question_id string | question string | question_images list | option_1 string | option_2 string | option_3 string | option_4 string | correct_option int64 | numerical_answer string | solution string | solution_images list | subject string | topic string | subtopic string | difficulty string | question_type string | has_image bool | exam string | source_paper string |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
CH-28-Q7 | Which of the following contains both electrovalent and covalent
bonds ? | [] | CH4 | H2O2 | NH4Cl | none | 3 | null | [
"images/image5.png"
] | Chemistry | Inorganic Chemistry | Chemical Bonding | Moderate | single_correct | true | JEE Main | CH-28 Chemistry Paper FST 16 Jan.docx | |
CH-27-Q4 | Benzene and naphthalene form an ideal solution at room
temperature. For this process, the true statement(s) is (are):
bl izØe | [] | $\Delta G$ is positive $\Delta G$ A | $\Delta S_{surroundings\ } = 0$ | $\Delta H = 0$ | 3 | null | $\Delta G = - \ ve\ $ $\Delta S_{systen\ } = + \ ve\ $ Always
for solution formation.
$\Delta S_{surr.\ } = 0$ No heat exchange between solution and
surrounding.
$\Delta H = 0$ For ideal solution. | [] | Chemistry | Physical Chemistry | Moderate | single_correct | false | JEE Main | CH-27 Chemistry Paper 2 15 Jan.docx | ||
CH-27-Q32 | Benzene and toluene form nearly ideal solutions. At 20ºC, the
vapour pressure of benzene is 75 torr and that of toluene is 22 torr.
The partial vapour pressure of benzene at 20 ºC for a solution
containing 78 g of benzene and 46 g of toluene in torr is:
csathu rFkk VkWyqbZu yxHkx cukrs gSaA 20ºC ij] casthu
g rFkk VkWyq... | [] | null | 50 | $P_{B} = P_{B}^{0}XB$ $P_{B}^{0} = 75\ torr\ $
$X_{B} = \frac{78/78}{(78/78) + (46/92)} = \frac{1}{1 + 0.5} = \frac{1}{1.5}P_{B} = 75 \times \frac{1}{1.5} = 50\ torr.\ $ | [] | Chemistry | Physical Chemistry | Moderate | numerical | false | JEE Main | CH-27 Chemistry Paper 2 15 Jan.docx | |||||
CH-06-Q13 | The radial probability distribution curve of an orbital of H has
4 local mixima. If orbital has 3 angular node then orbital will be | [] | 7f | 8f | 7d | 8d | 1 | null | $n\mathcal{- l} = 4$
$\mathcal{l =}3$
n = 7: so 7f | [] | Chemistry | Physical Chemistry | Atomic Structure | Moderate | single_correct | false | JEE Main | CH-06 Chemistry Paper 14 October.docx |
CH-01-Q11 | (C) is: (C) | [
"images/image23.png",
"images/image24.png",
"images/image25.png",
"images/image26.png"
] | null | null | [
"images/image31.png"
] | Chemistry | single_correct | true | JEE Main | CH-01 Chemistry Paper 1.docx | ||||||||
CH-24-Q8 | What is the minimum mass of CaCO_3 (s), below which it
decomposes completely, required to establish equilibrium in a 6.50 litre
container for the reaction:
${CaCO}_{3}(s) \rightleftharpoons CaO(s) + {CO}_{2}(g)$; K_c = 0.05 | [] | 32.5 g | 24.6 g | 40.9 g | 8.0 g | 1 | null | K_C = [CO_2] = 0.05 mole/litre
so moles of CO_2 = 6.50 × 0.05 moles = 0.3250 moles
${CaCO}_{3}(s) \rightleftharpoons CaO(s) + {CO}_{2}(g)$
1 mole of CO_2 = 1 mole of CaCO_3
0.3250 moles of CO_2 = 0.3250 moles of CaCO_3 = 0.3250 × 100 g of
CaCO_3 = 32.5 gm of CaCO_3 | [] | Chemistry | Physical Chemistry | Chemical Equilibrium | Tough | single_correct | false | JEE Main | CH-24 Chemistry Paper 31 Dec..docx |
CH-12-Q4 | The inter metallic compound LiAg crystallizes in cubic lattice
in which both lithium and silver have coordination number of eight. The
crystal class is. | [] | Simple cube | Body-centered cube | Face-centered cube | None of these | 2 | null | In Body-centered cube an atom have coordination number of eight | [] | Chemistry | Physical Chemistry | Moderate | single_correct | false | JEE Main | CH-12 Chemistry Paper 2 Nov..docx | |
CH-23-Q13 | In which of the following pairs of carbanion the first one is
more stable than second. | [] | 2 | null | Stability of carbanion µ -I effect, -m effect.
[IMAGE] (due to $p\pi - d\pi$ back bonding).
[IMAGE] (stability of anion, sp > sp2 > sp3)
[IMAGE] (stability order of carbanion inversely related to +I) | [
"images/image45.png",
"images/image46.png",
"images/image47.png",
"images/image48.png",
"images/image44.png"
] | Chemistry | Organic Chemistry | Organic Chemistry | Moderate | single_correct | true | JEE Main | CH-23 Chemistry Paper 31 Dec. FST.docx | ||||
CH-21-Q1 | In which case formation of butane nitrile is possible | [] | $C_{3}H_{7}Br + KCN$ | $C_{4}H_{9}Br + KCN$ | $C_{3}H_{7}OH + KCN$ | $C_{4}H_{9}OH + KCN$ | 1 | null | $C_{3}H_{7}Br + KCN \rightarrow C_{3}H_{7}CN + KBr$
In IUPAC system the carbon of functional group also take in numbering.
So $C_{3}H_{7}CN$ is butane nitrile.
gy IUPAC iz.kkyh | [] | Chemistry | Halogen | Properties of Halogen containing compounds | Easy | single_correct | false | JEE Main | CH-21 Chemistry Paper 19 Dec. Eng Hindi.docx |
CH-17-Q12 | Hot concentrated HNO3 converts graphite into | [] | graphite oxide | benzene hexacarboxylic acid | both (A) and (B) | none of the above | 2 | null | Graphite changes to Mellitic acid also called benzene
hexa-carboxylic acid with hot concentrated HNO | [] | Chemistry | P-block | Properties of Elements | Moderate | single_correct | false | JEE Main | CH-17 Chemistry Paper 26 Nov. Second.docx |
CH-17-Q16 | In a hypothetical solid C atoms form CCP lattice with A atoms
occupying all the Tetrahedral Voids and B atoms occupying all the
octahedral voids. A and B atoms are of the appropriate size such that
there is no distortion in the CCP lattice. Now if a plane is cut(as
shown) then type of voids and their numbers which are ... | [
"images/image52.png"
] | O.V = 3, T.V. = 4 | O.V. = 2, T.V. = 4 | O.V. = 1, T.V. = 2 | O.V. = 0, T.V. = 4 | 1 | null | [IMAGE] ® Octahedral void, at edge center &
body center. | [
"images/image53.png",
"images/image54.png",
"images/image55.png"
] | Chemistry | Voids | Moderate | single_correct | true | JEE Main | CH-17 Chemistry Paper 26 Nov. Second.docx | |
CH-04-Q9 | S_1: Photoelectric effect can be explained on the basis of
wave nature of electromagnetic radiations. -
S_2: An orbital represented by n = 2,= 1 is dumb-bell shaped.
S_3: d_xy orbital has zero probability of finding electrons
along X-axis and Y-axis.
S_1:
S_2: n = 2,= 1 (dumb-bell)
S_3: X Y | [] | FTF (2) FTT | TFT | TFF | null | 2 | S_1:Photoelectric effect can be explained on the basis of
particle nature of electromagnetic radiations.
S_2: n = 2, = 1 [IMAGE] 2p-orbital
[IMAGE] dumb-bell shaped.
S_3: d_xy orbital has its lobes directed at an angle of 45º
from X-axis and Y-axis. So, it has zero probability of finding
electrons along X-axis and Y-a... | [
"images/image20.png",
"images/image21.png",
"images/image22.png",
"images/image23.png"
] | Chemistry | Physical Chemistry | Atomic Structure | Moderate | numerical | true | JEE Main | CH-04 Paper 02 Chemistry with Hindi 22-8-2020.docx | |
CH-25-Q22 | [IMAGE] P (major), P is:
[IMAGE] P (eq[;), P | [
"images/image89.png",
"images/image89.png"
] | 3 | null | [
"images/image94.png",
"images/image95.png",
"images/image96.png",
"images/image97.png"
] | Chemistry | Organic Chemistry | Hydrocarbon | Tough | single_correct | true | JEE Main | CH-25 Chemistry Paper 7 Jan.docx | |||||
CH-28-Q8 | Select the correct statement with respect to alkali metals. | [] | Melting point decrease with increasing atomic number. | Potassium is lighter than sodium. | Salts of Li to Cs impart characteristic colour to an oxidising
flame (of Bunsen burner). | All of these. | 4 | null | (1) Down the group due to increase in size the strength of
metallic bond decreases and so, melting point decreases.
(2) Atomic volume of K is larger as compared to Na. Increase in atomic
mass does not over come the effect of increase atomic volume in case of
potassium.
(3) They have low ionisation energies because of t... | [] | Chemistry | Inorganic Chemistry | S-block | Easy | single_correct | false | JEE Main | CH-28 Chemistry Paper FST 16 Jan.docx |
CH-28-Q9 | Aluminium is extracted by the electrolysis of | [] | alumina | bauxite | molten cryolite. | alumina mixed with molten cryolite | 4 | null | Alumina is mixed with cryolite, in molten state which make
alumina good conductor and lowers the fusion temperature also. | [] | Chemistry | Inorganic Chemistry | P-block | Moderate | single_correct | false | JEE Main | CH-28 Chemistry Paper FST 16 Jan.docx |
CH-08-Q2 | The equilibrium concentration of X, Y and Y X_2 5lare
4,2 and 2 moles respectively for the equilibrium 2X + Y = YX_2.
The value of K_c. is | [] | 0.625 | 0.0625 | 6.25 | 0.00625 | 2 | null | [
"images/image2.png"
] | Chemistry | Physical Chemistry | Chemical and Ionic Equilibrium | Moderate | single_correct | true | JEE Main | CH-08 Chemistry Paper 23 October.docx | |
CH-06-Q8 | The quantum numbers of four electrons (e1 to e4) are given below:
-------------------------------------
n l m s
------- ------- ------- ------ ----------
e1 3 0 0 $$+
e2 4 0 0 $$+
e3 3 2 -2 $$-
e4 4 1 -1 $$+
-------------------------------------
The correct order of decreasing energy of these electrons is | [] | e4> e3 > e2 > e1 | e2 > e3 > e4 > e1 | e3 > e2 > e4 > e1 | e1 > e4 > e2 > e3 | 1 | null | e1 = 3s
e2 = 4s
e3 = 3d
e4 = 4p | [] | Chemistry | Physical Chemistry | Atomic Structure | Moderate | single_correct | false | JEE Main | CH-06 Chemistry Paper 14 October.docx |
CH-02-Q25 | are INTEGER ANSWER TYPE Questions.
(The answer of each of the questions is 2 digits integer)] | [] | null | null | [] | Chemistry | single_correct | false | JEE Main | CH-02 Chemistry paper 2.docx | ||||||||
CH-05-Q14 | What is number of delocalised lone pairs in the following
compound? | [
"images/image33.png"
] | 2 | 3 | 4 | 5 | 1 | null | Bridge head N is not delocalized electron. | [] | Chemistry | Organic Chemistry | Some Basic Principles and Techniques | Moderate | single_correct | true | JEE Main | CH-05 Chemistry Paper 10 October.docx |
CH-22-Q2 | Extraction of copper by smelting uses silica as an additive tore
move | [] | Cu_2 S | FeO | FeS | Cu_2 O | 2 | null | The reaction involved in the smelting process is given by,
$Q = \frac{\pi r^{4}}{8\eta}\frac{\Delta P}{L}$
$\frac{P_{1}r_{1}^{4}}{l_{1}} = \frac{P_{2}r_{2}^{4}}{l_{2}}$
In this prosses
$\frac{P_{r_{1}}^{4}}{l_{1}} = \frac{4P_{1}r_{2}^{4}}{\frac{I_{1}}{4}}$
forms the flux and $u_{initial\ } = \frac{5}{2}$ NRT
$r_{2}^{... | [] | Chemistry | Physical Chemistry | Metallurgy | Moderate | single_correct | false | JEE Main | CH-22 Chemistry Paper 19 Dec. Eng.docx |
CH-22-Q18 | Observation of "Rhumann's purple" is a confirmatory test
forthe presence of | [] | Reducing sugar | Cupric ion | Protein | Starch | 3 | null | The Ninhydrin test helps in detecting the presence of 170Hz.
[IMAGE] The purple colored product is also known as "Rhumann'spurple" | [
"images/image19.png"
] | Chemistry | Organic Chemistry | Biomolecules | Tough | single_correct | true | JEE Main | CH-22 Chemistry Paper 19 Dec. Eng.docx |
CH-07-Q12 | Aspirin is chemically | [] | Methyl salicylate | Ethyl salicylate | Acetyl salicylic acid | o-hydroxy benzoic acid | 3 | null | Aspirin an antibiotic chemically Acetyl Salicylic acid | [
"images/image6.png"
] | Chemistry | Organic Chemistry | Chemistry in everyday life | Moderate | single_correct | true | JEE Main | CH-07 Chemistry Paper 17 October.docx |
CH-27-Q1 | During depression of freezing point in a solution, the following
are in equilibrium | [] | Liquid solvent-solid solvent | Liquid solvent-solid solute | Liquid solute-solid solute | Liquid solute-solid solvent
fgekad ds voueu | 1 | null | Only solvent molecule under go solidification. So liquid
solvent and solid solvent remain in equilibrium.
dsoy foyk;d v.kqvksa dk gh Bkslhdj.k gksrk gSA blfy, nzo foyk;d,oa Bksl
foyk;d lkE | [] | Chemistry | Physical Chemistry | Easy | single_correct | false | JEE Main | CH-27 Chemistry Paper 2 15 Jan.docx | |
CH-27-Q23 | [IMAGE] A and B respectively are | [
"images/image30.png"
] | o-bromostyrene, benzoic acid | p-bromostryrene, benzaldehyde | m-bromostyrene, benzaldehyde | Styrene dibromide, benzoic acid.
[IMAGE] A | 4 | null | [
"images/image31.png"
] | Chemistry | Organic Chemistry | Hydrocarbon | Moderate | single_correct | true | JEE Main | CH-27 Chemistry Paper 2 15 Jan.docx | |
CH-18-Q5 | A compound having straight chain of five carbon atoms has one
ketone group and two methyl groups on different-different carbon atoms.
The IUPAC name of the compound is | [] | 2,4-Dimethyl-3-oxopentane
(2) 2,4-Dimethylpentan-3-one | 3,4-Dimethyl-2-oxopentane | 3,3-Dimethylpentan-2-one | 2 | null | [IMAGE] 2,4-Dimethylpentan-3-one 3,4-Dimethylpentan-2-one | [
"images/image10.png",
"images/image11.png"
] | Chemistry | IUPAC and Structural Isomerism | Functional Isomerism | Moderate | single_correct | true | JEE Main | CH-18 Chemistry Paper 27 Nov. Third.docx | |
CH-25-Q9 | To prepare But-2-yne from 2, 2, 3, 3-Tetrachlorobutane, reagent
used is | [] | Zinc dust / $\Delta$ | Sodamide | Alc. KOH | aq. KOH
vfHkdeZd gksxk | 1 | null | [
"images/image26.png"
] | Chemistry | Organic Chemistry | Hydrocarbon | Moderate | single_correct | true | JEE Main | CH-25 Chemistry Paper 7 Jan.docx | |
CH-19-Q10 | Consider a Body Centered Cubic(bcc) arrangement, let de, dfd,
dbd be the distances between successive atoms located along the edge,
the face-diagonal, the body diagonal respectively in a unit cell.Their
order is given by | [] | de< dfd < dbd | dfd > dbd > de | dfd> de> dbd | dbd > de> dfd, | 3 | null | $d_{fd} = \sqrt{2}a$
$d_{bd} = \frac{\sqrt{3}a}{2}$
$\therefore d_{fd} > d_{e} > d_{bd}$ | [
"images/image13.png"
] | Chemistry | Simple Cubic Structure & BCC | Moderate | single_correct | true | JEE Main | CH-19 Chemistry Paper 28 Nov. Fourth.docx |
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