question_id string | question string | question_images list | option_1 string | option_2 string | option_3 string | option_4 string | correct_option int64 | numerical_answer string | solution string | solution_images list | subject string | topic string | subtopic string | difficulty string | question_type string | has_image bool | exam string | source_paper string |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
CH-07-Q19 | Hydrogen molecule differs from chlorine molecule in the
following respect | [] | Hydrogen molecule is non-polar but chlorine molecule is polar | Hydrogen molecule is polar while chlorine molecule is non-polar | Hydrogen molecule can form intermolecular hydrogen bonds but
chlorine
molecule does not | Hydrogen molecule cannot participate in coordination bond
formation but chlorine molecule can | 4 | null | Chlorine has lone pair which it can donate to form co-ordinate bond
while hydrogen cannot. | [] | Chemistry | Inorganic Chemistry | Hydrogen And Its Compound | Easy | single_correct | false | JEE Main | CH-07 Chemistry Paper 17 October.docx |
CH-09-Q23 | Number of isomeric primary amines obtained from C_4H_11N are | [] | null | 4 | Four 1º amines are possible | [
"images/image48.png",
"images/image49.png",
"images/image50.png",
"images/image51.png"
] | Chemistry | Organic Chemistry | Organic compounds containing Nitrogen | Moderate | numerical | true | JEE Main | CH-09 Chemistry Paper 26 October.docx | ||||
CH-11-Q13 | At 27º C, one mole of an ideal gas is compressed isothermally
and reversibly from a pressure of 2 atm to 10 atm. The values of E
and q are (R = 2). | [] | 0, - 965.84 cal | - 965.84 cal,+ 965.84 cal | + 865.58 cal - 865.58 cal | - 865.58 cal,-865.58 cal | 1 | null | $W = 2.303\frac{P_{2}}{P_{1}}\ $
$= 2.303 \times 1 \times 2 \times 300\log\log\ \frac{10}{2}\ = 965.84$
At constant temperature, $E = 0$.
$E = q + w;q = - w = - 965.84\ $Cal | [] | Chemistry | Physical Chemistry | Thermodynamics | Moderate | single_correct | false | JEE Main | CH-11 Chemistry Paper-2 1Nov New Jee main.docx |
CH-22-Q14 | The correct statement about the synthesis of erythritol
(C(CH_2OH)_4) used in the preparation of PETN is | [] | The synthesis requires four aldol condensations between methanol
and ethanol. | The synthesis requires two aldol condensations and two Cannizzaro
reactions. | The synthesis requires three aldol condensations and one
Cannizzaro reaction. | Alpha hydrogens of ethanol and methanol are involved in this
reaction. | 3 | null | The synthesis of erythritol 1.67 ×10^5 J involves first three
aldol reactions between formaldehyde and acetaldehyde and then one
Cannizzaro reaction with formaldehyde. It can be expressed as, | [
"images/image17.png"
] | Chemistry | Organic Chemistry | Aldehyde Ketone & Carboxylic acid | Tough | single_correct | true | JEE Main | CH-22 Chemistry Paper 19 Dec. Eng.docx |
CH-27-Q3 | The Henry's law constant for the solubility of N2 gas in water
at 298 K is 1.0 × 105 atm. The mole fraction of N2 in air is 0.8. The
number of moles of N2 from air dissolved in 10 moles of water of 298 K
and 5 atm pressure is:
N2 xSl dh ty esa ? fy, gsujh fu;e fLFkjkad (Henry's law
constant) dk eku 298 K ij 1.0 × 105 a... | [] | 4 × 10-4 | 4.0 × 10-5 | 5.0 × 10-4 | 4.0 × 10-6 | 1 | null | $P_{N_{2}} = K_{H} \times X_{N_{2}}$
eksy
In 10 mole solubility is eksy | [] | Chemistry | Physical Chemistry | Moderate | single_correct | false | JEE Main | CH-27 Chemistry Paper 2 15 Jan.docx | |
CH-10-Q6 | Which is the best description of the behavior of bromine in the
reaction given below | [
"images/image26.png"
] | Oxidized only | Reduced only | Proton acceptor only | Both oxidized and reduced | 4 | null | [IMAGE] In the above reaction the oxidation number of [IMAGE] increases from zero [IMAGE] to +1 [IMAGE] and decrease from zero [IMAGE] to -1 (in
[IMAGE] ). Thus [IMAGE] is oxidized as well
as reduced & hence it is a redox reaction. | [
"images/image27.png",
"images/image28.png",
"images/image29.png",
"images/image30.png",
"images/image31.png",
"images/image32.png",
"images/image33.png"
] | Chemistry | Physical Chemistry | Redox Reaction | Moderate | single_correct | true | JEE Main | CH-10 Chemistry Paper-1 30 Oct New Jee main.docx |
CH-12-Q1 | If is the number of atoms in the unit cell that represents
the closest packing sequence ---A B C A B C---,the number
of tetrahedral voids in the unit cell is equal to | [] | Z | _2Z | 2 | null | Number of tetrahedral voids in the unit cell = 2 × number of
atoms = 2 Z | [] | Chemistry | Physical Chemistry | Easy | single_correct | false | JEE Main | CH-12 Chemistry Paper 2 Nov..docx | |||
CH-07-Q11 | Which of the following can possibly be used as analgesic without
causing addiction and any modification | [] | Morphine | N -acetyl paraamino phenol | Diazepam | Tetra hydro-cat-enol | 3 | null | "Diazepam" can be used as analgesic without addition and
modification. | [] | Chemistry | Organic Chemistry | Chemistry in everyday life | Tough | single_correct | false | JEE Main | CH-07 Chemistry Paper 17 October.docx |
CH-12-Q2 | Structure similar to zinc blende is found in | [] | AgCl | NaCl | CuCl | TlCl | 3 | null | Zinc blende (ZnS) has fcc structure and is an ionic crystal
having 4: 4 co-ordination number. | [] | Chemistry | Physical Chemistry | Moderate | single_correct | false | JEE Main | CH-12 Chemistry Paper 2 Nov..docx | |
CH-04-Q22 | 1 g sample of alkaline earth metal react completely with 4.08 g
H2SO_4 and yield an ionic product MSO_4. Then find out the atomic mass
of Alkaline earth metal (M)?,d 4.08 xzke ds lkFk iw.kZr 1 4.08 H2SO4
MSO4 M
? | [] | null | 24 | M + H2SO4 [IMAGE] MSO4 + H2
[IMAGE] This is atomic weight of M (M ) = | [
"images/image51.png",
"images/image52.png",
"images/image53.png",
"images/image54.png"
] | Chemistry | Physical Chemistry | Mole Concept | Moderate | numerical | true | JEE Main | CH-04 Paper 02 Chemistry with Hindi 22-8-2020.docx | ||||
CH-19-Q15 | Which can do glass etching? | [] | HIO4 | HF | HNO3 | SiF4 | 2 | null | SiO2 + 6HF → H2SiF6 + 2H2O | [] | Chemistry | P-block VA, VIA, VIIA elements | Hydracids | Easy | single_correct | false | JEE Main | CH-19 Chemistry Paper 28 Nov. Fourth.docx |
CH-14-Q12 | The correct order of magnetic moments (spin only values in B.M.)
among is | [] | 3 | null | [IMAGE] Number of unpaired electron =
[IMAGE] Number of unpaired electron =
[IMAGE] Number of unpaired electron =
Magnetic moment [IMAGE] Where, n = number of unpaired electron i.e., greater the number of
unpaired electron greater will be the paramagnetic character. | [
"images/image56.png",
"images/image57.png",
"images/image58.png",
"images/image59.png"
] | Chemistry | Inorganic Chemistry | D & F -Block Elements | Moderate | single_correct | true | JEE Main | CH-14 Chemistry Paper 7 Nov..docx | ||||
CH-27-Q34 | The number of P--O--P bonds in cyclic trimetaphosphoric acid
is:
pØh; VªkbZesVkQkWLQksfjd vEy | [] | null | 3 | [IMAGE] According to the structure of cyclic metaphosphoric acid, (HPO3)3,
there are three P - O - P bonds.
pØh; esVkQWkLQksfjd vEy, (HPO_3)_3 dh lajpuk ij;gk¡ rhu P
- O - P A | [
"images/image39.png"
] | Chemistry | Inorganic Chemistry | P-block nitrogen | Moderate | numerical | true | JEE Main | CH-27 Chemistry Paper 2 15 Jan.docx | ||||
CH-09-Q13 | Aniline on treatment with conc. HNO_3 + conc. H_2SO_4mixture
yields | [] | o - and p - nitro anilines | m - nitro anilines | A black tarry matter | No reaction | 3 | null | [IMAGE] Nitration of aniline without protecting the amino group is not possible
because HNO_3
is strong oxidizing agent which oxidizes aniline. | [
"images/image38.jpeg"
] | Chemistry | Organic Chemistry | Organic compounds containing Nitrogen | Easy | single_correct | true | JEE Main | CH-09 Chemistry Paper 26 October.docx |
CH-22-Q6 | Identify the incorrect statement | [] | S_2 is paramagnetic like oxygen. | Rhombic and monoclinic sulphur have S_8 molecules. | S_8 ring has a crown shape. | The S-S-S bond angles in the S_8 and S_6 rings are the same. | 4 | null | The statement "The $v = \frac{\omega}{k}$ bond angle in
the $= \frac{200\pi}{\left( \frac{5\pi}{4} \right)}$ and = 160 m/s
$\Phi_{1} = \Phi_{2} = \Phi_{3} = \Phi_{4}\ $rings are the same." is
incorrect.
Both $C = \frac{\varepsilon_{0}A}{3}$ and
$C = \frac{\left( \frac{k\varepsilon_{0}A}{3} \right)\left( \frac{\varepsi... | [
"images/image1.png"
] | Chemistry | Inorganic Chemistry | P-block | Easy / Moderate/ Tough | single_correct | true | JEE Main | CH-22 Chemistry Paper 19 Dec. Eng.docx |
CH-15-Q19 | Among the following ions, which one has the highest
paramagnetism? | [] | 2 | null | (1) Cr3+, 3d3
[IMAGE] n = 3
(2) Fe2+, 3d5 [IMAGE] n = | [
"images/image24.png",
"images/image25.png"
] | Chemistry | Coordination Compounds | Applications of crystal field theory | Tough | single_correct | true | JEE Main | CH-15 Chemistry Paper 11 Nov..docx | ||||
CH-26-Q31 | The number of hydrogen atom (s) attached to phosphorus atom in
hypophosphorus acid is:
gkbiks QkLQksjl vEy esa QkWLQksjl ijek.kq ls tqM+s gq, gkbMªkstu ijek.kq
¼Bksl½ | [] | null | 2 | Hypophosphorus acid gkbiksQkWLQksjl vEy
[IMAGE] Number of hydrogen atom(s) attached to phosphorus atom is 2 which are
called as reducing hydrogen.
QkWLQksjl ijek.kq ls tqM+s gkbMªkstu ijek.kq nks gSa] tks
fd vipf;r gkbMªkstu dgykrs gSaA | [
"images/image44.png"
] | Chemistry | Inorganic Chemistry | P-block nitrogen | Moderate | numerical | true | JEE Main | CH-26 Chemistry Paper 1 15 Jan.docx | ||||
CH-14-Q8 | Which element gives maximum balanced oxide? | [] | V | Cr | Mn | Fe | 3 | null | Among the transition metals Mn forms maximum no. of oxides. | [
"images/image34.png"
] | Chemistry | Inorganic Chemistry | D & F -Block Elements | Easy | single_correct | true | JEE Main | CH-14 Chemistry Paper 7 Nov..docx |
CH-02-Q21 | Given that (in[IMAGE] ) at T = 298 K:
[IMAGE] are 228.8,120.3 & 129.8 respectively. Specific
conductance for 0.2 N [IMAGE] solution is
[IMAGE] then value of pH of the given solution of
[IMAGE] will be nearly: (Take log 2 = 0.3) | [
"images/image129.png",
"images/image130.png",
"images/image131.png",
"images/image132.png",
"images/image133.png",
"images/image134.png",
"images/image133.png"
] | null | null | [
"images/image135.png",
"images/image136.png",
"images/image137.png",
"images/image138.png",
"images/image139.png",
"images/image140.png",
"images/image141.png",
"images/image142.png",
"images/image143.png",
"images/image144.png",
"images/image145.png"
] | Chemistry | single_correct | true | JEE Main | CH-02 Chemistry paper 2.docx | ||||||||
CH-23-Q7 | Complete the following reactions | [] | 1 | null | [
"images/image20.png",
"images/image24.png",
"images/image25.png",
"images/image22.png",
"images/image26.png",
"images/image25.png"
] | Chemistry | Organic Chemistry | Aromatic compounds Final | Moderate | single_correct | true | JEE Main | CH-23 Chemistry Paper 31 Dec. FST.docx | |||||
CH-15-Q12 | Bleeding is stopped by the application of ferric chloride. This
is because | [] | the blood starts flowing in opposite direction | the blood reacts and forms a solid, which seals the blood vessel | the blood is coagulated and thus the blood vessel is sealed | the ferric chloride seals the blood vessel. | 3 | null | Blood is a colloidal solution containing a -ve charge
colloidal particle (Albuminoid), bleeding can be stopped by use of alum
or FeCl3 solution. The addition of Al3+ or Fe3+ causes coagulation of
blood, so bleeding stops. | [] | Chemistry | Surface Chemistry | Purification and Preparation of Colloid | Moderate | single_correct | false | JEE Main | CH-15 Chemistry Paper 11 Nov..docx |
CH-23-Q26 | Calculate the energy required to excite one litre Hydrogen gas
at 1 atm and 298 K to first excited state of atomic hydrogen. The energy
for the dissociation of H-H bond is 436 kJ mol-1. | [] | null | 98 | Determination of number of moles of hydrogen gas
$n = \frac{PV}{RT} = \frac{1 \times 1}{0.082 \times 298} = 0.0409$
The concerned reaction is
$H_{2} \longrightarrow 2H;\Delta H = kJ{mol}^{- 1}$
Energy required to bring 0.0409 moles of hydrogen gas to atomic state
$= 436 \times 0.0409 = 17.83kJ$
1 mole of H2 gas has 6.0... | [] | Chemistry | Physical Chemistry | Atomic Structure | Tough | numerical | false | JEE Main | CH-23 Chemistry Paper 31 Dec. FST.docx | ||||
CH-17-Q2 | The correct IUPAC name of following compound is | [
"images/image3.png"
] | 4-Aminomethyl-3-hydroxycyclohex-5-ene-1-carboxylic acid | 2-Aminomethyl-5-carboxycyclohex-3-en-1-ol | 4-Aminomethyl-5-hydroxycyclohex-2-ene-1-carboxylic acid | 3 -Hydroxy-4-aminomethylcyclohex-5-en-1-oic acid | 3 | null | acid | [
"images/image4.png"
] | Chemistry | IUPAC Nomenclature | IUPAC -Nomenclature of chain terminating Functional groups | Easy | single_correct | true | JEE Main | CH-17 Chemistry Paper 26 Nov. Second.docx |
CH-27-Q14 | If 10-4 dm3 of water is introduced into a 1.0 dm3 flask at 300
K, how many moles of water are in the vapour phase when equilibrium is
established ?
(Given: Vapour pressure of H2O at 300 K is 3170 Pa; R= 8.314 J K-1
mol-1)
rks lkE;
LFkkfir gks tkus ij ty ds fdrus eksy ok"i izkoLFkk esa gksaxs
( 300 K ij H2O dk ok"i nk... | [] | 5.56 × 10-3 mol | 1.53 × 10-2 mol | 4.46 × 10-2 mol | 1.27 × 10-3 mol | 4 | null | PV = nRT
V = 1 dm3 = 10-3 m3
P = 3170 Pa
R = 8.314 J K-1 mol-1
T = 300 K
3170 × 10-3 = n × 8.314 × 300
n = $\frac{3170 \times 10^{- 3}}{8.314 \times 300}$ =1.27 × 10^-3 mol | [] | Chemistry | Physical Chemistry | Chemical Equilibrium | Moderate | single_correct | false | JEE Main | CH-27 Chemistry Paper 2 15 Jan.docx |
CH-13-Q25 | Benzene and toluene form nearly ideal solutions. At 20ºC, the
vapour pressure of benzene is 75 torr and that of toluene is 22
torr. The parial vapour pressure of benzene of 20ºC for a solution
containing 78g of benzene and 46g of toluene in torr is. | [] | null | 50 | [IMAGE] P_B = 50 torr | [
"images/image43.png",
"images/image44.png",
"images/image45.png"
] | Chemistry | Physical Chemistry | Easy | numerical | true | JEE Main | CH-13 Chemistry Paper 4 Nov..docx | |||||
CH-15-Q22 | Compound A and B react to form C and D in a reaction that was
found to be second-order over all and second-order in A. The rate
constant -at 30ºC is 0.622 L mol-1 min-1. What is the half-life of A
when 4.10 × 10-2 M of A is mixed with excess B? | [] | null | 39.2 | A + B → C + D
Second order with respect to A
then,
$t_{1/2} = \frac{1}{{Ka}_{0}} \Rightarrow t_{12} = \frac{1}{0.622 \times 4.10 \times 10^{- 2}} = 39.2min$ | [] | Chemistry | Chemical Kinetics | Integrated Rate law : Second Order & Pseudo first order | Moderate | numerical | false | JEE Main | CH-15 Chemistry Paper 11 Nov..docx | ||||
CH-11-Q11 | Which is the decreasing order of stability? | [
"images/image19.png",
"images/image20.png",
"images/image21.png"
] | (i) < (ii) < (iii) | (i) > (ii) > (iii) | (iii) > (ii) > (i) | (i) > (iii) > (i) | 3 | null | [
"images/image22.png"
] | Chemistry | Organic Chemistry | Organic Chemistry | Moderate | single_correct | true | JEE Main | CH-11 Chemistry Paper-2 1Nov New Jee main.docx | |
CH-24-Q30 | Calculate the change in pH of 0.1 M Na_2HA solution after
diluting it to ten times the original volume. (Given that for H_3A:
[IMAGE] = 10^-4, [IMAGE] = 10^-7,
[IMAGE] = 10^-11) | [
"images/image37.png",
"images/image38.png",
"images/image39.png"
] | null | 0 | pH of solutions of amphiprotic species is independent of
concentration of solution. | [] | Chemistry | Physical Chemistry | Ionic Equilibrium | Moderate | numerical | true | JEE Main | CH-24 Chemistry Paper 31 Dec..docx | ||||
CH-06-Q25 | Consider all the atoms of C_2H_2 are on Z-axis. Find total no.
of orbitals which involve in overlapping along Z-axis | [] | null | 6 | Total no. of orbitals = [4-sp orbitals from 2 carbon atoms +
two 1s-orbitals from 2 hydrogen atoms] = 6 | [] | Chemistry | Inorganic Chemistry | Chemical Bonding | Tough | numerical | false | JEE Main | CH-06 Chemistry Paper 14 October.docx | ||||
CH-14-Q22 | The specific conductance of a solution is [IMAGE] and conductivity is [IMAGE] The cell constant would be | [
"images/image90.png",
"images/image91.png"
] | null | null | [
"images/image93.png"
] | Chemistry | Physical Chemistry | Electrochemistry | Easy | single_correct | true | JEE Main | CH-14 Chemistry Paper 7 Nov..docx | |||||
CH-26-Q39 | The minimum volume of the water needed to dissolve 1 g of BaSO4
(Ksp = 10-10) is about: Assume no reaction of cation/anion.
[Mol. mass (BaSO4) = 233 u]
1g BaSO4 (Ksp =10-10) dks ?kksyus ds fy, ty
yxHkx........ | [] | null | 430 | Solubility of BaSO_4 =
$\sqrt{K_{5p}} = \sqrt{10^{- 10}} = 1 \times 10^{- 5}M$
$\therefore$ wt. of BaSO4 = 1 × 10-5 × 233 = 233 × 10-5 g/litre.
$\therefore$ Volume of water needed to dissolve 1 g BaSO4 is equal to
$\frac{1}{233 \times 10^{- 5}} \approx$ 430 litres
BaSO_4 =
$\sqrt{K_{5p}} = \sqrt{10^{- 10}} = 1 \times 1... | [] | Chemistry | Physical Chemistry | Ionic Equilibrium | Tough | numerical | false | JEE Main | CH-26 Chemistry Paper 1 15 Jan.docx | ||||
CH-28-Q40 | The equilibrium constant at 298 K for a reaction
$A + B \rightleftharpoons C + D$ is 100. If the initial concentration of
all the four species were 1 M each, then equilibrium concentration of D
(in mol L-1) will be | [] | null | 1.818 | $A\ \ \ \ \ \ \ \ \ + \ \ \ \ \ \ \ \ \ B\ \ \ \ \ \ \ \ \ \rightleftharpoons \ \ \ \ \ \ \ \ \ \ C\ \ \ \ \ \ \ \ \ + \ \ \ \ \ \ \ \ D$
t = 0 1 1 1 1
$t_{eq}$ $1 - x\ $ $1 - x$ $1 + x$ $1 + x$
$\Rightarrow \frac{(1 + x)^{2}}{(1 - x)^{2}} = 100 \Rightarrow \frac{1 + x}{1 - x} = 10$
$\Rightarrow 1 + x = 10 - 10x \Right... | [] | Chemistry | Physical Chemistry | Chemical equilibrium | Moderate | numerical | false | JEE Main | CH-28 Chemistry Paper FST 16 Jan.docx | ||||
CH-21-Q11 | Given is the electronic configuration of element X:
dlh rRo X dk bysDVªkWfud K L M N
2 8 11 2
The number of electrons present with = 2 in an atom of element X is:
rRo X ds,d ijek.kq esa = 2 okys bysDVªkWuks | [] | 3 | 6 | 5 | 4 | 1 | null | $X_{23}:1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{3}4s^{2}$
No. of electron with$\mathcal{l =}2$are$3\left( 3d^{3} \right)$
$\mathcal{l =}2$ | [] | Chemistry | Atomic Structure | Quantum numbers & Electronic configuration | Moderate | single_correct | false | JEE Main | CH-21 Chemistry Paper 19 Dec. Eng Hindi.docx |
CH-26-Q20 | Arrange the following alkanols A, B and C in order of their
reactivity towards acid catalysed dehydration:-,flM mRizsfjr futZyhdj.k | [
"images/image23.png",
"images/image24.png",
"images/image25.png"
] | A > B > C | B > A > C | B > C > A | C > B > A | 3 | null | n catalytic dehydration carbocation is formed as an
intermediate.
n catalytic fMgkbMªs"ku dkcksZds"ku,d:i esa curk gSA
Rate of dehydration of alcohol $\propto$ Stability of carbocation
"kjkc | [
"images/image26.png",
"images/image27.png",
"images/image28.png"
] | Chemistry | Organic Chemistry | Hydrocarbon | Moderate | single_correct | true | JEE Main | CH-26 Chemistry Paper 1 15 Jan.docx |
CH-12-Q19 | When phenol reacts with CHCl_3 and KOH, the product
obtained would be | [] | Salicylaldehyde | p-hydroxyl benzaldehyde | Both (a) and (b) | Chloretone | 3 | null | + 2CHCl_3 + 6KOH → | [
"images/image7.png"
] | Chemistry | Organic Chemistry | HALOALKANES & HALOARENES | Easy | single_correct | true | JEE Main | CH-12 Chemistry Paper 2 Nov..docx |
CH-16-Q22 | How many of the following have greaterZ_eff than Silicon atom:
Na, Mg, Al, P, Cl, S, N, O, C, F | [] | null | 7 | N, O, F, P, C, S, Cl | [] | Chemistry | Periodic table | Shielding Effect & Z_eff | Easy | numerical | false | JEE Main | CH-16 Chemistry Paper 25 Nov. Fisrt.docx | ||||
CH-28-Q5 | The correct order of electronegativity on Pauling scale is | [] | $F > Cl > O > S$ | $Li > Na > K > Rb > Cs$ | $Be < B < N < C$ | Both (A) and (B) | 2 | null | Electronegativity of elements generally increases across the
period (less increase) and decreases down the group (more decrease). | [] | Chemistry | Inorganic Chemistry | Periodic table | Easy | single_correct | false | JEE Main | CH-28 Chemistry Paper FST 16 Jan.docx |
CH-20-Q13 | A gas decolourised by ${KMnO}_{4}$ solution but givesno
precipitate with ammoniacal cuprous chloride is | [] | Ethane | Methane | Ethene | Acetylene | 3 | null | [
"images/image13.png"
] | Chemistry | Organic Chemistry | ALKENE | Moderate | single_correct | true | JEE Main | CH-20 Chemistry Paper 12 Dec..docx | |
CH-15-Q1 | If rate constant is numerically the same for the three reactions
of first, second and third order respectively. Assume all the reactions
of the kind A→ products. Which of the following is correct | [] | if = 1 then r_1= r_2 = r_3 | if < 1 thenr_1> r_2 > r_3 | if > 1 then r_3 < r_2 < r_1 | All | 4 | null | Rate law for: I^storder II^ndorder III^rdorder
Rate = R_3 =
Thanwe can say < 1 then r_1> r_2 >
r_3
> 1 then r_3 < r_2 < r_1 | [] | Chemistry | Chemical Kinetics | Rate of chemical reaction and Dependence of Rate : Basic | Tough | single_correct | false | JEE Main | CH-15 Chemistry Paper 11 Nov..docx |
CH-14-Q18 | Which one of the following reactions is a method for the
conversion of a ketone into a hydrocarbon? | [] | Aldol condensation | Reimer-Thiemann reaction | Cannizzaro reaction | Wolf-Kirshner reduction | 4 | null | [
"images/image80.png"
] | Chemistry | Organic Chemistry | Aldehydes, Ketones & Carboxylic Acids | Easy | single_correct | true | JEE Main | CH-14 Chemistry Paper 7 Nov..docx | |
CH-01-Q17 | EAN of the central metal in the complexes K_2[Ni(CN)_4], | [] | 36, 35, 86 | 34, 35, 84 | 34, 35, 86 | 34, 36, 86 | null | null | [
"images/image47.png",
"images/image48.png",
"images/image49.png",
"images/image50.png",
"images/image51.png",
"images/image52.png",
"images/image53.png",
"images/image54.png",
"images/image55.png",
"images/image56.png"
] | Chemistry | single_correct | true | JEE Main | CH-01 Chemistry Paper 1.docx | ||||
CH-06-Q6 | The correct bond angle order of CCl_4, SiCl_4, GeCl_4 and
SnCl_4 is | [] | CCl_4> SiCl_4> GeCl_4> SnCl_4 | CCl_4< SiCl_4< GeCl_4< SnCl_4 | CCl_4 = SiCl_4 = GeCl_4 = SnCl_4 | None of these | 3 | null | CCl_4, SiCl_4, GeCl_4 and SnCl_4 all are sp^3 hybridised
symmetrical species there fore bond angle will be same. | [] | Chemistry | Inorganic Chemistry | Chemical Bonding | Easy | single_correct | false | JEE Main | CH-06 Chemistry Paper 14 October.docx |
CH-21-Q20 | An aqueous solution of colourless metal sulphate $M$, gives a
white precipitate with $NH4OH$. This was soluble in excess of $NH4OH$.
On passing $H2S$ gas through this solution a white precipitate is
formed. The metal $M$ in the salt is | [] | Ca | Ba | Al | Zn | 4 | null | ${Zn}^{2 +} + 2{NH}_{4}OH \longrightarrow Zn(OH)_{2} \downarrow (\ white\ ) + 2{{NH}_{4}}^{+}$
$Zn(OH)_{2} + 4{NH}_{4}OH \longrightarrow Zn\left( {NH}_{3} \right)_{4} + 6H_{2}O$ | [] | Chemistry | Salt Analysis | IVth Group | Moderate | single_correct | false | JEE Main | CH-21 Chemistry Paper 19 Dec. Eng Hindi.docx |
CH-24-Q5 | 2 mole each of SO_3, CO, SO_2 and CO_2 is taken in a one lit.
Vessel. If KC for
${SO}_{3}(g) + CO(g) \rightleftharpoons {SO}_{2}(g) + {CO}_{2}(g)$. Is | [] | Total no. of moles at equilibrium is less than 8 | n(SO_3) + n(CO_2) = 4 | [n(SO_2)/n(CO)] < 1 | Both (B) and (C). | 4 | null | ${SO}_{3}(g) + CO(g) \rightleftharpoons {SO}_{2}(g) + {CO}_{2}(g)$
$9 = \left( \frac{2 + x}{2 - x} \right)^{2}$
2 2 2 2
2+x 2+x 2-x 2-x x = 1
n_eq = 3 + 3 + 1 + 1 = 8 n(SO_3) + n(CO_2) = 4
$\frac{n\left( {SO}_{2} \right)}{n(CO)} = \frac{1}{2} < 1$
Therefore, (D) option is correct. | [] | Chemistry | Physical Chemistry | Chemical Equilibrium | Moderate | single_correct | false | JEE Main | CH-24 Chemistry Paper 31 Dec..docx |
CH-08-Q18 | Carbon suboxide C_3O_2 has | [] | Linear structure | Bent structure | Trigonal planar structure | Distorted tetrahedral structure | 1 | null | Carbon suboxide has linear structure with
C - C bond length equal to [IMAGE] and
C - O bond length equal to [IMAGE] | [
"images/image17.png",
"images/image18.png",
"images/image19.png"
] | Chemistry | Inorganic Chemistry | p block | Easy | single_correct | true | JEE Main | CH-08 Chemistry Paper 23 October.docx |
CH-09-Q10 | In the series of reaction
[IMAGE] X and Y are respectively | [
"images/image30.png"
] | 3 | null | [
"images/image35.png"
] | Chemistry | Organic Chemistry | Organic compounds containing Nitrogen | Moderate | single_correct | true | JEE Main | CH-09 Chemistry Paper 26 October.docx | |||||
CH-26-Q21 | Kolbe's electrolysis of sodium maleate at anode gives.
Kolbe | [] | Only acetylene dsoy acetylene | Only CO2 dsoy CO2 | Acetylene + CO2 | CO2 + H2 | 3 | null | [
"images/image29.png"
] | Chemistry | Organic Chemistry | Hydrocarbon | Moderate | single_correct | true | JEE Main | CH-26 Chemistry Paper 1 15 Jan.docx | |
CH-13-Q12 | Increasing order of solubility is | [] | CaCO_3, KHCO_3, NaHCO_3 | NaHCO_3, KHCO_3, CaCO_3 | KHCO_3, NaHCO_3, CaCO_3 | CaCO_3, NaHCO_3, KHCO_3 | 4 | null | CaCO_3, > NaHCO_3 > KHCO_3 is the increasing order
of solubility. | [] | Chemistry | Inorganic Chemistry | P-Block Element | Easy | single_correct | false | JEE Main | CH-13 Chemistry Paper 4 Nov..docx |
CH-09-Q6 | Which of the following substances acts as an oxidizing as well as
a reducing agent? | [] | Na_2O | SnCl_2 | Na_2O_2 | NaNO_2 | 4 | null | NaNO_2, (Sodium nitrite) act both as oxidizing as well as
reducing agent because in it N atom is in +3 oxidation state
(intermediate oxidation state)
Oxidizing property
[IMAGE] Reducing property | [
"images/image10.png",
"images/image11.png"
] | Chemistry | Physical Chemistry | Redox Reaction | Moderate | single_correct | true | JEE Main | CH-09 Chemistry Paper 26 October.docx |
CH-15-Q23 | 1 g of complex was passed through a cation
exchanger to produce HCl. The acid liberated was diluted to 1 liter.
What will be the molarity of acid solution [Molecular weight of complex
= 266.5] ? | [] | null | 0.0075 | 1 mole of complex will give two moles of Cl- ion, i.e. 2 mole
HCl
$\lbrack Cr{(H_{2}O)}_{5}Cl\rbrack{Cl}_{2} \cdot H_{2}O \rightleftharpoons {\lbrack Cr{(H_{2}O)}_{5}Cl\rbrack}^{+ 2} + 2{Cl}^{-}$
1g
mole of HCl$= \frac{2 \times 1}{266.5}$ (for HCl, V.f. = 1
[IMAGE] N = M)
$\therefore N = \frac{2/266.5}{1} = 0.0075$ | [
"images/image29.png"
] | Chemistry | Coordination Compounds | Werner's Theory | Tough | numerical | true | JEE Main | CH-15 Chemistry Paper 11 Nov..docx | ||||
CH-07-Q8 | Which of the following is not an antiseptic drug | [] | Iodoform | Dettol | Gammexane | Genatian violet | 3 | null | It is an insecticide. | [] | Chemistry | Organic Chemistry | Chemistry in everyday life | Moderate | single_correct | false | JEE Main | CH-07 Chemistry Paper 17 October.docx |
CH-18-Q19 | Amongst NH3, PH3, AsH3 and SbH3 the one with highest boiling
point is | [] | NH3 because of lower molecular weight | SbH3 because of higher molecular weight | PH3 because of H-bonding | AsH3 because of lower molecular weight | 2 | null | As molecular weight increases, magnitude of Van der Waal's
force of attraction increases.
Therefore, boiling point increases. Though NH3 has strong H-bonding
but boiling point of SbH3 is highest due to highest molecular weight.
Boiling point NH3 = 238.5 K and SbH3 = 254.6 K. | [] | Chemistry | Chemical Bonding | Applications of H-bond | Moderate | single_correct | false | JEE Main | CH-18 Chemistry Paper 27 Nov. Third.docx |
CH-21-Q18 | When a mixture containing phosphate is heated with conc. $HNO3$
and ammonium molybdate solution, a canary yellow precipitate is formed.
The formula of the yellow precipitate is:
tc QkWLQsV eksfyCMsV foy;u | [] | $(NH4)3PO4$ | $(NH4)3PO4.12MoO4$ | $(NH4)3PO4.12MoO3$ | $(NH4)3PO4.(NH4)2MO4$ | 3 | null | $NaHPO4\ + \ 12(NH4)2MoO4\ + \ 23HNO3\ \rightarrow$
$(NH4)3PO4.12MoO3\ + \ 2MaNO3\ + \ 21NH4NO3\ + \ 12H2O$
(Canary yellowdsusjhihyk) | [] | Chemistry | Salt Analysis | Precipitation Reactions | Moderate | single_correct | false | JEE Main | CH-21 Chemistry Paper 19 Dec. Eng Hindi.docx |
CH-25-Q5 | Which of the following undergoes decarboxylation most readily on
being heated ?
nsrk | [] | 4 | null | $\beta$-keto acid decarboxylate readily
$\beta$-dhVks vEy rsth | [] | Chemistry | Organic Chemistry | Hydrocarbon | Moderate | single_correct | false | JEE Main | CH-25 Chemistry Paper 7 Jan.docx | ||||
CH-26-Q22 | Hydration of [IMAGE] in presence of H2SO4 / HgSO4 gives
H2SO4 / HgSO4 | [
"images/image30.png",
"images/image30.png"
] | 1 | null | [
"images/image35.png"
] | Chemistry | Organic Chemistry | Hydrocarbon | Moderate | single_correct | true | JEE Main | CH-26 Chemistry Paper 1 15 Jan.docx | |||||
CH-12-Q8 | Main function of roasting is | [] | To remove volatile substances | Oxidation | Reduction | Slag formation | 1 | null | To remove volatile substance.
S_8 + 8O_2 → 8SO_2 ↑; P_4 + 5O_2 → P_4 O_10 ↑
4 As + 3O_2 → 2AS_2 O_3 ↑ | [] | Chemistry | Inorganic Chemistry | Metallurgy | Moderate | single_correct | false | JEE Main | CH-12 Chemistry Paper 2 Nov..docx |
CH-27-Q6 | Which of the following is the wrong statement ? | [] | ONCl and ONO^- are not isoelectronic. | O_3 molecule is bent | Ozone is violet-black in solid state | Ozone is diamagnetic gas. | null | null | (1) ONCl = 8 + 7 + 17 = 32e^-
ONO- = 8 + 7 + 8 + 1 = 24e^- (correct)
(2) [IMAGE] Central atom O is sp^2 hybridised with
1 lone pair, so bent shape (correct)
(3) Ozone is violet-black in solid state.
(4) O_3 has no unpaired electrons, so diamagnetic (correct)
(1) ONCl = 8 + 7 + 17 = 32e^-
ONO- = 8 + 7 + 8 + 1 = 24e^- (l... | [
"images/image4.png",
"images/image4.png"
] | Chemistry | Inorganic Chemistry | P-block nitrogen | Moderate | single_correct | true | JEE Main | CH-27 Chemistry Paper 2 15 Jan.docx |
CH-07-Q1 | For a real gas (van der temperature and
low pressure, the pressure may be ($V_{m}$⇒ molar volume) | [] | $a.b.V_{m}$ | $\frac{V_{m}}{a.b}$ | $\frac{a}{V_{m} \cdot b}$ | $\frac{b}{a \cdot V_{m}}$ | 3 | null | A real gas behaves ideally at Boyle's temperature in low pressure
range.
$Z = \frac{{PV}_{M}}{RT} = 1$
$P = \frac{RT}{V_{M}} = \frac{R\frac{a}{Rb}}{V_{M}} = \frac{a}{V_{M} \cdot b}$ | [] | Chemistry | Physical Chemistry | Gaseous state | Moderate | single_correct | false | JEE Main | CH-07 Chemistry Paper 17 October.docx |
CH-26-Q11 | What is the equilibrium constant expression for the reaction
P4 (s) + 5O2 (g)[IMAGE] P4 O10 (s) ? | [
"images/image6.png"
] | Kc = | Kc = | 2 | null | P4(g) + 5O2 (g)[IMAGE] P4O10(g) K_c =
$\frac{\left\lbrack P_{4}O_{10}(s) \right\rbrack}{\left\lbrack P_{4}(s) \right\rbrack\left\lbrack O_{2}(g) \right\rbrack^{5}}$ | [
"images/image6.png"
] | Chemistry | Physical Chemistry | Chemical Equilibrium | Moderate | single_correct | true | JEE Main | CH-26 Chemistry Paper 1 15 Jan.docx | ||
CH-09-Q19 | The disease that occurs due to eating high Hg content fish. | [] | Minimata disease | Beri-beri disorder | Kwashiorkar disese | Osteosclerosis | 1 | null | Explanation: Minamata disease is a neurological syndrome caused
by severe mercury poisoning. Fishes that present in Hg contaminated
water bodies efficiently store Hg in the form of highly toxic organic
compound methylmercury in their bodies. Minimata disease is caused by
eating these fishes. | [] | Chemistry | Inorganic Chemistry | Environmental Chemistry | Easy | single_correct | false | JEE Main | CH-09 Chemistry Paper 26 October.docx |
CH-16-Q15 | In the ionic equation
$2K^{+}B{rO}_{3}^{-} + 12H^{+} + 10e^{-} \longrightarrow {Br}_{2} + 6H_{2}O + 2K^{+}$,
the equivalent weight of KBrO3 will be | [] | 1 | null | ${BrO}_{2} \longrightarrow {Br}_{2}$
+5 0
$\therefore(V.f.){BrO}_{3}^{-} = 5$ | [] | Chemistry | Equivalent Concept | Equivalent weight, n-factor and Normality for Oxidant and | Moderate | single_correct | false | JEE Main | CH-16 Chemistry Paper 25 Nov. Fisrt.docx | ||||
CH-28-Q24 | The presence or absence of hydroxy group on which carbon atom of
sugar differentiates RNA and DNA. | [] | $1^{st}$ | $\ 2^{nd\ }$ | $3^{rd}$ | $4_{\ }^{th\ }$ | 2 | null | RNA and DNA has ribose and deoxyribose sugars, which differs in
absence of hydroxy group at $2^{nd\ }$ carbon | [] | Chemistry | Organic Chemistry | Biomolecule & Polymers | Moderate | single_correct | false | JEE Main | CH-28 Chemistry Paper FST 16 Jan.docx |
CH-17-Q25 | Two substances $A\ (t_{1/2} = 5min)$ and $B\ (t_{1/2} = 15min)$
are taken in such a way that initially The time after
which both the concentration will be equal is: (Assume that reaction is
first order) | [] | ^ = lbrackfrac - fracrbrack t$
$2ln2 = lbrackfrac - fracrbrack t$
$2 = leftlbrack frac - frac rightrbrack t$
$Rightarrow 2 = frac times t$
$t = 15minute.$ | null | 15 | $C_{t} = C_{0}e^{- Kt}$
According to question
$C_{A,t} = C_{B},t$
$\frac{C_{A}}{C_{B}} = \frac{e^{- K_{B}t}}{e^{- K_{A}t}} \Rightarrow \frac{C_{A}}{C_{B}} = e^{(K_{A} - K_{B})t}$
$4 = e^{\lbrack\frac{ln2}{5} - \frac{ln2}{15}\rbrack xt}$
$\Rightarrow ln4 = \lbrack\frac{ln2}{5} - \frac{ln2}{15}\rbrack t$
$ln(2)^{2} = \lb... | [] | Chemistry | Chemical Kinetics | Integrated rate law : Zero and First Order Reaction | Tough | numerical | false | JEE Main | CH-17 Chemistry Paper 26 Nov. Second.docx | |||
CH-08-Q23 | Starting with three different amino acid molecules, how many
different tripeptide molecules are formed | [] | null | 6 | Six type of tripe tide molecules are formed. | [] | Chemistry | Organic Chemistry | Biomolecules | Moderate | numerical | false | JEE Main | CH-08 Chemistry Paper 23 October.docx | ||||
CH-10-Q19 | The volume of a gas decreases from [IMAGE] to
[IMAGE] when a sample of gas is compressed by an average
pressure of 0.6 atm. During this process 10 of heat is liberated. The
change in internal energy is | [
"images/image95.png",
"images/image96.png"
] | - 2.16 J | 12.156 J | 2.16 J | 101.3 J | 3 | null | Here t Change in
[IMAGE] Pressure (P) = 0.6 atm and heat liberated (q)=10 J
But 1 liter-atm = 101.3 J
Hence [IMAGE]. We also know that heat is liberated,
therefore it would be negative. Thus change in | [
"images/image97.png",
"images/image98.png",
"images/image99.png"
] | Chemistry | Physical Chemistry | Thermodynamics | Moderate | single_correct | true | JEE Main | CH-10 Chemistry Paper-1 30 Oct New Jee main.docx |
CH-13-Q15 | Reaction of phenol with dil. HNO_3 gives | [] | p and m-nitrophenols | o- and p-nitrophenols | Picric acid | o- and m-nitrophenols | 2 | null | [
"images/image26.png"
] | Chemistry | Organic Chemistry | Alcohols, Phenols and Ethers | Moderate | single_correct | true | JEE Main | CH-13 Chemistry Paper 4 Nov..docx | |
CH-22-Q13 | Which one of the following reagents is not suitable for the
elimination reaction? | [
"images/image15.png"
] | Nal | 4 | null | The given conversion is carried out in the absence of 1.37
Bromopropane reacts with F_G$= \frac{GMm}{(R + h)^{2}}$ and yields
iodopropane.
$(4\pi\mu Bb)\Delta n$ | [] | Chemistry | Organic Chemistry | Alkyl And Aryl Halide | Moderate | single_correct | true | JEE Main | CH-22 Chemistry Paper 19 Dec. Eng.docx | |||
CH-25-Q12 | 1-Bromo-3-chlorocyclobutane will react with two moles of Na in
ether producing?
1-czkseks&3&Dyksjks Na ds nks eksy | [] | 1 | null | [
"images/image39.png"
] | Chemistry | Organic Chemistry | Hydrocarbon | Moderate | single_correct | true | JEE Main | CH-25 Chemistry Paper 7 Jan.docx | |||||
CH-19-Q8 | Nitration of aniline in the strong acidic medium also gives m
-nitroaniline because
A In absence of substituents nitro group always goes to m- positions
B In spite of substituents nitro group always goes to only m -
positions
C In strong acidic medium aniline is present as anilinium ion
D In electrophilic substitution ... | [] | 1 | null | Nitration of aniline in strong acidic medium also gives
m-nitroaniline because in acidic (strong) medium aniline is present as
anilinium ion. Amino ${- NH}_{2}$ group is ortho-para directing but
${- NH}_{3}^{+}$ group is meta directing.
$C_{6}H_{5} - {NH}_{2} + H^{+}\overset{strong\ acid}{\longrightarrow}C_{6}H_{5} - {... | [] | Chemistry | Amines | Chemical Reactions of Amines | Tough | single_correct | false | JEE Main | CH-19 Chemistry Paper 28 Nov. Fourth.docx | ||||
CH-18-Q4 | Which of the following is the structure of (S)-Pentan-2-ol is? | [] | 3 | null | [IMAGE] the arrow is clockwise but least priority
group is on horizontal line of fischer projection. | [
"images/image9.png"
] | Chemistry | Stereoisomerism | R/S & D/L Naming. | Moderate | single_correct | true | JEE Main | CH-18 Chemistry Paper 27 Nov. Third.docx | ||||
CH-16-Q6 | Equal weight of (At. wt. = 24) are
reacted to form the compound[IMAGE]. Then | [
"images/image20.png"
] | X is the limiting reagent | Y is the limiting reagent | No reactant is left over and mass of
[IMAGE] formed is double the mass of 'X' taken | none of these | 3 | null | [IMAGE] No. one is L.R. | [
"images/image22.png",
"images/image23.png",
"images/image24.png",
"images/image25.png",
"images/image26.png",
"images/image27.png",
"images/image28.png",
"images/image29.png",
"images/image30.png"
] | Chemistry | Mole concept | Limiting reagent, % Excess, % Yield / Efficiency | Tough | single_correct | true | JEE Main | CH-16 Chemistry Paper 25 Nov. Fisrt.docx |
CH-01-Q14 | Suppose that a hypothetical H-like atom gives a red Green, blue, &
violet line spectrum.
Which jump according to figure would give off the red spectral line. | [
"images/image41.png"
] | 3 - 1 | 2 → 1 | 4 ࢮ 1 | 3 ࢮ 2 | null | null | In VIBGYOR, Red has maximum wavelength.
∴ Line having red color will have maximum energy
Hence
3 → 2 | [] | Chemistry | single_correct | true | JEE Main | CH-01 Chemistry Paper 1.docx | |||
CH-24-Q3 | N_2 and H_2 are taken in 1: 3 molar ratio in a closed vessel
to attained the following
equilibrium$N_{2}(g) + 3H_{2}(g) \rightleftharpoons 2{NH}_{3}(g)$. Find
K_p for reaction at total pressure of 2P if [IMAGE] at
equilibrium is $\frac{P}{3}$. | [
"images/image2.png"
] | $\frac{1}{3P^{2}}$ | $\frac{4}{3P^{2}}$ | $\frac{4P^{2}}{3}$ | None | 2 | null | $N_{2}(g) + 3H_{2}(g) \rightleftharpoons 2{NH}_{3}(g)$.
At equilibrium $\frac{P}{3}$ P, [IMAGE] $K_{p} = \frac{\frac{2P}{3} \times \frac{2P}{3}}{\frac{P}{3} \times P^{3}} = \frac{1}{P^{2}} \cdot \frac{4}{3}$
$\Rightarrow$ $K_{p} = \frac{4}{3P^{2}}$ | [
"images/image3.png",
"images/image4.png"
] | Chemistry | Physical Chemistry | Chemical Equilibrium | Moderate | single_correct | true | JEE Main | CH-24 Chemistry Paper 31 Dec..docx |
CH-13-Q2 | Lowering of vapour pressure is highest for | [] | Urea | 0.1M glucose | 0.1 M MgSO_4 | 0.1 M BaCl_2 | 4 | null | of P^0 - P_s Ps is maximum for BaCl_2. | [
"images/image5.png",
"images/image6.png"
] | Chemistry | Physical Chemistry | Moderate | single_correct | true | JEE Main | CH-13 Chemistry Paper 4 Nov..docx | |
CH-19-Q2 | What is in the following reaction ?
MgCl2.6H2O + HCl + H2O | [
"images/image3.png"
] | MgO | Mg | Mg(OH)2 | Mg(OH)Cl. | 1 | null | MgCl2.6H2O[IMAGE] MgO + 2 HCl + 5H2O | [
"images/image4.png"
] | Chemistry | S-block | Oxides, Peroxides, Super Oxides, Hydroxides | Easy | single_correct | true | JEE Main | CH-19 Chemistry Paper 28 Nov. Fourth.docx |
CH-14-Q4 | 4 g of copper was dissolved in concentrated nitric acid. The
copper nitrate solution on strong heating gave 5 g of its oxide. The
equivalent weight of copper is | [] | 23 | 32 | 12 | 20 | 2 | null | present.
--------------------------------------------
Element Wt. At Wt. Wt./At Wt. Ratio
---------- ---- ----- ------------ ------------
Cu 4 gm 63.5 4/63.5 = 0.625 [IMAGE] O 1 gm 16 1-16 = 0.0625 [IMAGE] --------------------------------------------
Empirical formula = [IMAGE] of oxide
In this oxide, oxidation no.... | [
"images/image12.png",
"images/image13.png",
"images/image14.png",
"images/image15.png",
"images/image16.png",
"images/image17.png",
"images/image18.png"
] | Chemistry | Physical Chemistry | Electrochemistry | Moderate | single_correct | true | JEE Main | CH-14 Chemistry Paper 7 Nov..docx |
CH-27-Q9 | The substance used in holmes singnals of the ship is a mixture of:
tgktkssa gksYe flXuy (holmes singnals) | [] | CaC2 + Ca3P2 | Ca3(PO4)2 + Pb3O4 | H3PO4 + CaCl2 | NH3 + HOCl | 1 | null | The spontaneous combustion of phosphine is technically used in
Holme's signals. Containers containing calcium carbide and calcium
phosphide are pierced and thrown in the sea when the gases evolved burn
and serve as a signal.
QkWLQhu ds Lor ngu dks rduhdh:i ls gksYe ds lwpdksa (Holme's signals)
ik=kksa dks fNfnzr dj l... | [] | Chemistry | Inorganic Chemistry | P-block Halogen | Moderate | single_correct | false | JEE Main | CH-27 Chemistry Paper 2 15 Jan.docx |
CH-28-Q17 | In a first order reaction, the concentration of the reactant,
decreases from 0.8 M to 0.4 M in 15 minutes. The time taken for the
concentration to change from 0.1 M to 0.025 M is | [] | 30 minutes | 15 minutes | 7.5 minutes | 60 minutes | 1 | null | The concentration fo the reactant decreases from 0.8 M to 0.4 M
in 15 minutes, i.e., $t_{1/2} = 15$ minute. Therefore, the concentration
of reactant will fall from 0.1 M to 0.025 in two half live. i.e.,
$2t_{1/2} = 2 \times 15 = 30$ minutes. | [] | Chemistry | Physical Chemistry | Chemical Kinetics & Radioactivity | Moderate | single_correct | false | JEE Main | CH-28 Chemistry Paper FST 16 Jan.docx |
CH-23-Q22 | Excess of silver nitrate is added to a water sample to determine
the amount of chloride ion present in the sample. 1.4 g of silver
chloride is precipitated. The mass of chloride ion present in the sample
is:
Molar masses (g-mol-1): AgNO3 169.91, AgCl 143.25 | [] | 0.25 g | 0.35 g | 0.50 g | 0.75 g | 2 | null | ${AgNO}_{3} + {Cl}^{-} \longrightarrow AgCl \downarrow + {NO}_{3}^{-}$
1.4 g
$= \frac{1.4}{143.5}mol$
$= \frac{1.4}{143.25} \times 35.5gmCl = 0.35gm$ | [] | Chemistry | Physical Chemistry | Mole concept | Easy | single_correct | false | JEE Main | CH-23 Chemistry Paper 31 Dec. FST.docx |
CH-08-Q15 | In Goldschmidt aluminothermic process, thermite contains | [] | 3 parts of Al_2O_3 and 4 parts of Al | 3 parts of Fe_2O_3 and 2 parts of Al | 3 parts of Fe_2O_3 and 1 parts of Al | 1 parts of Fe_2O_3 and 1 parts of Al | 3 | null | In Goldschmidt aluminothermic process, thermite contains 3
parts of Fe_2O_3 and 1 part
of Al. | [] | Chemistry | Inorganic Chemistry | p-block elements | Easy | single_correct | false | JEE Main | CH-08 Chemistry Paper 23 October.docx |
CH-10-Q1 | [IMAGE], the reaction is | [
"images/image1.png"
] | Redox | Neutralization | Oxidation | Reduction | 1 | null | [IMAGE] Oxidation and Reduction both occur so the reaction is redox. | [
"images/image2.png"
] | Chemistry | Physical Chemistry | Redox Reaction | Moderate | single_correct | true | JEE Main | CH-10 Chemistry Paper-1 30 Oct New Jee main.docx |
CH-22-Q1 | The following statements concern elements in the periodic table.
Which of the following is true? | [] | All the elements in Group 17 are gases. | The Group 13 elements are all metals. | Elements of Group 16 have lower ionization enthalpy values
compared to those of Group 15 in the correspondingperiods. | For Group 15 elements, the stability of +5 oxidation
stateincreases down the group. | 3 | null | The group $g_{out\ } = \frac{Gm}{r^{2}}$ elements have
ionization energy that is much higher than that of the elements if
group $F = Y\alpha_{L}A\Delta t$ as $F = \left( 2 \times 10^{11}{Nm}^{- 2} \right)\left( 1.2 \times 10^{- 5}K^{- 1} \right)\left( 40 \times 10^{- 4}m^{2} \right)(10)$
the ground = 9.6 × 10^4 N
= 1 ×... | [] | Chemistry | Inorganic Chemistry | Periodic Table | Moderate | single_correct | false | JEE Main | CH-22 Chemistry Paper 19 Dec. Eng.docx |
CH-26-Q9 | Change in volume of the system does not alter the number of moles
in which of the following equilibriums:
fuEu esa fdl fy, vk;ru ifjorZu | [] | N2(g) + O2(g)[IMAGE] 2NO(g) | PCl5(g)[IMAGE] PCl3(g) + Cl2(g) | N2(g) + 3H2(g)[IMAGE] 2NH3(g) | SO2Cl2(g)[IMAGE] SO2(g) + Cl2(g) | 1 | null | In this reaction the ratio of number of moles of reactants to
products in same i.e., 2: 2, hence change in volume will not alter the
number of moles.
leku gksrk gS] vFkkZr~ 2: 2 gSA vr vk;ru ifjorZu | [] | Chemistry | Physical Chemistry | Chemical Equilibrium | Moderate | single_correct | false | JEE Main | CH-26 Chemistry Paper 1 15 Jan.docx |
CH-24-Q18 | The pH of a solution obtained by mixing 100 mL of 0.2 M
CH_3COOH with 100 mL of 0.2 M NaOH would be: (pK_a for CH_3COOH =
4.74) | [] | 4.74 | 8.87 | 9.10 | 8.57 | 2 | null | CH_3COOH + OH^- [IMAGE] CH3COO^- + H_2O
t = 0 20 20
t = eq - - 20
So, [CH_3 COO^-] $= \frac{20}{200}$ = 0.1M
pH = 7 +
$\frac{1}{2}{pK}_{a} + \frac{1}{2}logC = 7 + 2.37 + \frac{1}{2}$
log10^-1 = 7 + 2.37 - 0.5 = 8.87 | [
"images/image26.png"
] | Chemistry | Physical Chemistry | Ionic Equilibrium | Moderate | single_correct | true | JEE Main | CH-24 Chemistry Paper 31 Dec..docx |
CH-06-Q12 | Which of the following graph of potential energy represent the
unimolecular elimination reaction ? | [] | 3 | null | It is two step reaction and first step is slow and rds. | [] | Chemistry | Organic Chemistry | Hydrocarbons | Easy | single_correct | false | JEE Main | CH-06 Chemistry Paper 14 October.docx | ||||
CH-24-Q27 | The dissociation pressure of silver oxide at 445ºC is 207 atm.
Calculate $\Delta$Gº for the formation of 1 mole Ag_2O(s) from metal
and oxygen at this temperature. (log 207 = 2.315). Report your answer in
Kcal and round of the value to nearest integer. | [] | null | 4 | T = 445ºC = 445 + 273 = 718K
P = 207atm
n = 1 mole
${Ag}_{2}O \rightleftharpoons 2Ag(s) + \frac{1}{2}O_{2}(g)$
$K_{p} = \sqrt{P_{O_{2}}}$ = (207)^1/2 = 14.39
$\Delta G^{\circ} = \Delta G^{0}$ + 2.303 Rt log K_eq
But at eq. $\Delta$G = 0
$\Delta$ G^0 = - 2.303 RT log K_eq.
But for formation
$2Ag(s) + \frac{1}{2}O_{2}(g)... | [] | Chemistry | Physical Chemistry | Chemical Equilibrium | Tough | numerical | false | JEE Main | CH-24 Chemistry Paper 31 Dec..docx | ||||
CH-09-Q1 | [
"images/image1.png",
"images/image2.png"
] | In neutral solution | In acidic solution | In non-polar solvent | In alkaline solution | 2 | null | When [IMAGE] reduces with [IMAGE].
It is present in acidic solution. | [
"images/image1.png",
"images/image2.png",
"images/image3.png"
] | Chemistry | Physical Chemistry | Redox Reaction | Easy | single_correct | true | JEE Main | CH-09 Chemistry Paper 26 October.docx | |
CH-23-Q14 | Least contributing resonating structure of nitroethene is | [] | 3 | null | In (C) two positive charge on adjacent position. | [] | Chemistry | Organic Chemistry | Organic Chemistry | Moderate | single_correct | false | JEE Main | CH-23 Chemistry Paper 31 Dec. FST.docx | ||||
CH-05-Q23 | How many of the following compounds are found to exist?
(i) BiF_5 (ii) T[IMAGE] I_3 (iii) PbO_2 (iv) SnCl_2 | [
"images/image44.png"
] | null | null | 6 (except (vi)) | [] | Chemistry | Inorganic Chemistry | Periodic Properties | Moderate | single_correct | true | JEE Main | CH-05 Chemistry Paper 10 October.docx | ||||
CH-06-Q9 | In which one of the following species the central atom has the
type of hybridization which is not the same as that present in the other
three? | [] | SF_4 | $l_{3}^{-}$ | ICl_5 | PCl_5 | 3 | null | ICl_5 has sp^3d^2 hybridization.
$l_{3}^{-}$, SF_4, and PCl_5; all have sp3d hybridization | [] | Chemistry | Inorganic Chemistry | Chemical Bonding | Tough | single_correct | false | JEE Main | CH-06 Chemistry Paper 14 October.docx |
CH-11-Q12 | Which is the most stable carbocation? | [] | iso-propyl | Triphenylmethyl cation | Ethyl cation | [IMAGE] -propyl cation | 2 | null | Stability of carbonium ions. tertiary alkyl > secondary alkyl
> primary alkyl > methyl. More the number of alkyl groups, the greater
the dispersal of positive charge and therefore, more the stability of
carbonium ion is observed.
[IMAGE] Dispersal of positive charge increases with the increase in the number
of benzene ... | [
"images/image24.png"
] | Chemistry | Organic Chemistry | Organic Chemistry | Moderate | single_correct | true | JEE Main | CH-11 Chemistry Paper-2 1Nov New Jee main.docx |
CH-24-Q19 | For a BH_2Cl_2 solution (chloride salt of a diacidic base B):
(Dissociation constants of base are [IMAGE] & | [
"images/image27.png",
"images/image28.png"
] | 3 | null | [
"images/image33.png",
"images/image34.png",
"images/image35.png"
] | Chemistry | Physical Chemistry | Ionic Equilibrium | Moderate | single_correct | true | JEE Main | CH-24 Chemistry Paper 31 Dec..docx | |||||
CH-09-Q17 | Mottling of teeth caused by excessive intake of | [] | Potassium | Iodine | Chlorine | Fluorine | 4 | null | Explanation: Dental fluorosis is also known as mottling of
teeth. It is caused by excessive ingestion of Fluorine during enamel
formation. | [] | Chemistry | Inorganic Chemistry | Environmental Chemistry | Moderate | single_correct | false | JEE Main | CH-09 Chemistry Paper 26 October.docx |
CH-22-Q3 | Identify the reaction which does not liberate hydrogen | [] | Reaction of zinc with aqueous alkali | Electrolysis of acidified water using Pt electrodes. | Allowing a solution of sodium in liquid ammonia to stand. | Reaction of lithium hydride with B_2 H_6. | 4 | null | Lithium hydride reacts
with$U_{total\ } = \frac{1}{2}nRT + \frac{5}{2}NRT - \frac{5}{2}NRT$
$= \frac{1}{2}nRT$
and the reaction is expressed as follows,
$a = a_{0}e^{\frac{- bc}{m}}$
The above reaction proves that the liberation of hydrogen gas is not
possible. | [] | Chemistry | Inorganic Chemistry | P-block | Moderate | single_correct | false | JEE Main | CH-22 Chemistry Paper 19 Dec. Eng.docx |
CH-27-Q16 | The standard Gibbs energy change at 300 K for the reaction is
2A[IMAGE] B + C is 2494.2 J. At a given time, the
composition of the reaction mixture is = 2
and = 8.314 | [
"images/image14.png"
] | Forward direction because Q > KC
(2) Reverse direction because Q > KC | foijhr fn'kk | Forward direction because Q < KC | Reverse direction because Q < KC
300 K ij vfHkfØ;k 2A[IMAGE] B + C dh ekud fxCt
gksrh | 2 | null | DG = DGº + RT ln Q
= 2494.2 + 8.314 × 300 ln 4
= positive èkukREkd
$\Delta G = RT\mathcal{l}n\frac{Q}{K}$
Since, ΔG is positive so, Q > K, so reaction shifts in reverse
direction.
pwfda ΔG èkukRed gS, blfy, Q > K, vr | [] | Chemistry | Physical Chemistry | Chemical Equilibrium | Moderate | single_correct | true | JEE Main | CH-27 Chemistry Paper 2 15 Jan.docx |
CH-07-Q7 | Morphine is | [] | Anesthetic | Analgesic | Antiseptic | Antibiotics | 2 | null | Morphine is analgesic. | [] | Chemistry | Organic Chemistry | Chemistry in everyday life | Easy | single_correct | false | JEE Main | CH-07 Chemistry Paper 17 October.docx |
CH-14-Q7 | Which of the following statement is not true about Mohr's salt | [] | It decolorizes [IMAGE] | It is a primary standard | It is a double salt | Oxidation state of iron is +2 in this salt | 4 | null | Oxidation state of iron in Mohr's salt | [
"images/image33.png"
] | Chemistry | Inorganic Chemistry | D & F -Block Elements | Easy | single_correct | true | JEE Main | CH-14 Chemistry Paper 7 Nov..docx |
CH-10-Q7 | Of the four oxy-acids of chlorine the strongest oxidizing agent
in dilute aqueous solution is | [] | 4 | null | [IMAGE] is the strongest oxidizing agent. The
correct order of oxidizing power is | [
"images/image37.png",
"images/image38.png"
] | Chemistry | Physical Chemistry | Redox Reaction | Moderate | single_correct | true | JEE Main | CH-10 Chemistry Paper-1 30 Oct New Jee main.docx | ||||
CH-15-Q9 | Colloidal solution of gold prepared by different methods of
different colors because of | [] | different diameters of colloidal gold particles | variable valency of gold | different concentration of gold particles | impurities produced by different methods | 1 | null | Different colloidal particle will provide different color to
the sol. | [] | Chemistry | Surface Chemistry | Classification and Preparation of Colloid | Easy | single_correct | false | JEE Main | CH-15 Chemistry Paper 11 Nov..docx |
CH-05-Q11 | Total number of structural unsaturated 3º alcohols possible with
molecular formula C_6H_12O is | [] | 1 | 2 | 3 | 4 | 4 | null | (i) [IMAGE] (ii) | [
"images/image24.png",
"images/image25.png",
"images/image26.png"
] | Chemistry | Organic Chemistry | Some Basic Principles and Techniques | Tough | single_correct | true | JEE Main | CH-05 Chemistry Paper 10 October.docx |
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