question_id string | question string | question_images list | option_1 string | option_2 string | option_3 string | option_4 string | correct_option int64 | numerical_answer string | solution string | solution_images list | subject string | topic string | subtopic string | difficulty string | question_type string | has_image bool | exam string | source_paper string |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
CH-27-Q20 | The major product in the following reaction is | [
"images/image22.png"
] | 3 | null | [
"images/image27.png"
] | Chemistry | Organic Chemistry | Hydrocarbon | Tough | single_correct | true | JEE Main | CH-27 Chemistry Paper 2 15 Jan.docx | |||||
CH-11-Q1 | The conversion of PbO_2 to Pb(NO_3)_2 is | [] | Oxidation | Reduction | Neither oxidation nor reduction | Both oxidation and reduction | 2 | null | ${{Pb}^{+ 4}O}_{2} \rightarrow {Pb}^{+ 2}\left( NO_{3} \right)_{2}$. in
this reaction reduction occurs. | [] | Chemistry | Physical Chemistry | Redox Reaction | Moderate | single_correct | false | JEE Main | CH-11 Chemistry Paper-2 1Nov New Jee main.docx |
CH-27-Q25 | A compound decolourises KMnO4 but does not give ammonical AgNO3
ppt test,d;kSfxd KMnO4 dks fo?kfVr djrk | [] | CH3COCH3 | C2H6 | C2H4 | C2H2 | 3 | null | [
"images/image33.png",
"images/image34.png"
] | Chemistry | Organic Chemistry | Hydrocarbon | Moderate | single_correct | true | JEE Main | CH-27 Chemistry Paper 2 15 Jan.docx | |
CH-05-Q18 | Which of the following does not represent the correct order of
the property indicated against it? | [] | F > Cl > Br > I (Electro negativity) | Li > B > Be > C (Second ionisation enthalpy) | O < S > Se > Te (Electron affinity) | Ti < Zr[IMAGE] Hf (Atomic size) | 2 | null | Li > B > C > Be (Second ionisation enthalpy) | [] | Chemistry | Inorganic Chemistry | Periodic Properties | Moderate | single_correct | false | JEE Main | CH-05 Chemistry Paper 10 October.docx |
CH-05-Q19 | Aspirin has the formula C_9H_8O_4. How many atoms of oxygen
are there in a tablet weighing 360 mg ? | [] | 1.204 × 10^23 | 1.08 × 10^22 | 1.204 × 10^24 | 4.81 × 10^21 | 4 | null | Number of oxygen atoms$= \frac{360 \times 10^{- 3}}{180}$× 6.02
× 10^23 × 4 = 4.81 × 10^21 | [] | Chemistry | Physical Chemistry | Some Basic Concepts of Chemistry | Easy | single_correct | false | JEE Main | CH-05 Chemistry Paper 10 October.docx |
CH-27-Q31 | Water is added to the solution M such that the mole fraction of
water in the solution becomes 0.9. The boiling point of this solution is | [] | null | 376.2 | $\Delta T_{b} = K_{b} \cdot m$
$= 0.52 \times \frac{0.1}{0.9 \times 18} \times 1000 = \frac{520}{9 \times 18} = 3.20$
$T_{b} = 373 + 3.20 = 376.2K$ | [] | Chemistry | Physical Chemistry | Moderate | numerical | false | JEE Main | CH-27 Chemistry Paper 2 15 Jan.docx | |||||
CH-22-Q11 | Bromination of cyclohexene under conditions given below yields | [
"images/image2.png"
] | 2 | null | The given reaction follows the mechanism as shown below.
[IMAGE] This reaction undergoes free radical substitution.
In case of bromination of cyclohexene in the presence of light, the
product formed is shown below. | [
"images/image7.png",
"images/image8.png"
] | Chemistry | Organic Chemistry | Hydrocarbons | Moderate | single_correct | true | JEE Main | CH-22 Chemistry Paper 19 Dec. Eng.docx | ||||
CH-24-Q29 | In a solution containing 0.01 M HCl and 0.1 M H_2CO_3, ratio
of produced from strong acid & weak acid respectively is x: 1.
Report your answer as x/500. Given: of H_2CO_3 are 4 × 10^-7 & 4 ×
10^-11 respectively. | [] | null | 5 | $4 \times 10^{- 7} = \frac{0.01 \times \left\lbrack {HCO}_{3}^{-} \right\rbrack}{0.1}$
$\Rightarrow$ [H+]~from weak acid~ = [HCO_3^-] = 4 × 10^-6 M
$\therefore$ Ratio =
$\frac{0.01}{4 \times 10^{- 6}} = \frac{2500}{1} = x$
So, answer $= \frac{x}{500} = x$ | [] | Chemistry | Physical Chemistry | Ionic Equilibrium | Moderate | numerical | false | JEE Main | CH-24 Chemistry Paper 31 Dec..docx | ||||
CH-18-Q6 | Select the correct statement about this compound. | [
"images/image12.png"
] | All three C-N bond length are same. | C1-N and C3-N bonds length are same but shorter than C5-N bond
length. | C1-N and C5-N bonds length are same but longer than C3-N bond
length. | C1-N and C3-N bonds length are different but both are longer than
C5-N bond length. | 3 | null | Due to SIR effect. | [] | Chemistry | Organic Chemistry | Steric Inhibition of Resonance (SIR Effect) | Easy | single_correct | true | JEE Main | CH-18 Chemistry Paper 27 Nov. Third.docx |
CH-08-Q20 | Atoms in a P_4 molecule of white phosphorus are arranged
regularly in space in which of the following way | [] | At the corners of tetrahedron | At the corners of a cube | At the corners of a four membered ring | At the centre and corners of an equilateral triangle | 1 | null | [
"images/image21.jpeg"
] | Chemistry | Inorganic Chemistry | p block | Moderate | single_correct | true | JEE Main | CH-08 Chemistry Paper 23 October.docx | |
CH-16-Q19 | What will the concentration of in a sample of 1 liter
hard water if after treatment with washing soda 10 g insoluble CaCO3 is
precipitated. | [] | 0.2 M | 0.1 M | 0.3 M | 0.4 M | 2 | null | ${nCaCl}_{2} = {nCaCO}_{3}$
= 0.1mole$$ | [] | Chemistry | Equivalent Concept | Volume strength of H_2O_2, Hardness of water | Moderate | single_correct | false | JEE Main | CH-16 Chemistry Paper 25 Nov. Fisrt.docx |
CH-18-Q9 | When 100g of ethylene polymerises entirely to polyethene, the
weight of polyethene formed as per the equation n(C2H4) → (-CH2-CH2-)n
is | [] | 100g | 100ng | 2 | null | By applying POAC for C atoms
moles of ethylene × 2 = mole of polythene × n × 2
$\frac{100g}{28} \times 2 = \frac{wt.\ of\ polethene}{28 \times n} \times n \times 2$
wt. of polyethene = 100 g | [] | Chemistry | Mole concept | Stoichiometry, Equation based calculations | Moderate | single_correct | false | JEE Main | CH-18 Chemistry Paper 27 Nov. Third.docx | ||
CH-04-Q6 | In a gaseous mixture, if an alkane (C_xH_2x + 2) and an alkene
(C_yH_2y) are taken in 2: 1 mole ratio, the average molecular weight
of mixture is observed to be 20. If the same alkane and alkene are taken
in 1: 2 mole ratio, the average molecular weight of mixture is observed
to be 24. Then, the value of are respective... | [] | 2, 1 (2) 1, 2 | 2, 3 | 3, 2 | null | 2 | [IMAGE] 28x + 14y = 56...... (1)
[IMAGE] 14x + 28y = 70....... (2) | [
"images/image10.png",
"images/image11.png",
"images/image12.png"
] | Chemistry | Physical Chemistry | Mole Concept | Tough | numerical | true | JEE Main | CH-04 Paper 02 Chemistry with Hindi 22-8-2020.docx | |
CH-05-Q21 | x + y [IMAGE] x_2 y_3
2 moles of X and 4 moles of Y are mixed in a container. Difference of
final moles of Y and X_2Y_3 is | [
"images/image40.png"
] | null | null | 2X + 3Y [IMAGE] X_2 Y_2
2 4 0
LR ER
2 - 2 4 - 3 1 mole | [
"images/image41.png"
] | Chemistry | Physical Chemistry | Some Basic Concepts of Chemistry | Easy | single_correct | true | JEE Main | CH-05 Chemistry Paper 10 October.docx | ||||
CH-03-Q25 | are INTEGER ANSWER TYPE Questions.
(The answer of each of the questions is 2 digits
21 Energy of an emitted photon with wavelength 620 nm in electron volt
is:, 620 nm | [] | null | 02 | [
"images/image59.png",
"images/image60.png"
] | Chemistry | Physical Chemistry | Atomic Structure | Easy | numerical | true | JEE Main | CH-03 Paper 01 Chemistry with Hindi 21-8-2020.docx | |||||
CH-20-Q25 | The increasing order of acidity among phenol, p-methylphenol,
m-nitrophenol and p-nitrophenol is. Chose the correct integer as your
option. | [] | phenol<p-methylphenol<m-nitrophenol <p-nitrophenol | p-nitrophenol<p-methylphenol<m-nitrophenol <phenol | phenol <p-methylphenol<m-nitrophenol <p-nitrophenol | p-methylphenol< phenol<m-nitrophenol <p-nitrophenol | 4 | null | [
"images/image14.png"
] | Chemistry | Organic Chemistry | ALCOHOL | Easy | single_correct | true | JEE Main | CH-20 Chemistry Paper 12 Dec..docx | |
CH-18-Q17 | At 273 K temp. and 9 atm pressure, the compressibility for a gas
is 0.9. The volume of 1 mili-mole of gas at this temperature and
pressure is | [] | 2.24 litre | 0.020 mL | 2.24 mL | 22.4 mL | 3 | null | $Z = \frac{PV}{nRT};V = \frac{0.9 \times 0.0821 \times 273}{9} = 2.24litre/mol$
Volume of 1 mili-mole of gas = 2.24 mL | [] | Chemistry | Real Gas | Vander waal equation and virial equation of state | Moderate | single_correct | false | JEE Main | CH-18 Chemistry Paper 27 Nov. Third.docx |
CH-28-Q16 | The rate of chemisorption | [] | decreases with increase of pressure | increases with increase of pressure | is independent of pressure | is independent of temperature | 2 | null | On increasing pressure more molecule will into contact with the
surface of solid adsorbent. | [] | Chemistry | Physical Chemistry | Moderate | single_correct | false | JEE Main | CH-28 Chemistry Paper FST 16 Jan.docx | |
CH-16-Q9 | Match the correct atomic radius with the element:
S.No. Element Code Atomic radius (pm)
(i) Be (p) 74
(ii) C (q) 88
(iii) O (r) 111
(iv) B (s) 77
(v) N (t) 66 | [] | (i) - r, (ii) - q, (iii) - t, (iv) - s, (v) - p | (i) - t, (ii) - s, (iii) - r, (iv) - p, (v) - q | (i) - r, (ii) - s, (iii) - t, (iv) - q, (v) - p | (i) - t, (ii) - p, (iii) - r, (iv) - s, (v) - q | 3 | null | On moving left to right in a period, atomic radii decreases due
to increase in Z_eff and addition of electrons to the same outermost
shell. | [] | Chemistry | Periodic table | Atomic and Ionic radius | Moderate | single_correct | false | JEE Main | CH-16 Chemistry Paper 25 Nov. Fisrt.docx |
CH-19-Q13 | Bleaching powder turns Red litmus to blue and finally white, it
is due to:
(A) OH-
(B) HCl
(C) OCl-
(D) Cl | [] | 2 | null | (i) CaOCl2 + H2O → Ca(OH)2 + Cl2
(ii) Cl2 + H2O → HOCl+ HCl
HOCl → HCl +
Cl2 + H2O → 2HCl + | [] | Chemistry | S-block | Miscellaneous (Silicones, Silicates, Zeolites & Alums) | Moderate | single_correct | false | JEE Main | CH-19 Chemistry Paper 28 Nov. Fourth.docx | ||||
CH-27-Q39 | The solubility of Ag2CO3 in water is 1.26 × 10-4 mole/litre.
What is its solubility in 0.02 M Na2CO3 solution ? Assume no hydrolysis
of CO32- ion. (Take = 1.26)
ty esa Ag2CO3 1.26 x 10-4 eksy@yhVj
esa bl ekusa fd CO32- vk;u | [] | null | 10 | Na2CO3 [IMAGE] 2Na+ + CO32-
2 × 0.01 0.01
Ag2CO3 [IMAGE] 2 Ag+ + CO32-
2 x (x + 0.01) $\approx$ 0.01
Ksp = 4x2 (0.01)
Ksp = 4s3 = 4 × 10-12 = 4x2 (0.01) $\Rightarrow$ x = 10-5 | [
"images/image47.png",
"images/image48.png"
] | Chemistry | Physical Chemistry | Ionic Equilibrium | Moderate | numerical | true | JEE Main | CH-27 Chemistry Paper 2 15 Jan.docx | ||||
CH-05-Q17 | 81 gm mixture of MgCO_3(s) and NH_2COONH_4(s) is heated to
constant mass.
MgCO_3(s) [IMAGE] MgO(s) + CO_2(g)
NH_2COONH_4(s) [IMAGE] 2NH_3(g) + CO_2(g)
If vapour density of gaseous mixture evolved was found to
be$\frac{61}{4}$then find mole of MgCO_3 in theoriginal sample. | [
"images/image34.png",
"images/image35.png"
] | 50 | 60 | 75 | None of these | 1 | null | Let no. of moles of MgCO_3 = a
let no. of moles of NH_2COONH_4 = b
MgCO_3(s) [IMAGE] MgO(s) + CO_2(g) a - -
- - a
NH_2COONH_4(s) [IMAGE] 2NH_3(g) + CO_2(g)
b - -
- 2b b
a × 84 + b × 75 = 81.......(1)
$\frac{(a + b) + 4 + (2b)17}{a + b + 2b} = \frac{61}{4} \times 2$........(2)
$a\ = b = \frac{1}{2}$ MgCO_3 = 50 | [
"images/image36.png",
"images/image37.png"
] | Chemistry | Physical Chemistry | Some Basic Concepts of Chemistry | Tough | single_correct | true | JEE Main | CH-05 Chemistry Paper 10 October.docx |
CH-09-Q16 | ____ is a secondary pollutant. | [] | CO | CO_2 | PAN | NO_2 | 3 | null | Explanation: Secondary pollutants are not emitted directly from
any source; they form by reacting with molecules present in the
atmosphere. Some secondary pollutants are nitric acid, PAN etc. | [] | Chemistry | Inorganic Chemistry | Environmental Chemistry | Easy | single_correct | false | JEE Main | CH-09 Chemistry Paper 26 October.docx |
CH-18-Q13 | Choose the correct order of atomic radii of Fluorine and Neon
(in pm) out of the options given below | [] | 72, 160 | 160, 160 | 72, 72 | 160, 72 | 1 | null | Vanderwaal's radius is considered in case of neon, which
normally has a large value. Also, in neon, the valence shell is
completely filled with electrons. As a result, there are interelectronic
repulsions and thus electron cloud expands. So, atomic radii of neon is
greater than that of fluorine. | [] | Chemistry | Periodic table | Atomic and Ionic radius | Easy | single_correct | false | JEE Main | CH-18 Chemistry Paper 27 Nov. Third.docx |
CH-23-Q4 | (X) is the product of cross aldol condensation between
benzaldehyde (C6H5CHO) and acetone. What is its structure ? | [] | C6H5-CH=C-(CH3)2 | C6H5-CO-CH2-C=(CH3)2 | None of these | 1 | null | [
"images/image5.png"
] | Chemistry | Organic Chemistry | Carbonyl compound_Final | Moderate | single_correct | true | JEE Main | CH-23 Chemistry Paper 31 Dec. FST.docx | ||
CH-11-Q20 | [IMAGE] Standard entropy change for the above reaction is | [
"images/image30.png"
] | $60.3{JK}^{- 1}{mol}^{- 1}$ | $80.7\ JK^{- 1}{mol}^{- 1}$ | $- 70\ JK^{- 1}mol^{- 1}$ | $\ + 10.7\ JK^{- 1}{mol}^{- 1}$ | 2 | null | $80.7{JK}^{- 1}{mol}^{- 1}$ | [
"images/image31.png"
] | Chemistry | Physical Chemistry | Thermodynamics | Easy | single_correct | true | JEE Main | CH-11 Chemistry Paper-2 1Nov New Jee main.docx |
CH-21-Q6 | Which gas is obtained when iodoform is heated with Ag powder ?
tc s Ag pw.kZ ds lkFk xeZ rks
izkIr gksrh | [] | $CH_{4}$ | $C_{2}H_{4}$ | $C_{2}H_{6}$ | $C_{2}H_{2}$ | 4 | null | [
"images/image3.png"
] | Chemistry | Hydrocarbon | Hydrocarbon | Moderate | single_correct | true | JEE Main | CH-21 Chemistry Paper 19 Dec. Eng Hindi.docx | |
CH-07-Q6 | The compressibility factor for a gas is 0.9 at 273K and 9 atm.
Find the volume of $10^{–3}$ mol of gas at this T and P
$R = \left( \frac{0.0821atmL}{molK} \right)$ | [] | 2.24 L | 22.4 L | 2.24 m | 22.4 m | 3 | null | $Z = \frac{PV}{nRT}$
Or $0.9 = \frac{9 \times V}{10^{- 3} \times 0.0821 \times 273}$
Or $V = 2.24 \times 10^{- 3}L\text{ or }2.24mL$ | [] | Chemistry | Physical Chemistry | Gaseous state | Easy | single_correct | false | JEE Main | CH-07 Chemistry Paper 17 October.docx |
CH-10-Q16 | Which statement is true for cyclohexane | [] | It has two possible isomers | It has three conformations | Boat conformation is most stable | Chair and boat conformations differ in energy by | 4 | null | Chair and boat conformations differ in energy by | [
"images/image76.png",
"images/image77.png"
] | Chemistry | Organic Chemistry | Organic Chemistry | Easy | single_correct | true | JEE Main | CH-10 Chemistry Paper-1 30 Oct New Jee main.docx |
CH-24-Q10 | For the reaction$H_{2}(g) + I_{2}(g) \rightleftharpoons 2HI(g)$
K_c = 66.9 at 350ºC and Kc = 50.0 at 448ºC. The reaction has | [] | $\Delta$H = + ve | $\Delta$H = - ve | $\Delta$H = zero | $\Delta$H sign can not be determined | 2 | null | $H_{2}(g) + I_{2}(g) \rightleftharpoons 2HI(g)$
$log\frac{K_{2}}{K_{1}} = \frac{\Delta H}{2.303R}\left\lbrack \frac{1}{T_{1}} - \frac{1}{T_{2}} \right\rbrack$
$log\frac{50}{66.9} = \frac{\Delta H}{2.303R}\left\lbrack \frac{1}{623} - \frac{1}{721} \right\rbrack$
After calculation negative value of $\Delta$H is obtained. | [] | Chemistry | Physical Chemistry | Chemical Equilibrium | Moderate | single_correct | false | JEE Main | CH-24 Chemistry Paper 31 Dec..docx |
CH-13-Q7 | On heating KClO_3, we get | [] | Cl_2O | ClO_2 | ClO_3 | Cl_2 O_7 | 2 | null | 3KClO3 + 3H_2SO4 [IMAGE] 3KHSO_4 +
HClO_4 + 2ClO_2 + H_2O. | [
"images/image17.png"
] | Chemistry | Inorganic Chemistry | P-Block Element | Tough | single_correct | true | JEE Main | CH-13 Chemistry Paper 4 Nov..docx |
CH-11-Q15 | The work done in ergs for the reversible expansion of one mole
of an ideal gas from a volume of 10 litres to 20 litres at 25ºC is | [] | $2.303 \times 298 \times 0.082log2$ | $298 \times 10^{7} \times 8.31 \times 2.303log2$ | $2.303 \times 298 \times 0.082log0.5$ | $8.31 \times 10^{7} \times 298 - 2.303\log\log\ 0.5\ $ | 2 | null | $W = 2.303\frac{V_{2}}{V_{1}}\ $
$= 2.303 \times 1 \times 8.314 \times 10^{7} \times 298\log\log\ \frac{20}{10}\ $
$= 298 \times 10^{7} \times 8.314 \times 2.303log2$. | [] | Chemistry | Physical Chemistry | Thermodynamics | Easy | single_correct | false | JEE Main | CH-11 Chemistry Paper-2 1Nov New Jee main.docx |
CH-22-Q23 | The enthalpy of neutralization of a weak monoprotic acid (HA) in
1M solution with a strong base is -55.95 kJ/mol. If acid HA requires
1.4 complete ionization and enthalpy of
neutralization of the strong monobasic acid with a strong monoacidic
base is -57.3 kJ/mol. What is the ionization of the weak acid in
molar soluti... | [] | null | 3.57 | $HA - H^{+} + A^{-};\Delta_{r}H = 1.4kJ/mol$
$\Delta H_{neutalization\ } = \Delta H_{ionization\ } + \Delta_{r}H\ of\ \left( H^{+} + {OH}^{-} \rightarrow H_{2}O \right)$
$- 55.95 = \Delta H_{ionization\ } - 57.3$
$\Delta H_{ionization\ }\ for\ 1MHA = 1.35kJ/mol$ heat utilized by 1 M acid for ionization
$= \frac{1.35}{1... | [] | Chemistry | Physical Chemistry | Thermodynamics | Tough | numerical | false | JEE Main | CH-22 Chemistry Paper 19 Dec. Eng.docx | ||||
CH-23-Q11 | Softening of hard water is done using sodium aluminium silicate
(zeolite). This causes | [] | adsorption of Ca2+ and Mg2+ ions of hard water replacing Na+ ions. | adsorption of Ca2+ and Mg2+ ions of hard water replacing Al3+ ions | both (A) and (B) | none of these | 1 | null | Softening of hard water: Ion exchange resins used for
softening of hard water is based upon selective and competitive
adsorption of ions on resins.
${Na}_{2}Z + {Ca}^{+ 2} \longrightarrow CaZ + 2{Na}^{+}$
The organic polymers containing groups like -COOH, -SO3H and -NH2
etc. possess the property of selective adsorption... | [] | Chemistry | Physical Chemistry | Surface Chemistry | Moderate | single_correct | false | JEE Main | CH-23 Chemistry Paper 31 Dec. FST.docx |
CH-15-Q10 | At 373 K, a gaseous reaction A→ 2B + C is found to be of first
order. Starting with pure A, the total pressure at the end of 10 min was
176 mm of Hg and after a long time when A was completely dissociated, it
was 270 mm of Hg. The pressure of A at the end of 10 minutes was | [] | 94 mm of Hg | 47 mm of Hg | 43 mm of Hg | 90 mm of Hg | null | null | [IMAGE] Pressure of A after 10 minute = 90 - 43 = 47 | [
"images/image14.png",
"images/image15.png",
"images/image16.png",
"images/image17.png",
"images/image18.png",
"images/image19.png"
] | Chemistry | Chemical Kinetics | Experimental Method to calculate order and rate law of | Moderate | single_correct | true | JEE Main | CH-15 Chemistry Paper 11 Nov..docx |
CH-26-Q28 | The elevation in boiling point of a solution of 13.44 g of CuCl2
in 1kg of water using the following information, will be (Molecular
weight of CuCl2 = 134.4 and Kb = 0.52 K molal-1):
1kg ty esa 13.44 g CuCl2 DoFkukad fuEu lwpuk djrs gq,] gksxk dk v.kqHkkj (CuCl2 = 134.4 o Kb = 0.52 K
molal-1) | [] | null | 0.16 | $\Delta T_{0} = iK_{0}m$ i (vant Haff factor) of ¼okUVgkWQ
xq.kkad½ CuCI2 = 3
$\Delta T_{b} = 3 \times 0.52 \times \frac{13.44}{134.4 \times 1} = 0.156 = 0.16$ | [] | Chemistry | Physical Chemistry | Moderate | numerical | false | JEE Main | CH-26 Chemistry Paper 1 15 Jan.docx | |||||
CH-04-Q15 | Which of the following statement is correct | [] | Due to lanthanide contraction size of 3d series elements
[IMAGE] 4d series element.
(2) Due to lanthanide contraction size of 4d series elements
[IMAGE] 5d series element. | Due to lanthanide contraction size of 3d series elements < 5d
series element. | Due to lanthanide contraction size of 5d series element > 4d
series elements. | 2 | null | [] | Chemistry | Physical Chemistry | Periodic Table | Easy | single_correct | false | JEE Main | CH-04 Paper 02 Chemistry with Hindi 22-8-2020.docx | ||
CH-26-Q29 | When 20 g of naphthoic acid (C11H8O2) is dissolved in 50 g of
benzene (Kf = 1.72 K kg mol-1), a freezing point depression of 2 K is
observed. The van't Hoff factor (i) is:
tc 20 g us¶FkkWbd vEy (C11H8O2) dks 50 g csathu eas ?kksyk ( (Kf
= 1.72 K kg mol-1) rc fgekad esa voueu 2 K A okUVgkWQ
xq.kkad (i) gksxk | [] | null | 0.5 | $\Delta T_{f} = i \times K_{f} \times \ molality\ $(eksyyrk)
$\Rightarrow 2 = i \times 1.72 \times \frac{20}{172} \times \frac{1000}{50}$
$\Rightarrow 2 = 4i$
$\Rightarrow i = 1/2 = 0.5$ | [] | Chemistry | Physical Chemistry | Moderate | numerical | false | JEE Main | CH-26 Chemistry Paper 1 15 Jan.docx | |||||
CH-04-Q4 | Calculate the ratio of the energy of a photon of wavelength 3000
to that of a photon of wavelength respectively.
3000 - s - s | [] | null | 2 | [
"images/image5.png"
] | Chemistry | Physical Chemistry | Atomic Structure | Easy | numerical | true | JEE Main | CH-04 Paper 02 Chemistry with Hindi 22-8-2020.docx | |||||
CH-04-Q18 | In P_4 O_10 molecule
(A) There are 4 P-P bond
(B) There are 8 P-O bond
(C) The bond angle is 180°
(D) The phosphorus atom is sp^3 hybridised
P_4O_10 | [] | 4 P-P | 8 P-O | 180° (4) sp^3 | null | 4 | P_4O_10 molecule has no P-P bonds, 16 P-O bonds POP angle
is about 109°.28 & P atom is sp^3
P_4O_10 P-P 16P-O, POP
109°.28 P sp^3 | [] | Chemistry | Physical Chemistry | Chemical Bonding | Easy | numerical | false | JEE Main | CH-04 Paper 02 Chemistry with Hindi 22-8-2020.docx | |
CH-01-Q7 | When CrCl3 is reacts with excess NaOH solution then green solution
"A" is obatined?
[IMAGE] The oxidation number of chromium in the compound "C" is | [
"images/image13.png"
] | +10 | +6 | +3 | None of these | null | null | CrCl_3 + NaOH → Cr(OH)_3↓ (OH)_4]
Green ppt. Green solution (A)
Na[Cr(OH)_4] + H_2O_2 + NaOH [IMAGE] Na_2CrO_4 +
H_2O
(A) (B) yellow solution
Na_2CrO_4 + H_2O_2
[IMAGE] CrO_5 + NaOH
(C) blue solution | [
"images/image14.png",
"images/image15.png",
"images/image16.png"
] | Chemistry | single_correct | true | JEE Main | CH-01 Chemistry Paper 1.docx | |||
CH-28-Q14 | Green chemistry means such reactions which | [] | produce colour during reactions. | reduce the use and production of hazardous chemicals. | are related to the depletion of ozone layer. | study the reactions in plants. | 2 | null | Green chemistry involves such reactions which reduce the use
and production of hazardous or toxic chemical to reduce pollution from
environment. | [] | Chemistry | Organic Chemistry | Environmental Chemistry | Easy | single_correct | false | JEE Main | CH-28 Chemistry Paper FST 16 Jan.docx |
CH-11-Q7 | When SO_2 is passed through acidic solution of potassium
dichromate, then chromium sulphate is formed. Change in valency of
chromium is. | [] | +4 to +2 | +5 to +3 | +6 to +3 | +7 to 2 | 3 | null | [IMAGE] In this reaction chromium change from + 6 to +3 oxidation state. | [
"images/image1.png",
"images/image6.png"
] | Chemistry | Physical Chemistry | Redox Reaction | Moderate | single_correct | true | JEE Main | CH-11 Chemistry Paper-2 1Nov New Jee main.docx |
CH-01-Q25 | are INTEGER ANSWER TYPE Questions. (The answer of each of
the questions is 2 digits) | [] | null | null | [] | Chemistry | single_correct | false | JEE Main | CH-01 Chemistry Paper 1.docx | ||||||||
CH-15-Q18 | At CMC, the surfactant molecules | [] | Decomposes | Become completely soluble | Associate | Dissociate | 3 | null | Association occurs at CMC so colloid is formed. | [] | Chemistry | Surface Chemistry | Emulsion, Micelle and Gel | Easy | single_correct | false | JEE Main | CH-15 Chemistry Paper 11 Nov..docx |
CH-25-Q23 | The number of monochloro derivatives of isohexane is (Only
structural isomers)
vkblks gsDlsu | [] | null | 5 | [
"images/image98.png"
] | Chemistry | Organic Chemistry | Hydrocarbon | Easy | numerical | true | JEE Main | CH-25 Chemistry Paper 7 Jan.docx | |||||
CH-11-Q2 | $H_{2}O_{2}$ reduces $K_{4}Fe(CN)_{6}$ | [] | In neutral solution | In acidic solution | In non-polar solvent | In alkaline solution | 2 | null | When $H_{2}O_{2}$ reduces
with$K_{4}\left\lbrack Fe(CN)_{6} \right\rbrack$. It is present in
acidic solution.
$2K_{4}\left\lbrack Fe(CN)_{6} \right\rbrack + H_{2}SO_{4} + H_{2}O_{2} \rightarrow$
$2K_{3}\left\lbrack Fe(CN)_{6} \right\rbrack + K_{2}SO_{4} + 2H_{2}O$ | [] | Chemistry | Physical Chemistry | Redox Reaction | Moderate | single_correct | false | JEE Main | CH-11 Chemistry Paper-2 1Nov New Jee main.docx |
CH-11-Q25 | Number of structural isomers of C_4 H_10 O is | [] | null | 7 | C_4H_10O have 7 isomers out of which 4 are alcohols and
3 are ethers. | [
"images/image38.png",
"images/image39.png",
"images/image40.png",
"images/image41.png",
"images/image42.png",
"images/image43.png",
"images/image44.png"
] | Chemistry | Organic Chemistry | Organic Chemistry | Easy | numerical | true | JEE Main | CH-11 Chemistry Paper-2 1Nov New Jee main.docx | ||||
CH-06-Q19 | A atom forms an ion by the loss of three electrons. The ion has
an electronic configuration The symbol of the ion is | [] | Fe^3+ | Ni3^+ | Co^3+ | Mn^+3 | 3 | null | Ni: 4s^2 | [] | Chemistry | Physical Chemistry | Atomic Structure | Moderate | single_correct | false | JEE Main | CH-06 Chemistry Paper 14 October.docx |
CH-20-Q9 | A solution of urea contains 8.6 gm/liter (mol. wt. 60.0. It is
isotonic with a5 solution of a nonvolatile solute. The molecular weight
of the solute will be | [] | 348.9 | 34.89 | 3489 | 861.2 | 1 | null | For two non-electrolytic solution if isotonic, $C_{1} = C_{2}$
$\therefore\frac{8.6}{60 \times 1} = \frac{5 \times 1000}{m.wt. \times 100}\therefore m = 348.9$ | [] | Chemistry | Physical Chemistry | Easy | single_correct | false | JEE Main | CH-20 Chemistry Paper 12 Dec..docx | |
CH-23-Q1 | An alcohol (A), 0.22 g of this alcohol librates 56 ml of CH4 at
STP on reaction with CH3MgBr. Write the molecular weight of alcohol
which satisfies these conditions. | [] | 88 gm | 55 gm | 66 gm | 80 gm | 1 | null | $ROH + {CH}_{3}MgX \rightarrow {CH}_{4} + ROMgX$
Let molecular mass of alcohol is M
$\frac{56}{22400} = \frac{0.22}{M}$
$M = \frac{22400 \times 0.22}{56} = 88gm$ | [] | Chemistry | Organic Chemistry | Organic Reaction mechanisms-I | Moderate | single_correct | false | JEE Main | CH-23 Chemistry Paper 31 Dec. FST.docx |
CH-19-Q20 | Which of the following oxides is amphoteric in nature? | [] | N2O3 | P4O6 | Sb4O6 | Bi2O3 | 3 | null | Sb4O6 reacts with NaOH forming arsenite as well as HCl forming
SbCl | [] | Chemistry | P-block VA, VIA, VIIA elements | Oxides, Hydroxides, Peroxides, Oxyacids | Easy | single_correct | false | JEE Main | CH-19 Chemistry Paper 28 Nov. Fourth.docx |
CH-24-Q26 | For a solution of weak triprotic acid H_3A
[IMAGE],[A^3-] = 10^-17 M. Determine pH of
solution. Report your answer as if you find data insufficient. | [
"images/image36.png"
] | null | 4 | ${HA}^{2 -}\ \ \ \ \ \ \rightleftharpoons \ \ \ \ \ \ \ \ \ \ \ \ H^{+} + \ \ \ \ \ \ \ \ \ A^{3 -}$; K_a3 = 10^-13
t = eq; 10^-8 10^-17
$\frac{\left\lbrack H^{+} \right\rbrack \times 10^{- 17}}{10^{- 8}} = 10^{- 13}$
So, = 10^-4 M $\therefore$ pH = 4 | [] | Chemistry | Physical Chemistry | Ionic Equilibrium | Moderate | numerical | true | JEE Main | CH-24 Chemistry Paper 31 Dec..docx | ||||
CH-26-Q6 | Which of the following properties is not shown by NO ?
NO dkSu&lk fuEu xq.k iznf'kZr ugha djrk | [] | It is dimagnetic in gaseous state | It is a neutral oxide | It combines with oxygen to form nitrogen dioxide | It's bond order is 2.5
NO dkSu&lk fuEu xq.k iznf'kZr ugha djrk | 1 | null | NO is paramagnetic in gaseous state. | [] | Chemistry | Inorganic Chemistry | P-block nitrogen | Moderate | single_correct | false | JEE Main | CH-26 Chemistry Paper 1 15 Jan.docx |
CH-14-Q16 | [IMAGE] is oxidised to [IMAGE] using | [
"images/image70.png",
"images/image71.png"
] | Selenium dioxide | All of these | 3 | null | [
"images/image74.png"
] | Chemistry | Organic Chemistry | Aldehydes, Ketones & Carboxylic Acids | Moderate | single_correct | true | JEE Main | CH-14 Chemistry Paper 7 Nov..docx | |||
CH-10-Q2 | When sodium metal is dissolved in liquid ammonia, blue colour
solution is formed. The blue colour is due to | [] | 2 | null | vated [IMAGE] ions
(2) Solvated electrons
(3) Solvated [IMAGE] ions
(4) Solvated protons | [
"images/image3.png",
"images/image4.png",
"images/image5.png"
] | Chemistry | Physical Chemistry | Redox Reaction | Moderate | single_correct | true | JEE Main | CH-10 Chemistry Paper-1 30 Oct New Jee main.docx | ||||
CH-24-Q24 | If the equilibrium constant of the reaction
$2HI(g) \rightleftharpoons H_{2}(g) + I_{2}(g)$ is 0.25, find the
equilibrium constant of the reaction.
$\frac{1}{2}H_{2} + \frac{1}{2}I_{2} \rightleftharpoons HI(g)$ | [] | null | 04 | $H_{2}(g) + I_{2}(g) \rightleftharpoons 2HI(g)$
$K^{'} = \frac{1}{0.25} = 4$
For reaction
$\frac{1}{2}H_{2} + \frac{1}{2}I_{2} \rightleftharpoons HI(g)$
$K^{''} = \sqrt{4}$ | [] | Chemistry | Physical Chemistry | Chemical Equilibrium | Easy | numerical | false | JEE Main | CH-24 Chemistry Paper 31 Dec..docx | ||||
CH-26-Q23 | p-nitro toluene on further nitration gives | [] | 1 | null | [
"images/image40.png"
] | Chemistry | Organic Chemistry | Hydrocarbon | Moderate | single_correct | true | JEE Main | CH-26 Chemistry Paper 1 15 Jan.docx | |||||
CH-19-Q5 | The common features of the species N22-, O2 and NO- are | [] | bond order three and isoelectronic. | bond order two and isoelectronic. | bond order three but not isoelectronic. | bond order two but not isoelectronic. | 3 | null | $N_{2}^{2 -}:\sigma 1s^{2}\sigma^{\star}1s^{2}\ \sigma 2s^{2}\sigma^{\star}2s^{2}\ \pi 2p_{x\ }^{2}\ \pi 2p_{y}^{2}\ \sigma 2p_{z}^{2}\ \pi 2p_{x}^{1}\pi^{*}2p_{y}^{1}$
O2, NO-O2$= \frac{10 - 6}{2} = 2$ | [] | Chemistry | Chemical Bonding | MOT | Tough | single_correct | false | JEE Main | CH-19 Chemistry Paper 28 Nov. Fourth.docx |
CH-23-Q12 | Which of the following statements are correct in context of
point defects in a crystal ? | [] | AgCl has anion Frenkel defect and CaF2 has Schottky defects | AgCl has cation Frenkel defects and CaF2 has anion Frenkel defects | AgCl as well as CaF2 have anion Frenkel defects | AgCl as well as CaF2 has Schottky defects | 2 | null | Since Ag+ (cation) is smaller than Cl- (anion) & hence cation
is present in voids.
In CaF2, is smaller. | [] | Chemistry | Physical Chemistry | Easy | single_correct | false | JEE Main | CH-23 Chemistry Paper 31 Dec. FST.docx | |
CH-27-Q24 | Hydroloration of isobutylene followed by oxidative alkaline
hydrolysis gives
vkblks C;wfVyhu | [] | 1-butanol | 2-butanol | Isobutyl alcohol vkblks C;wfVy,Ydksgy | (CH_3)_3C-OH | 3 | null | [
"images/image32.png"
] | Chemistry | Organic Chemistry | Hydrocarbon | Moderate | single_correct | true | JEE Main | CH-27 Chemistry Paper 2 15 Jan.docx | |
CH-08-Q16 | Colour is imported to glass by mixing | [] | Synthetic dyes | Metal oxide | Oxides of non-metal | Coloured salt | 2 | null | Metal oxides of some salts are fused with glass to imported
colour of glass. | [] | Chemistry | Inorganic Chemistry | p-block elements | Moderate | single_correct | false | JEE Main | CH-08 Chemistry Paper 23 October.docx |
CH-24-Q4 | The value of Kp for the reaction,
$2H_{2}O(g) + 2{Cl}_{2}(g) \rightleftharpoons 4HCl(g) + O_{2}(g)$ is
0.03 atm at 427º C, when the partial pressure are expressed in
atmosphere then the value of KC for the same reaction is | [] | 5.23 × 10^-4 | 7.34 × 10^-4 | 3.2 × 10^-3 | 5.43 × 10^-5 | 1 | null | $2H_{2}O(g) + 2{Cl}_{2}(g) \rightleftharpoons 4HCl(g) + O_{2}(g)$
Kp = 0.03 T = 427oC = 700 K
Kp = KC(RT)1
$K_{C} = \frac{K_{P}}{RT} = \left\lbrack \frac{0.03}{0.082 \times 700} \right\rbrack$
KC = 5.23 × 10-4 | [] | Chemistry | Physical Chemistry | Chemical Equilibrium | Moderate | single_correct | false | JEE Main | CH-24 Chemistry Paper 31 Dec..docx |
CH-21-Q8 | How many of following are correctly matched for electrolytic
reducing in molten state.
Ore Reagent / Process Remark
(a) Al2O3 AlF3 and CaF2 added Decrease M.P.
(b) MgCl2 KCl, CaCl2 Increase conductivity
(c) NaCl AlCl3 Decrease M.P.
(d) AlF3 Haroult process Al form at cathode
(e) MgBr2 Dow process Br2 from at anode
(f) ... | [] | 5 (a, e, d, b, f) | 5 (a, b, d, e, f) | 5 (b, a, f, e, d) | 5 (a, b, c, e, f) | 2 | null | In NaCl metallurgy CaCl2 and KF are added. Carnellite firstly
converted into anhydrous MgCl2 then undergo process.
gy NaCl /kkrqdeZ eas CaCl2 o KF feyk;s tkrs gSaA dkusZykbV bl izfØ;k | [] | Chemistry | Inorganic Chemistry | Metallurgy | Tough | single_correct | false | JEE Main | CH-21 Chemistry Paper 19 Dec. Eng Hindi.docx |
CH-07-Q2 | Value of Vander Waal's constants a and b for a gas depends upon | [] | moles | volume | pressure | Gas taken | 4 | null | For different gases value of van der Waal's constants a and b is
different. | [] | Chemistry | Physical Chemistry | Gaseous state | Tough | single_correct | false | JEE Main | CH-07 Chemistry Paper 17 October.docx |
CH-06-Q24 | How many of the following molecules has 75 p-character ?
BeCl_2(g), BCl_3, SiCl_4, AsF_5, H_2S, PH_3 | [] | null | 2 | Sp^3Hybridized molecules are SiCl_4, H_2S | [] | Chemistry | Inorganic Chemistry | Chemical Bonding | Tough | numerical | false | JEE Main | CH-06 Chemistry Paper 14 October.docx | ||||
CH-23-Q17 | On dissolving moderate amount of sodium metal in liquid NH3 at
low temperature, which one of the following does not occur? | [] | Blue coloured solution is obtained | Na+ ions are formed in the solution | Liquid NH3 becomes good conductor of electricity | Liquid NH3 remains diamagnetic. | 4 | null | Na + (x + y) NH3 (moderate amount) → [Na(NH3)x]+ +
The blue colour solution is attributed to the solvated electrons.
The blue color solution is highly conducting due to the presence of
mainly solvated electrons and solvated Na+ ions.
The blue color solution is not diamagnetic but paramagnetic due to the
presence of sol... | [] | Chemistry | Inorganic Chemistry | S-block | Easy | single_correct | false | JEE Main | CH-23 Chemistry Paper 31 Dec. FST.docx |
CH-04-Q16 | Example of super octet molecule is | [] | SF6 | PCl5 | IF7 (4) All of these | null | null | In SF6, PCl5 and IF7 the valence shell has 12, 10 and 14
electrons. As all contain more than 8 electrons in their valence shell
they are example of super octet molecules.
gy SF6, PCl5 IF7 12, 10 14
8 | [] | Chemistry | Physical Chemistry | Chemical Bonding | Easy | single_correct | false | JEE Main | CH-04 Paper 02 Chemistry with Hindi 22-8-2020.docx | |
CH-21-Q19 | When white crystalline precipitate of magnesium ammonium
arsenate is treated with acidified silver nitrate solution, precipitate
of silver arsenate is formed. The colour of precipitate is | [] | Yellow | Brownish red | White | Brownish black
tc vkflZusV | 2 | null | $Mg\left( {NH}_{4} \right)_{2}{AsO}_{4} + 3{Ag}^{+} \longrightarrow {Ag}_{3}{AsO}_{4} \downarrow + {Mg}^{2 +} + {NH}_{4}^{+}$
(Brownish red)
gy
$Mg\left( {NH}_{4} \right)_{2}{AsO}_{4} + 3{Ag}^{+} \longrightarrow {Ag}_{3}{AsO}_{4} \downarrow + {Mg}^{2 +} + {NH}_{4}^{+}$
¼Hkwjk yky½ | [] | Chemistry | Salt Analysis | IIB Group | Moderate | single_correct | false | JEE Main | CH-21 Chemistry Paper 19 Dec. Eng Hindi.docx |
CH-05-Q7 | In which of the following delocalisation of anion is not
possible? | [] | 3 | null | Octet of nitrogen is complete. | [] | Chemistry | Organic Chemistry | Some Basic Principles and Techniques | Easy | single_correct | false | JEE Main | CH-05 Chemistry Paper 10 October.docx | ||||
CH-27-Q29 | The van't Hoff factor for 0.1 M Ba(NO3)2 solution is 2.74. The
degree of dissociation is | [] | null | 87 | Van't Hoff factor, $i = 1 + (n - 1)\alpha$
Here n = 3
So, $2.74 + 1 + (3 - 1)\alpha$
So, $\alpha = 0.87\ i.e.\ 87\%$
okWUV gkWQ esa] $i = 1 + (n - 1)\alpha$;gk¡ n = 3 | [] | Chemistry | Physical Chemistry | Moderate | numerical | false | JEE Main | CH-27 Chemistry Paper 2 15 Jan.docx | |||||
CH-11-Q18 | Internal energy is | [] | Partly potential and partly kinetic | Totally kinetic | Totally potential | None of these | 1 | null | The exact value of internal energy is not known as it includes
all type of energies of molecules constituting the given mass of matter
such as translational, vibrational, and rotational. The kinetic &
potential energy of the nuclei & electron within the individual
molecules and the manner in which the molecule are link... | [] | Chemistry | Physical Chemistry | Thermodynamics | Moderate | single_correct | false | JEE Main | CH-11 Chemistry Paper-2 1Nov New Jee main.docx |
CH-04-Q3 | Total number of H_2 molecules that can be obtained from all
hydrogen atoms of 10 formula units of CH_3COONH_4 is:
CH_3COONH_4 10
H2 | [] | 35 N_A | 140 | 140 N_A (4) 35 | 4 | null | 10 formula units of CH_3COONH_4 = 10 × 7 H-atoms =
[IMAGE] H_2 molecules = 35 H_2 molecules.
CH_3COONH_4 ds 10 lw=k bdkbZ;k = 10 × 7 H -ijek.kq =
[IMAGE] H_2 v.kq = 35 H_2 v.kq | [
"images/image4.png",
"images/image4.png"
] | Chemistry | Physical Chemistry | Mole Concept | Moderate | single_correct | true | JEE Main | CH-04 Paper 02 Chemistry with Hindi 22-8-2020.docx | |
CH-11-Q17 | $E^{0}$ of combustion of isobutylene is -X kJ mol^-1. The
value of $\Delta H^{\circ}$ is | [] | $= \Delta E^{0}$ | $> \Delta E^{\circ}$ | = 0 | $< \Delta E^{\circ}$ | 4 | null | $\left( {CH}_{3} \right)_{2}C = {CH}_{2}(g) + 6O_{2}(g) \rightarrow 4{CO}_{2}(g) + 4H_{2}O(l)$
$ng = 4 - 6 = - 2$ (i.e, negative)
We know that $H = \Delta E + \Delta ngRT$
$= \Delta E - (\Delta ng)RT(\because\Delta ng = - ve)$
$\therefore\Delta H < \Delta E$ | [] | Chemistry | Physical Chemistry | Thermodynamics | Moderate | single_correct | false | JEE Main | CH-11 Chemistry Paper-2 1Nov New Jee main.docx |
CH-14-Q11 | Which of the following compound expected to be colorless | [] | 3 | null | [IMAGE] As all the electrons are paired. It is expected to be colorless. | [
"images/image49.png",
"images/image51.png"
] | Chemistry | Inorganic Chemistry | D & F -Block Elements | Moderate | single_correct | true | JEE Main | CH-14 Chemistry Paper 7 Nov..docx | ||||
CH-16-Q18 | What can be the maximum percentage of available chlorine
possible in a given bleaching powder sample (Take formula of bleaching
powder as CaOCl2) ? | [] | 52.9 | 55.9 | 58 | 60 | 2 | null | The weight of available Cl2 from the given sample of
bleaching powder on reaction with dil acids or CO2 is called available
chlorine.
Max. of available of ${Cl}_{2} = \frac{71}{127} \times 100 = 55.9\%$ | [] | Chemistry | Equivalent Concept | Eudiometric/Eudiometric Titration, Calculation of Available | Moderate | single_correct | false | JEE Main | CH-16 Chemistry Paper 25 Nov. Fisrt.docx |
CH-25-Q11 | Match the reactants given in Column-I with the reagent given in
Column-II for the preparation of cyclobutane
Column-I Column-II
(A) [IMAGE] (p) $\Delta$, NH2 - NH2 /KOH
(D) Cl - CH2 - (CH2)2 - CH2 - Cl (s) Electrolysis, H_2 s cukus Wye - I ds
-II ft,A
dkWye - I dkWye - II
(A) [IMAGE] (p) $\Delta$, NH2 - NH2 /KOH
(D) Cl... | [
"images/image28.png",
"images/image29.png",
"images/image30.png",
"images/image28.png",
"images/image29.png",
"images/image30.png"
] | (A) - (p, r) (C) - (s); (D) - (q) | (A) - (p, q) (C) - (s); (D) - (q) | (A) - (p, r) (C) - (q); (D) - (s) | (A) - (q, r) (C) - (r); (D) - (p) | 1 | null | [
"images/image31.png",
"images/image32.png",
"images/image33.png",
"images/image34.png"
] | Chemistry | Organic Chemistry | Hydrocarbon | Tough | single_correct | true | JEE Main | CH-25 Chemistry Paper 7 Jan.docx | |
CH-01-Q19 | Asseration: A solution of surcose in water
is dextroratatory. But on hydrolysis in the presence of little
hydrochloric acid, it becomes levoratatory.
Reason: Surcose hydrolysis gives unequal amounts of glucose and
fructose. As a result
of this change in sign of rotation is observed. | [] | If both accretion and reason are true and reason is the correct
explanation of assertion | If both accretion and reason are true but reason is not the
correct explanation of assertion | If assertion is true but reason is false. | If both assertion and reason are false. | null | null | [
"images/image59.png"
] | Chemistry | single_correct | true | JEE Main | CH-01 Chemistry Paper 1.docx | ||||
CH-21-Q22 | In extraction of metal how many of the following ores
calcination process is involved.
(i) Dolomite (ii) Malachite (iii) Calcite (iv) Copperpyrities (v)
Sylvine
(vi) Cryolite (vii) Siderite (viii) Iron pyrite (ix) Argentite
fuEu es ls fdrus fuekZ.k es fuLrkiu izØe lfEefyr gksrk gS
(i) MksyksekbV (ii) esyssdkbV (iii) ds... | [] | null | 4 | (i) Dolomite CaCO3.MgCO3 (ii) Malachite CuCO3.Cu(OH)2
(iii) Calcite ZnCO3 (iv) Copperpyrities CuFeS2
(v) Sylvine KCl (vi) Cryolite Na3AlF6
(vii) Siderite FeCO3 (viii) Iron pyrite FeS2
(ix) Argentite Ag2S
So, answer is (i), (ii), (iii) and (vii)
gy (i) MksyksekbV CaCO3.MgCO3 (ii) esyssdkbV CuCO3.Cu(OH)2
(iii) dsylkbV Zn... | [] | Chemistry | Inorganic Chemistry | Metallurgy | Tough | numerical | false | JEE Main | CH-21 Chemistry Paper 19 Dec. Eng Hindi.docx | ||||
CH-15-Q3 | Finely divided catalyst has greater surface area and has greater
catalytic activity than the compact solid. If a total surface area of
6291456 cm2 is required for adsorption in a catalyzed gaseous reaction,
then how many splits should be made to a cube of exactly 1 cm in length
to achieve required surface area.
(Given:... | [] | 60 | 80 | 20 | 22 | 3 | null | Total surface area of eight cubes. | [] | Chemistry | Surface Chemistry | Adsorption | Easy | single_correct | false | JEE Main | CH-15 Chemistry Paper 11 Nov..docx |
CH-01-Q20 | has four choices | [] | , | , | , | out of which ONLY ONE is correct] | null | null | [] | Chemistry | single_correct | false | JEE Main | CH-01 Chemistry Paper 1.docx | ||||
CH-23-Q15 | Molecular formula C3H6O2 have two structures A & B. Structure A
releases CO2 gas with NaHCO3 but B does not. Compound B is fruity
smelling liquid. Write the structures & IUPAC name of A and B. | [] | null | null | CH3CH2COOH (Propanoic acid) → (A)
CH3COOCH3 (Methyl acetate) → (B) or HCOOC2H5 | [] | Chemistry | Organic Chemistry | Structure Identification & POC | Moderate | single_correct | false | JEE Main | CH-23 Chemistry Paper 31 Dec. FST.docx | ||||
CH-23-Q24 | A2(g) and B2(g) having partial pressures 60 mm of Hg & 42 mm of
Hg respectively, are present in a closed vessel. At equilibrium, partial
pressure of AB(g) is 28 mm of Hg. If all measurements are made under
similar condition, then calculate percentage of dissociation of AB (g).
(Round of answers to nearest integer). | [] | null | 72 | $A_{2}(g) + B_{2}(g) \rightleftharpoons 2AB(g)$
at t=0 60 42 0
at eq. (60-x) (42-x) (2x)
(Partial pressures)
$\Rightarrow 2x = 28 \Rightarrow x = 14$
$K_{p} = \frac{\left( P_{AB} \right)^{2}}{\left( P_{A_{2}} \right)\left( P_{B_{2}} \right)} = \frac{(28)^{2}}{(46)(28)} = \frac{14}{23}$
For $\Delta n_{g} = 0;K_{p} = K_{... | [] | Chemistry | Physical Chemistry | Chemical Equilibrium | Tough | numerical | false | JEE Main | CH-23 Chemistry Paper 31 Dec. FST.docx | ||||
CH-08-Q12 | On heating glucose with Fehling's solution we get a precipitate
whose colour is | [] | Yellow | Red | Black | White | 2 | null | Glucose + Fehling solution $\rightarrow$ Gluconic acid
+$\begin{matrix}
{Cu}_{2}O \\
(Red\ ppt)
\end{matrix}$ | [] | Chemistry | Organic Chemistry | Biomolecules | Moderate | single_correct | false | JEE Main | CH-08 Chemistry Paper 23 October.docx |
CH-17-Q4 | What is the relation between 3-Ethylpentane and 3-Methylhexane? | [] | Chain isomers
(B) Position isomers
(C) Functional isomers
(D) Relation | 1 | null | [IMAGE] Carbon skeleton is different in both compounds. | [
"images/image7.png",
"images/image8.png"
] | Chemistry | Isomerism | Structural Isomerism | Moderate | single_correct | true | JEE Main | CH-17 Chemistry Paper 26 Nov. Second.docx | |||
CH-25-Q27 | One mole of a symmetrical alkene on ozonolysis gives two moles
of an aldehyde having a molecular mass of 44 u. The alkene is n-butene.
Find n.,d lefer,sYdhu ds,d vkst+ksuh vi?kVu djus ij,d,sfYMgkbM ds
nks eksy izkIr gksrs gSa,sYdhu n A n | [] | null | 2 | $C_{n}H_{2n}O = 44$
$C_{n}H_{2n} = 44 - 16$
$C_{n}H_{2n} = 28$
$n = 2$
${CH}_{3} - CH = CH - {CH}_{3}\overset{O_{3}/Zn}{\rightarrow}{CH}_{3} - CH = O$ | [] | Chemistry | Organic Chemistry | Hydrocarbon | Moderate | numerical | false | JEE Main | CH-25 Chemistry Paper 7 Jan.docx | ||||
CH-28-Q18 | Select correct statement regarding silver extraction /
purification process. | [] | When the lead-silver alloy is rich in silver, lead is removed by
the cupellation process. | Lead is removed from argentiferous lead by Parke's process. | Zinc forms an alloy with lead, from which lead is separated by
distillation. | Zinc forms an alloy with silver, from which zinc is separated by
distillation. | 4 | null | (1) Cupellation is used when lead is present in traces.
(2) In argentiferous lead the silver is removed by Parke's process
because silver has higher solubility in molten zinc than lead.
(3) Silver has higher solubility in molten zinc than lead and thus
forms zinc-silver alloy from which zinc can be distilled off leavin... | [] | Chemistry | Inorganic Chemistry | Metallurgy | Moderate | single_correct | false | JEE Main | CH-28 Chemistry Paper FST 16 Jan.docx |
CH-25-Q2 | Which of the following alkanes can be synthesized by the Wurtz
reaction in good yield ?] | [] | (CH3)2CH - CH2 - CH (CH3)2] | (CH3)2CH - CH2 - CH2 - CH (CH3)2] | CH3 - CH2 - C(CH3)2CH2 - CH3] | (CH3)3C - CH2 - CH2 - CH3] | 2 | null | Symmetrical alkane with even no. of carbon atoms can be
prepared by Wurtz reaction.,Ydsu ftlesa le cZu ijek.kq gks oqVZ~l vfHkfØ tk ldrk | [] | Chemistry | Organic Chemistry | Hydrocarbon] | Moderate] | single_correct | false | JEE Main | CH-25 Chemistry Paper 7 Jan.docx |
CH-14-Q2 | On passing 3 ampere of electricity for 50 minutes, 1.8 gram metal
deposits. The equivalent mass of metal is | [] | 20.5 | 25.8 | 19.3 | 30.7 | 3 | null | [
"images/image7.png",
"images/image8.png"
] | Chemistry | Physical Chemistry | Electrochemistry | Moderate | single_correct | true | JEE Main | CH-14 Chemistry Paper 7 Nov..docx | |
CH-06-Q4 | Which of the following are planar ? | [] | XeF_2, SF_4,PCl_5 | PCl_5, SF_6, IF_7 | H_2O, XeF_4, ClF_3 | ${SF}_{4},\ {ClF}_{3},l_{3}^{-}$ | 3 | null | Planar molecules:
${XeF}_{2},{ClF}_{3},H_{2}O,I_{3}^{-},{XeF}_{4}$.
SF_4- See - Saw shape
PCl_5- Trigonal bipyramidal
SF_6- Square bipyramidal
IF_7- Pentagonal bipyramidal | [] | Chemistry | Inorganic Chemistry | Chemical Bonding | Moderate | single_correct | false | JEE Main | CH-06 Chemistry Paper 14 October.docx |
CH-22-Q16 | Which of the following polymers is synthesized using a
freeradical polymerization technique ? | [] | Teflon | Terylene | Melamine polymer | Nylon 6,6 | 1 | null | The free radical polymerization of
tetrafluoroethylenesynthesizes Teflon. This polymerization is a type of
vinylpolymerization and proceeds via free radical mechanism.
[IMAGE] Thus, out of all the given polymers, Teflon is the only polymerwhich is
synthesized using free radical polymerization. | [
"images/image18.png"
] | Chemistry | Organic Chemistry | Polymer | Moderate | single_correct | true | JEE Main | CH-22 Chemistry Paper 19 Dec. Eng.docx |
CH-09-Q4 | Which of the following is not a reducing agent? | [] | NaNO_2 | NaNO_3 | HI | SnCl_3 | 2 | null | NaNO_2, SnCl_3 and HI have reducing and oxidizing properties
but NaNO_3 have only oxidizing property. | [] | Chemistry | Physical Chemistry | Redox Reaction | Easy | single_correct | false | JEE Main | CH-09 Chemistry Paper 26 October.docx |
CH-22-Q9 | The transition metal ions responsible for color in ruby and
emerald are, respectively | [] | ${Cr}^{3 +}\ and\ {Co}^{3 +}$ | ${Co}^{3 +}\ and\ {Cr}^{3 +}$ | ${Co}^{3 +}\ and\ {Co}^{3}$ | ${Cr}^{3 +}\ and\ {Cr}^{3 +}$ | 4 | null | The transition metal ions -4500 J is responsible for color in
ruby and emerald.
Aluminum oxide is also known as ruby. It consists of chromium ions.
Each aluminum and chromium ion is surrounded by six oxide ions in an
octahedral manner. Emerald is composed of beryllium aluminum silicate
in which chromium ions is surroun... | [] | Chemistry | Inorganic Chemistry | D and F block element | Moderate | single_correct | false | JEE Main | CH-22 Chemistry Paper 19 Dec. Eng.docx |
CH-26-Q10 | Concentrated hydrochloric acid when kept in open air sometimes
produces a cloud of white fumes. This is due to | [] | strong affinity of HCl gas for moisture in air results in forming
of droplets of liquid solution which appears like a cloudy smoke. | strong affinity for water, conc. HCl pulls moisture of air
towards self. The moisture forms droplets of water and hence the
cloud. | conc. HCl emits strongly smelling HCl gas all the time. | oxygen in air reacts with emitted HCl gas to form a cloud of
chlorine gas.
lkUnz gkbMªksDyksfjd vEy dks tc
lQsn vHkz izkIr gksrs gSaA;g bl dkj.k gksrk | 4 | null | 4HCI + O_2 → 2CI_2 + 2H_2O white fumes cloud ¼lQsn /kqze
vHkz ¼ckny½½A | [] | Chemistry | Inorganic Chemistry | P-block Halogen | Moderate | single_correct | false | JEE Main | CH-26 Chemistry Paper 1 15 Jan.docx |
CH-01-Q3 | From the data provided, calculate the bond energy of a C -- H bond.
DH_f of C_2H_2(g) = 225 kJ/mole, DHsublimation of Cgraphite = 705 kJ
DH_f of H(g) = 165 kJ, C C bond energy = 815 kJ. | [] | 350 kJ | 500 kJ | 242.5 kJ | 150 kJ | null | null | [
"images/image11.png"
] | Chemistry | single_correct | true | JEE Main | CH-01 Chemistry Paper 1.docx | ||||
CH-27-Q11 | In which of the following reactions, increase in the volume at
constant temperature don't effect the number of moles of at equilibrium:
ij eksyks | [] | 2NH3[IMAGE] N2 + 3H2 | C (g) + (1/2) O2 (g)[IMAGE] CO (g) | H2 (g) + O2 (g)[IMAGE] H2O2 (g) | None of these. bu sbZ ugha | 4 | null | If in the reaction the ratio of number of moles of reactants to
products in same i.e., 1: 1, then change in volume will not alter the
number of moles.
leku gksrk rc vk;ru ifjorZu | [] | Chemistry | Physical Chemistry | Chemical Equilibrium | Moderate | single_correct | false | JEE Main | CH-27 Chemistry Paper 2 15 Jan.docx |
CH-08-Q8 | Glucose gives silver mirror with Tollen's reagent. It shows the
presence of | [] | An acidic group | An alcoholic group | A ketonic group | An aldehydic group | null | null | Glucose + Tollen's reagent $\rightarrow$ | [] | Chemistry | Organic Chemistry | Biomolecules | Easy | single_correct | false | JEE Main | CH-08 Chemistry Paper 23 October.docx |
CH-19-Q17 | Nitrogen is best obtained by the thermal decomposition of which
one of the following | [] | NH4Cl | NH4NO3 | AgNO3 | NH4NO2 | 4 | null | NH4Cl gives NH3, NH4NO3 gives N2O and AgNO3 gives NO | [] | Chemistry | P-block VA, VIA, VIIA elements | General facts about elements | Moderate | single_correct | false | JEE Main | CH-19 Chemistry Paper 28 Nov. Fourth.docx |
CH-27-Q26 | In a saturated solution of Ag2SO4, silver ion concentration is 3
× 10-2 M. Its solubility product is ____ × 10-5: Assume no
reaction of cation/anion.
foys;rk xq.kuQy ____ × 10-5 | [] | null | 1.35 | Ag2CO3[IMAGE] 2Ag+ + CO32-
2s s
Here = 2 s = 2 × 10-4 M $\Rightarrow$ s = 1 × 10-4 M
$\therefore$ Ksp = 4s3 = 4(3 × 10-2)3 = 1.35 × 10-5 | [
"images/image35.png"
] | Chemistry | Physical Chemistry | Ionic Equilibrium | Moderate | numerical | true | JEE Main | CH-27 Chemistry Paper 2 15 Jan.docx | ||||
CH-28-Q39 | How many N atom are present in final product
[IMAGE] Final product. | [
"images/image31.png"
] | null | 0 | [
"images/image32.png",
"images/image33.png"
] | Chemistry | Organic Chemistry | Aromatic Compounds | Tough | numerical | true | JEE Main | CH-28 Chemistry Paper FST 16 Jan.docx |
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