BaCrO4 is 2.4 × 10-10 M2. The maximum
concentration of Ba(NO3)2 possible without precipitation in a 6 × 10-4
M K2CrO4 solution is....... × 10-7:
BaCrO4 xq.kuQy 2.4 × 10-10 M2 gSA K2CrO4 | [] | null | 4 | Ksp (BaCrO4) = 2.4 × 10-10 M2
4-2] = 2.4 ×
10-10
$\Rightarrow$ × 6 × 10-4 = 2.4 × 10-10
= 4 × 10-7 M | [] | Chemistry | Physical Chemistry | Ionic Equilibrium | Moderate | numerical | false | JEE Main | CH-27 Chemistry Paper 2 15 Jan.docx | ||||
CH-23-Q6 | Which one of the following bases is not present in DNA ? | [] | Quinoline | Adenine | Cytosine | Thymine | 1 | null | Quinoline is an alkaloid, it is not present in DNA, DNA has
four nitrogenous bases in adenine, guanine, cytosine & thymine | [] | Chemistry | Organic Chemistry | Biomolecule & Polymers | Moderate | single_correct | false | JEE Main | CH-23 Chemistry Paper 31 Dec. FST.docx |
CH-27-Q12 | For the reaction, CO(g) + Cl2 (g) [IMAGE] COCl2
(g) then Kp / Kc is equal to:
CO(g) + Cl2 (g) [IMAGE] COCl2 (g) vfHkfØ fy,] Kp /
Kc fuEu | [
"images/image9.png",
"images/image9.png"
] | 1.0 | $\sqrt{RT}$ | RT | 1 | null | CO(g) + Cl2 (g) [IMAGE] COCl2 (g)
Δn = 1 - 2 = - 1; K_p = K_c (RT)^Δn $\therefore$
$\frac{K_{p}}{K_{c}} = (RT)^{- 1} = \frac{1}{RT}$ | [
"images/image9.png"
] | Chemistry | Physical Chemistry | Chemical Equilibrium | Moderate | single_correct | true | JEE Main | CH-27 Chemistry Paper 2 15 Jan.docx | |
CH-20-Q7 | Choose the chain terminating step
(a)$H_{2} \rightarrow H^{*} + H^{*}$
(b)$Br_{2} \rightarrow Br^{*} + Br^{*}$
(c)$Br^{*} + HBr \rightarrow H^{*} + Br_{2}$
(d)$H^{*} + Br_{2} \rightarrow HBr + Br^{*}$
(e) $Br^{*} + Br^{*} \rightarrow Br_{2}$ | [] | a | c | d | e | 4 | null | In chain termination step free radical present in reactant
side. | [] | Chemistry | Organic Chemistry | Organic Chemistry | Moderate | single_correct | false | JEE Main | CH-20 Chemistry Paper 12 Dec..docx |
CH-16-Q21 | 0.05 mole of LiAlH4 in ether solution was placed in a flask
containing 74g (1 mole) of t-butyl alcohol. The product LiAlHC12H27O3
weighed 12.7 g. If Li atoms are conserved, the percentage yield is: (Li
= 7, Al = 27, H = 1, C = 12, O = 16). | [] | null | 100 | $Li{AlH}_{4} + t - butyl\ alcohol\overset{Ether}{\longrightarrow}{LiAlHC}_{12}H_{27}O_{3}(M \cdot W. = 254)$
0.05 mole 12.7 gram
[IMAGE] Li atom remain conserved so
No. of mole of LiAlH4 = No. of mole of LiAlHC12H27O3
So No. of mole of LiAlHC12H27O3 = 0.05 yield [IMAGE] = 100 | [
"images/image40.png",
"images/image41.png"
] | Chemistry | Mole concept | Limiting reagent, % Excess, % Yield / Efficiency | Tough | numerical | true | JEE Main | CH-16 Chemistry Paper 25 Nov. Fisrt.docx | ||||
CH-16-Q3 | The general formula [IMAGE] could be for open chain | [
"images/image10.png"
] | diketones | carboxylic acids | diols | dialdehydes | 2 | null | Diketones:[IMAGE], Carboxylic acid
Diols:[IMAGE], Dialdehydes | [
"images/image11.png",
"images/image12.png",
"images/image13.png",
"images/image14.png"
] | Chemistry | Isomerism | Structural Isomerism | Easy | single_correct | true | JEE Main | CH-16 Chemistry Paper 25 Nov. Fisrt.docx |
CH-21-Q21 | In${CH}_{3}{CH}_{2}Br,\%$ of Br is ${CH}_{3}{CH}_{2}Br$ | [] | null | 75 | $\%\ of\ Br = \frac{\ Mass\ of\ Br}{\ Mass\ of\ organic\ compound\ } \times 100$
$= \frac{80}{109} \times 100 = 73.39\%$or approx. $75\%$ | [] | Chemistry | Halogen | Introduction of Halogen containing compounds | Easy | numerical | false | JEE Main | CH-21 Chemistry Paper 19 Dec. Eng Hindi.docx | ||||
CH-26-Q16 | When different types of salts have nearly same solubility
product constants Ksp, but less than one, the most soluble salt is that | [] | Which produces maximum number of ions per formula unit | Which produces minimum number of ions per formula unit | Which produces ions with maximum charge | Which produces ions with miniumum charge
tc fofHkUu çdkj ds yo.kksa xq.kuQy Ksp yxHkx cjkcj gaS]
ijUrq 1 ls de tks | 1 | null | For different salts such as AB, AB2, AB3,..........etc.
Ksp = s2, 4s3, 27s4............ respectively. If Ksp is same for
different salts, then s is more for the salt in which produces more
number of ions.
AB, AB2, AB3,..........bR;kfn tSls fofHkUu yo.kksa ds fy, Ksp =
s2, 4s3, 27s4............ gksrs gSaA;fn fHkUu yo.kk... | [] | Chemistry | Physical Chemistry | Ionic Equilibrium | Moderate | single_correct | false | JEE Main | CH-26 Chemistry Paper 1 15 Jan.docx |
CH-11-Q4 | In the following reaction
Which element is reduced? | [] | Cr | H | O | I | 1 | null | [
"images/image1.png",
"images/image2.png"
] | Chemistry | Physical Chemistry | Redox Reaction | Easy | single_correct | true | JEE Main | CH-11 Chemistry Paper-2 1Nov New Jee main.docx | |
CH-20-Q8 | Which of the following will not lose asymmetry on reduction with
LiAlH_4 | [] | 2 | null | On reduction of C=O group it will give COH. | [] | Chemistry | Organic Chemistry | Isomerism | Moderate | single_correct | false | JEE Main | CH-20 Chemistry Paper 12 Dec..docx | ||||
CH-17-Q23 | Consider the cell [IMAGE] The measured EMF of the
cell is 1.0 V. What is the value of x ? [IMAGE] | [
"images/image70.png",
"images/image71.png"
] | null | 2 | [
"images/image72.png",
"images/image73.png",
"images/image74.png",
"images/image75.png",
"images/image76.png",
"images/image77.png",
"images/image78.png"
] | Chemistry | Electrochemistry | Nernst equation & its Applications (including concentration | Tough | numerical | true | JEE Main | CH-17 Chemistry Paper 26 Nov. Second.docx | |||||
CH-22-Q24 | When pure water is saturated with both CaCO3 and CaC2O4, the
concentration of calcium ion in the solution under equilibrium is 8 ×
10-5 M. If the ratio of the solubility product of CaCO3 to that of
CaC2O4 is 3, what is the solubility product of CaCO3 in pure water ?
Report your answer after multiplying by 109 and round... | [] | null | 5 | ${CaCO}_{3} \rightleftharpoons {Ca}^{+ 2} + {CO}_{3}^{- 2}$
${CaC}_{2}O_{4} \ \ \rightleftharpoons \ {Ca}^{+ 2} + \ C_{2}O_{4}^{- 2}$
x x y y
(x+y) x (x+y) y
$\frac{K_{SP}\left( {CaCO}_{3} \right)}{K_{SP}\left( {CaC}_{2}O_{4} \right)} = \frac{x}{y} = 3 \Rightarrow x = 3y$
$(x + y) = 8 \times 10^{- 5}$
$(3y + y) = 8 \ti... | [] | Chemistry | Physical Chemistry | Ionic equilibrium | Moderate | numerical | false | JEE Main | CH-22 Chemistry Paper 19 Dec. Eng.docx | ||||
CH-09-Q21 | Oxidation number of Fe in [IMAGE] is | [
"images/image39.png"
] | null | 3 | [
"images/image40.png",
"images/image41.png",
"images/image42.png",
"images/image43.png"
] | Chemistry | Physical Chemistry | Redox Reaction | Easy | numerical | true | JEE Main | CH-09 Chemistry Paper 26 October.docx | |||||
CH-01-Q1 | The Vander Waals constant for the three gases A, B & C are as shown.
[IMAGE] Which of the following gases will behave most ideally around 300 K.? | [
"images/image1.png"
] | B | C | A | All the gases | null | null | [
"images/image2.png",
"images/image3.png",
"images/image4.png"
] | Chemistry | single_correct | true | JEE Main | CH-01 Chemistry Paper 1.docx | ||||
CH-22-Q19 | The volume of 0.1 N dibasic acid sufficient to neutralize 1 g of
a base that furnishes 0.04 mole of ${OH}^{-}$ in aqueous solution is | [] | 200 mL | 400 mL | 600 mL | 800 mL | 2 | null | The law of equivalence states that the equivalence of acid
isequal to the equivalence of base. $s = ut + \frac{1}{2}{at}^{2}$
Therefore, the volume required is calculated as,
$s = (0)t + \frac{1}{2}{at}^{2}$
$s = \frac{1}{2}{at}^{2}$
$t = \sqrt{\frac{2s}{a}}$ | [] | Chemistry | Physical Chemistry | Equivalent concept of Titration | Moderate | single_correct | false | JEE Main | CH-22 Chemistry Paper 19 Dec. Eng.docx |
CH-05-Q4 | What is the correct order of second ionisation energy for the
following ? | [] | F < N < C < O | N < C < F < O | C < N < F < O | O < C < F < N | 3 | null | After removal of one electron:
C^+: 1S^2 2S^2 2p^1; N^+: 1S^2 2S^2 2p^2
O^+: 1S^2 2S^2 2p^3; F^+: 1S^2 2S^2 2p^4 | [] | Chemistry | Inorganic Chemistry | Periodic Properties | Moderate | single_correct | false | JEE Main | CH-05 Chemistry Paper 10 October.docx |
CH-28-Q26 | In an atom, the total number of electrons having quantum numbers
n = 4, $\left| m_{\mathcal{l}} \right| = 1$ and $m_{s} = - 1/2$ is | [] | null | 4 | n = 4 $m_{\mathcal{l}} = 1$
Hence$\ \mathcal{l}$ can be = 3,2,1
i.e. Hf; 2 orbitals
Hd; 2 orbitals
Hp; 2 orbitals
Hence total of 6 orbitals, and we want $ms\ = \ - \frac{1}{2}$, that
is only one kind of spin. So, 6 electrons. | [] | Chemistry | Physical Chemistry | Atomic Structure | Moderate | numerical | false | JEE Main | CH-28 Chemistry Paper FST 16 Jan.docx | ||||
CH-25-Q14 | Write the major product of following reactions. | [
"images/image59.png",
"images/image60.png"
] | 1 | null | [IMAGE] (iii) $Ph - Ph + {CH}_{3} - {CH}_{3} + Ph - {CH}_{3}$ | [
"images/image61.png",
"images/image65.png"
] | Chemistry | Organic Chemistry | Hydrocarbon | Moderate | single_correct | true | JEE Main | CH-25 Chemistry Paper 7 Jan.docx | ||||
CH-23-Q27 | The number of isomers of dibromobiphenyl (Biphenyl - C6H5) is | [] | null | 12 | Overall 12 isomers. | [
"images/image54.png",
"images/image55.png",
"images/image56.png",
"images/image57.png",
"images/image58.png",
"images/image59.png",
"images/image60.png",
"images/image61.png",
"images/image62.png",
"images/image63.png",
"images/image64.png",
"images/image65.png"
] | Chemistry | Organic Chemistry | IUPAC & Structural Isomerism | Tough | numerical | true | JEE Main | CH-23 Chemistry Paper 31 Dec. FST.docx | ||||
CH-19-Q14 | Which of the following compounds will not undergo azo coupling
reaction with benzene diazoniumchloride?
A Aniline
B Phenol
C Anisole
D Nitrobenzene | [] | 3 | null | Diazonium cation is weak electrophile and hence it reacts with
electron rich compounds containing electron donatinggroups such as
$- OH, - {NH}_{2}\ and{\ OCH}_{3}$ groups and not with compounds
containing electron withdrawing groups such as$- {NH}_{2}$etc. | [] | Chemistry | Amines | Diazonium Salts | Moderate | single_correct | false | JEE Main | CH-19 Chemistry Paper 28 Nov. Fourth.docx | ||||
CH-06-Q5 | The number of molecules having two or more $p\pi –d\pi$ bond
amongs the following is:
$H_{3}{PO}_{4},P_{4}O_{10},{SO}_{3},{SO}_{2},{HClO}_{4},{HClO}_{3},{HClO}_{2},N_{2}O_{5}$ | [] | 4 | 5 | 6 | 7 | 1 | null | H3PO4, HClO2: Only $1\pi$-bond
N_2O_5: No d-orbital's | [] | Chemistry | Inorganic Chemistry | Chemical Bonding | Tough | single_correct | false | JEE Main | CH-06 Chemistry Paper 14 October.docx |
CH-24-Q13 | The dissociation constant of acetic acid at a given temperature
is 1.69 × 10^-5. The degree of dissociation of 0.01 M acetic acid in
the presence of 0.01 M HCl is | [] | 1.69 × 10^-7 | 1.69 × 10^-5 | 1.69 × 10^-3 | 2.9 × 10^-2 | 3 | null | ${CH}_{3}COOH(aq) \rightleftharpoons H^{+}(aq) + {CH}_{3}{COO}^{-}(aq)$
t = 0 0.01
t = eq 0.01 - x x x
[H^+] = x + 0.01[IMAGE] 0.01 M
$\therefore$
$K_{a} = \frac{\left\lbrack H^{+} \right\rbrack\left\lbrack CH_{3}COO^{-} \right\rbrack}{\left\lbrack CH_{3}COOH \right.\ }$
$\Rightarrow$ 1.69 ×10^-5 =
$\frac{0.01 \times \... | [
"images/image24.png"
] | Chemistry | Physical Chemistry | Ionic Equilibrium | Moderate | single_correct | true | JEE Main | CH-24 Chemistry Paper 31 Dec..docx |
CH-22-Q22 | Ammonia gas at 15 atm is introduced in a rigid vessel at 300 K.
At equilibrium the total pressure of the vessel is found to be 40.11 atm
at 300ºC. The degree of dissociation of NH3 will be | [] | null | 0.4 | $P_{1} = 15\ atm\;T_{1} = 300K$
Equilibrium temperature is 300ºC that is 573 K.
So first of all we have to calculate pressure of NH3 at 573 K.
$\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}} = \frac{15}{300} = \frac{P_{2}}{573}$
$P_{2} = 28.65atm\ at\ 300^{\circ}C$
${NH}_{3}(g) \rightleftharpoons \frac{1}{2}N_{2}(g) + \frac... | [] | Chemistry | Physical Chemistry | Chemical equilibrium | Moderate | numerical | false | JEE Main | CH-22 Chemistry Paper 19 Dec. Eng.docx | ||||
CH-10-Q5 | Which of the following is redox reaction? | [] | In atmosphere, [IMAGE] from [IMAGE] by lightning | Evaporation of [IMAGE] | Nitrogen oxides form nitrogen and oxygen by lightning | 4 | null | [IMAGE] Here O.N. of N increases from O in [IMAGE] to +2 in
[IMAGE] and that of decreased from O in
[IMAGE] to -2 in O, therefore, it is a redox reaction. | [
"images/image22.png",
"images/image23.png",
"images/image24.png",
"images/image25.png"
] | Chemistry | Physical Chemistry | Redox Reaction | Easy | single_correct | true | JEE Main | CH-10 Chemistry Paper-1 30 Oct New Jee main.docx | |
CH-05-Q5 | Select equation having exothermic step | [] | S^- (g) + e^- (g) [IMAGE] S^2- (g) | Ne (g) + e^- (g) [IMAGE] Ne^- (g) | N (g) + e^- (g) [IMAGE] N^- (g) | Al^+ (g)[IMAGE] Al (g) - e^- (g) | 4 | null | [IMAGE] H_e.g.= (+) ve because of electrostatic repulsion.
(2) Ne (g) + e^-(g)[IMAGE] Ne^-(g) H_e.g.= (+) vebecause of stable completely
filled electron configuration
(+) ve because of stable half filled electron configuration.
= (-) ve because of the addition of electron to cation. | [
"images/image3.png",
"images/image4.png",
"images/image3.png",
"images/image4.png",
"images/image3.png",
"images/image4.png",
"images/image3.png",
"images/image4.png"
] | Chemistry | Inorganic Chemistry | Periodic Properties | Moderate | single_correct | true | JEE Main | CH-05 Chemistry Paper 10 October.docx |
CH-06-Q17 | The energy required to melt 1g ice is 33J. The number of quanta
of radiation of frequency 4.67 ×10^13 sec^-1, that must be absorbed
to melt 10 g ice is | [] | 1.065 ×10^22 | 3.205 ×10^23 | 9.076 ×10^20 | None of these | 1 | null | ΔE = n.h.(ν)
33 x 10 J= n. $6.62 \times 10⁻³⁴\ J \cdot s\ $`<!- ->`4.67
×10^13 sec^-1
n = 1.065 ×10^22 | [] | Chemistry | Physical Chemistry | Atomic Structure | Easy | single_correct | false | JEE Main | CH-06 Chemistry Paper 14 October.docx |
CH-19-Q6 | Which of the following explode on heating? | [] | Azides | Sulphates | Chlorides | Phosphides | 1 | null | some experiments describe on calcium and barium azid and
tetrazene, which explode while they are solid. The explosion of the
molten azides is due to self heating of the liquid. Explosion is
facilitated by the presence of an inert gas above the decomposing liquid
self heating of the liquid azides is due to the retention... | [] | Chemistry | Amines | Physical Properties of Amines | Moderate | single_correct | false | JEE Main | CH-19 Chemistry Paper 28 Nov. Fourth.docx |
CH-17-Q7 | Which of the following will form only one oxime on reaction with
NH2OH solution? | [
"images/image15.png",
"images/image16.png",
"images/image17.png",
"images/image18.png"
] | Only A is correct | Only B & C correct | Only C & D correct | Only A & D correct | 2 | null | I [IMAGE] + | [
"images/image19.png",
"images/image20.png",
"images/image21.png",
"images/image22.png",
"images/image23.png",
"images/image20.png",
"images/image24.png",
"images/image25.png",
"images/image20.png",
"images/image26.png",
"images/image27.png",
"images/image20.png",
"images/image28.png",
"ima... | Chemistry | Isomerism | Geometrical isomerism | Moderate | single_correct | true | JEE Main | CH-17 Chemistry Paper 26 Nov. Second.docx |
CH-20-Q21 | A certain buffer solution contains equal concentration of
$X^{-}$and HX. The $K_{b}$ for $X^{-}$ is$10^{- 10}$. The pH of the
buffer is | [] | null | 4 | $X^{-} + H_{2}O = OH^{-} + HX$
$K_{b} = \frac{\lbrack OH^{-}\rbrack\lbrack HX\rbrack}{\lbrack X^{-}\rbrack}$
$HX = H^{+} + X^{-}$
$K_{a} = \frac{\lbrack H^{+}\rbrack\lbrack X^{-}\rbrack}{\lbrack HX\rbrack}$
$\therefore K_{a} \times K_{b} = \lbrack H^{+}\rbrack\lbrack OH^{-}\rbrack = K_{v} = 10^{- 14}$
Hence, $K_{a} = 1... | [] | Chemistry | Physical Chemistry | Ionic equilibrium | Moderate | numerical | false | JEE Main | CH-20 Chemistry Paper 12 Dec..docx | ||||
CH-02-Q20 | [IMAGE] Product is | [
"images/image123.png"
] | null | null | [This section contains | [
"images/image128.png"
] | Chemistry | single_correct | true | JEE Main | CH-02 Chemistry paper 2.docx | |||||||
CH-24-Q1 | Molar concentration of 96 g of O_2 contained in a 2 liter vessel
is | [] | 2 | null | Molar
conc. $= \frac{\ no.\ of\ moles\ of\ O_{2}}{\ volume\ (in\ litre\ )} = \frac{96}{32} \times \frac{1}{2}$
= 1.5M | [] | Chemistry | Physical Chemistry | Chemical Equilibrium | Easy | single_correct | false | JEE Main | CH-24 Chemistry Paper 31 Dec..docx | ||||
CH-18-Q25 | 25 mL of a solution of Fe2+ ions was titrated with a solution of
the oxidizing agent Cr2O72-. 50 mL of 0.01 M K2Cr2O7 solution was
required. What is the molarity of the Fe2+ solution? | [] | null | 0.12 | [IMAGE] No. of m.eq. of Fe+2 = No. of m.eq. of Cr2O7-2
$\lbrack M \times 25\rbrack \times 1 = \lbrack 0.01 \times 50\rbrack \times 6$
$M = \frac{0.01 \times 50 \times 6}{25}$
$M = 0.02 \times 6 = 0.12$ | [
"images/image41.png"
] | Chemistry | Equivalent Concept | Equivalent Concept for Redox reactions, KMnO4 / K2Cr2O7 v/s | Moderate | numerical | true | JEE Main | CH-18 Chemistry Paper 27 Nov. Third.docx | ||||
CH-26-Q34 | An amount of solid NH_4HS is placed in a flask already
containing ammonia gas at a certain temperature at 0.50 atm pressure.
Ammonium hydrogen sulphide decomposes to yield NH_3 and H_2S gases in
the flask. When the decomposition reaction reaches equilibrium, the
total pressure in the flask rises to 0.84 atm? The equili... | [] | null | 0.11 | NH4HS(s) [IMAGE] NH3(g) + H2S(g)
Initial presens 0 0.5 0
At equi. 0 0.5+x x
Total pressure = 0.5 + 2x = 0.84 $\therefore\ $ x = 0.17 atm
Kp = [IMAGE] = 0.11 atm | [
"images/image52.png",
"images/image53.png"
] | Chemistry | Physical Chemistry | Chemical Equilibrium | Tough | numerical | true | JEE Main | CH-26 Chemistry Paper 1 15 Jan.docx | ||||
CH-15-Q5 | The correct IUPAC name for the compound [Co(NH3)4CI(ONO)]Cl is | [] | Tetraamminechloridonitrito-N-cobalt (III) chloride | Chloridonitrito-O-tetraamminecobalt (II) chloride | Dichloridonitrito-O-tetraamminecobalt (III) | Tetraamminechloridonitrito-O-cobalt (III) chloride | 4 | null | Cation is named first followed by anion. In coordination sphere
the ligands are named alphabetically followed by name of metal ion and
then its oxidation state in Roman numeral.
In [Co(NH3)4Cl(ONO)]+Cl-, cobalt is in +3 oxidation state and the
complex is cationic. ONO ligands attach to metal ion through O atom;
so --O-... | [] | Chemistry | Coordination Compounds | Nomenclature of coordination compounds | Moderate | single_correct | false | JEE Main | CH-15 Chemistry Paper 11 Nov..docx |
CH-28-Q38 | How many of the following may produce salicylic acid on
hydrolysis under appropriate conditions ?
(i) [IMAGE] (ii) | [
"images/image19.png",
"images/image20.png",
"images/image21.png",
"images/image22.png",
"images/image23.png"
] | null | 4 | [IMAGE] on acid hydrolysis) | [
"images/image19.png",
"images/image24.png",
"images/image25.png",
"images/image26.png",
"images/image27.png",
"images/image28.png",
"images/image25.png",
"images/image29.png",
"images/image30.png"
] | Chemistry | Organic Chemistry | Reduction Oxidation | Tough | numerical | true | JEE Main | CH-28 Chemistry Paper FST 16 Jan.docx | ||||
CH-02-Q22 | The half life periods of a reaction at initial concentrations
[IMAGE] and [IMAGE] are 200 sec and 40
sec respectively. The order of reaction is | [
"images/image146.png",
"images/image147.png"
] | null | null | [
"images/image148.png",
"images/image149.png",
"images/image150.png"
] | Chemistry | single_correct | true | JEE Main | CH-02 Chemistry paper 2.docx | ||||||||
CH-28-Q37 | The most reactive chlorine towards $H_{2}O$ is | [
"images/image16.png"
] | null | 3 | [IMAGE] Reaction Intermediate -- Carbocation:
III will give most stable carbocation Þ stabilised by +m effect of
[IMAGE] I will give stable carbocation 3º carbocation so order of reaction = III
> I > II. | [
"images/image17.png",
"images/image18.png"
] | Chemistry | Organic Chemistry | Organic reaction | Moderate | numerical | true | JEE Main | CH-28 Chemistry Paper FST 16 Jan.docx | ||||
CH-26-Q8 | XeF4 and XeF6 are expected to be | [] | Oxidizing | Reducing | Unreactive | Strongly basic | 1 | null | XeF4 & XeF6 both are strong oxidising agents. These can oxidise
H2 to H+, Cl- to Cl2, I- to I2 and Ce(III) to Ce(IV).
XeF4 rFkk XeF6 nksuksa izcy vkWDlhdkjd
Cl^- dks Cl2 esa, I^- dks I2 esa rFkk Ce(III) dks Ce(IV) esa
vkWDlhd`r dj ldrs gSA
XeF4 + 4I^- [IMAGE] 2I2 + 4F^- + Xe. | [
"images/image1.png"
] | Chemistry | Inorganic Chemistry | P-block Halogen | Moderate | single_correct | true | JEE Main | CH-26 Chemistry Paper 1 15 Jan.docx |
CH-22-Q4 | The commercial name for calcium oxide is | [] | Milk of lime | Slaked lime | Limestone | Quick lime | 4 | null | Calcium oxide has the chemical formula $\begin{matrix}
E \propto a^{2} \\
a \propto E
\end{matrix}$ and is commercially clled quick lime. | [] | Chemistry | Inorganic Chemistry | S-block | Easy | single_correct | false | JEE Main | CH-22 Chemistry Paper 19 Dec. Eng.docx |
CH-18-Q10 | A bulb of 40 W is producing a light of wavelength 620 nm with
80 of efficiency then the number of photons emitted by the bulb in 20
seconds are (1eV = 1.6 × 10-19 J, hc = 12400 eV | [] | 2 × 1018 | 1018 | 1021 | 2 × 1021 | 4 | null | $Power = \frac{nhC}{\lambda \times t} \Rightarrow 40 \times \frac{80}{100} = \frac{n \times 6.62 \times 10^{- 34} \times 3 \times 10^{8}}{620 \times 10^{- 9} \times 20} \Rightarrow n = 2 \times 10^{21}$ | [] | Chemistry | Atomic Structure | Quantum theory of light & Photoelectric Effect | Moderate | single_correct | false | JEE Main | CH-18 Chemistry Paper 27 Nov. Third.docx |
CH-10-Q23 | [IMAGE] has how many isomeric forms that contain
a benzene ring | [
"images/image119.png"
] | null | 5 | [IMAGE] has 5 isomers | [
"images/image119.png"
] | Chemistry | Organic Chemistry | Organic Chemistry | Moderate | numerical | true | JEE Main | CH-10 Chemistry Paper-1 30 Oct New Jee main.docx | ||||
CH-02-Q11 | In adjoining diagram depicts the temperature behavior of the rate
constant, k for two reactions A and B. Which of the following is correct
at low temperature? | [
"images/image69.png"
] | k of reaction [IMAGE] of reaction B and
[IMAGE] of reaction [IMAGE] of reaction B | k of reaction [IMAGE] of reaction B and
[IMAGE] of reaction [IMAGE] of reaction
B | k of reaction [IMAGE] of reaction B and
[IMAGE] of reaction [IMAGE] of reaction B | k of reaction [IMAGE] of reaction B and
[IMAGE] of reaction [IMAGE] of reaction
B. | null | null | [
"images/image77.png",
"images/image78.png"
] | Chemistry | single_correct | true | JEE Main | CH-02 Chemistry paper 2.docx | ||||
CH-20-Q19 | Molecular shapes of $SF_{4},CF_{4}$ and $XeF_{4}$ are | [] | The same with 2,0 and 1 lone pairs of electrons respectively | The same, with 1,1 and 1 lone pairs of electrons respectively | Different, with 0,1 and 2 lone pairs of electrons respectively | Different, with 1,0 and 2 lone pairs of electrons respectively | 4 | null | SF_4 shape is see saw, CF_4 shape is tetrahedral, XeF_4
shape is square planar. | [] | Chemistry | Inorganic Chemistry | Chemical Bonding | Moderate | single_correct | false | JEE Main | CH-20 Chemistry Paper 12 Dec..docx |
CH-19-Q19 | The acid D obtained through the following sequence of reactions
is | [] | Succinic acid | Malonic acid | Maleic acid | Oxalic acid | 1 | null | [
"images/image20.png",
"images/image21.png"
] | Chemistry | Carbonyl Compound (Aldehyde and Ketone) | Carboxylic acid (Preparation Methods) | Tough | single_correct | true | JEE Main | CH-19 Chemistry Paper 28 Nov. Fourth.docx | |
CH-26-Q1 | In the depression of freezing point experiment, it is found that:
I. The vapour pressure of the solution is less than that of pure
solvent.
II. The vapour pressure of the solution is more than that of pure
solvent.
III. Only solute molecules solidify at the freezing point.
IV. Only solvent molecules solidify at the fre... | [] | I, II | II, III | I, IV | I, II, III | 3 | null | The freezing point of a solvent depresses as a non-volatile
solute is added to a solvent. According to Raoult's law, when a
non-volatile solute is added to a solvent the vapour pressure of the
solvent decreases. At freezing point it will be only the solvent
molecules which will solidify.
?kV A vuqlkj tc vok" tks rks ok... | [] | Chemistry | Physical Chemistry | Moderate | single_correct | false | JEE Main | CH-26 Chemistry Paper 1 15 Jan.docx | |
CH-11-Q8 | Which of the following will show aromatic behaviour? | [] | 2 | null | [IMAGE] (1) Molecule is planar.
(2) [IMAGE] Electrons are present. | [
"images/image11.png",
"images/image12.png"
] | Chemistry | Organic Chemistry | Organic Chemistry | Easy | single_correct | true | JEE Main | CH-11 Chemistry Paper-2 1Nov New Jee main.docx | ||||
CH-26-Q14 | For the following three reactions a, b and c, equilibrium
constants are given:
fuEu rhu vfHkfØ;kvksa a, b rFkk c ds fy, mu fLFkjkad fn, x, gSa:
(a) CO(g) + H2O(g)[IMAGE] CO2(g) + H2(g); K1
(b) CH4(g) + H2O(g)[IMAGE] CO(g) + 3H2(g); K2
(c) CH4(g) + 2H2O(g)[IMAGE] CO2(g) + 4H2(g); K3
Which of the following relations is c... | [
"images/image10.png",
"images/image11.png",
"images/image12.png"
] | K2 K3 = K1 | K3 = K1K2 | K3 K23 = K12 | $K\sqrt{K_{2}} = K_{3}$ | 2 | null | c = a + b | [] | Chemistry | Physical Chemistry | Chemical Equilibrium | Easy | single_correct | true | JEE Main | CH-26 Chemistry Paper 1 15 Jan.docx |
CH-27-Q36 | Determine solubility of PbI2 in a 0.1 M solution of Pb(NO3)2.is
( ___ × 10-4). (Ksp of PbI2 = 7.1 × 10-9)
Pb(NO3)2 ds 0.1 M PbI2 ( ___ × 10-4).(PbI2 | [] | null | 1.4 | x + 0.1 2x
Ksp = (x + 0.1)(2x)2 = 8 × 10-9
$\Rightarrow$ 4x2 = 8 × 10-8
$\Rightarrow$ x = 1.4 × 10-4 M | [
"images/image45.png",
"images/image46.png"
] | Chemistry | Physical Chemistry | Ionic Equilibrium | Moderate | numerical | true | JEE Main | CH-27 Chemistry Paper 2 15 Jan.docx | ||||
CH-23-Q29 | Molar conductivity of 0.04 solution at 298 k is 200 Scm2mole-1.
A conductivity cell which is filled with MgCl2 have area of
cross-section of electrode 4cm2 & distance between electrode is 8 cm. If
potential difference between electrode is 10V then find current flow in
miliampere. | [] | null | 40 | $\lambda_{m} = \frac{K \times 1000}{M}$
$200 = \frac{K \times 1000}{0.04}$
$K = \frac{200 \times 0.04}{1000} = 8 \times 10^{- 3}S{cm}^{- 1}$
$K = \left( \frac{\mathcal{l}}{9} \right) \times \frac{1}{R}$
$8 \times 10^{- 3} = \left\lbrack \frac{8}{4} \right\rbrack \times \frac{1}{R}$
$R = \frac{2}{8 \times 10^{- 3}} = \f... | [] | Chemistry | Physical Chemistry | Electrochemistry | Moderate | numerical | false | JEE Main | CH-23 Chemistry Paper 31 Dec. FST.docx |
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