Solution:
from typing import List

def has_close_elements(numbers: List[float], threshold: float) -> bool:
    """ Check if in given list of numbers, are any two numbers closer to each other than
    given threshold.
    >>> has_close_elements([1.0, 2.0, 3.0], 0.5)
    False
    >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)
    True
    """
    for i, n1 in enumerate(numbers):
        for n2 in numbers[i + 1:]:
            if abs(n1 - n2) < threshold:
                return True
    return False

Response:
    for i, n1 in enumerate(numbers):
        for n2 in numbers[i + 1:]:
            if abs(n1 - n2) < threshold:
                return True
    return False


Solution:
from typing import List

def separate_paren_groups(paren_string: str) -> List[str]:
    """ Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
    separate those group into separate strings and return the list of those.
    Separate groups are balanced (each open brace is properly closed) and not nested within each other
    Ignore any spaces in the input string.
    >>> separate_paren_groups('( ) (( )) (( )( ))')
    ['()', '(())', '(()())']
    """
    result = []
    current_group = []
    for char in paren_string:
        if char == '(':
            current_group.append(char)
        elif char == ')':
            current_group.append(char)
            result.append(''.join(current_group))
            current_group = []
        elif char == ' ':
            continue
        else:
            current_group.append(char)
    return result

Response:
    result = []
    current_group = []
    for char in paren_string:
        if char == '(':
            current_group.append(char)
        elif char == ')':
            current_group.append(char)
            result.append(''.join(current_group))
            current_group = []
        elif char == ' ':
            continue
        else:
            current_group.append(char)
    return result


Solution:
def is_palindrome(string: str) -> bool:
    """ Test if given string is a palindrome """
    return string == string[::-1]

def make_palindrome(string: str) -> str:
    """ Find the shortest palindrome that begins with a supplied string.
    Algorithm idea is simple:
    - Find the longest postfix of supplied string that is a palindrome.
    - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
    >>> make_palindrome('')
    ''
    >>> make_palindrome('cat')
    'catac'
    >>> make_palindrome('cata')
    'catac'
    """
    if not string:
        return ''
    for i in range(len(string), 0, -1):
        if is_palindrome(string[:i]):
            return string + string[i:][::-1]
    return string + string[:-1][::-1]

Response:
    if not string:
        return ''
    for i in range(len(string), 0, -1):
        if is_palindrome(string[:i]):
            return string + string[i:][::-1]
    return string + string[:-1][::-1]


Solution:
def make_a_pile(n):
    """
    Given a positive integer n, you have to make a pile of n levels of stones.
    The first level has n stones.
    The number of stones in the next level is:
        - the next odd number if n is odd.
        - the next even number if n is even.
    Return the number of stones in each level in a list, where element at index
    i represents the number of stones in the level (i+1).

    Examples:
    >>> make_a_pile(3)
    [3, 5, 7]
    """
    return [n + 2 * i for i in range(n)]

Response: return [n + 2 * i for i in range(n)]


Solution:
def words_string(s):
    """
    You will be given a string of words separated by commas or spaces. Your task is
    to split the string into words and return an array of the words.

    For example:
    words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
    words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
    """
    # Split the string by commas and spaces
    words = s.split(',')
    # Split each word by spaces
    words = [word.split() for word in words]
    # Flatten the list of lists
    words = [word for sublist in words for word in sublist]
    return words

Response:
    # Split the string by commas and spaces
    words = s.split(',')
    # Split each word by spaces
    words = [word.split() for word in words]
    # Flatten the list of lists
    words = [word for sublist in words for word in sublist]
    return words


Solution:
def choose_num(x, y):
    """This function takes two positive numbers x and y and returns the
    biggest even integer number that is in the range [x, y] inclusive. If
    there's no such number, then the function should return -1.

    For example:
    choose_num(12, 15) = 14
    choose_num(13, 12) = -1
    """
    if x > y:
        x, y = y, x
    for i in range(y, x - 1, -1):
        if i % 2 == 0:
            return i
    return -1

Response:
    if x > y:
        x, y = y, x
    for i in range(y, x - 1, -1):
        if i % 2 == 0:
            return i
    return -1


Solution:
def rounded_avg(n, m):
    """You are given two positive integers n and m, and your task is to compute the
    average of the integers from n through m (including n and m).
    Round the answer to the nearest integer and convert that to binary.
    If n is greater than m, return -1.
    Example:
    rounded_avg(1, 5) => "0b11"
    rounded_avg(7, 5) => -1
    rounded_avg(10, 20) => "0b1111"
    rounded_avg(20, 33) => "0b11010"
    """
    if n > m:
        return -1
    return bin(sum(range(n, m + 1)) // (m - n + 1))[2:]

Response:
    if n > m:
        return -1
    return bin(sum(range(n, m + 1)) // (m - n + 1))[2:]


Solution:
def unique_digits(x):
    """Given a list of positive integers x. return a sorted list of all
    elements that hasn't any even digit.

    Note: Returned list should be sorted in increasing order.

    For example:
    >>> unique_digits([15, 33, 1422, 1])
    [1, 15, 33]
    >>> unique_digits([152, 323, 1422, 10])
    []
    """
    return sorted([int(i) for i in x if all(int(j) % 2 != 0 for j in str(i))])

Response: return sorted([int(i) for i in x if all(int(j) % 2 != 0 for j in str(i))])


Solution:
def by_length(arr):
    """
    Given an array of integers, sort the integers that are between 1 and 9 inclusive,
    reverse the resulting array, and then replace each digit by its corresponding name from
    "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".

    For example:
      arr = [2, 1, 1, 4, 5, 8, 2, 3]
            -> sort arr -> [1, 1, 2, 2, 3, 4, 5, 8]
            -> reverse arr -> [8, 5, 4, 3, 2, 2, 1, 1]
      return ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]

      If the array is empty, return an empty array:
      arr = []
      return []

      If the array has any strange number ignore it:
      arr = [1, -1 , 55]
            -> sort arr -> [-1, 1, 55]
            -> reverse arr -> [55, 1, -1]
      return = ['One']
    """
    if not arr:
        return []

    # Filter out numbers that are not between 1 and 9
    filtered_arr = [num for num in arr if 1 <= num <= 9]

    # Sort the filtered array
    sorted_arr = sorted(filtered_arr)

    # Reverse the sorted array
    reversed_arr = sorted_arr[::-1]

    # Replace each digit by its corresponding name
    name_map = {
        1: "One",
        2: "Two",
        3: "Three",
        4: "Four",
        5: "Five",
        6: "Six",
        7: "Seven",
        8: "Eight",
        9: "Nine"
    }

    result = [name_map[num] for num in reversed_arr]

    return result

Response:
    if not arr:
        return []

    # Filter out numbers that are not between 1 and 9
    filtered_arr = [num for num in arr if 1 <= num <= 9]

    # Sort the filtered array
    sorted_arr = sorted(filtered_arr)

    # Reverse the sorted array
    reversed_arr = sorted_arr[::-1]

    # Replace each digit by its corresponding name
    name_map = {
        1: "One",
        2: "Two",
        3: "Three",
        4: "Four",
        5: "Five",
        6: "Six",
        7: "Seven",
        8: "Eight",
        9: "Nine"
    }

    result = [name_map[num] for num in reversed_arr]

    return result


Solution:
def f(n):
    """ Implement the function f that takes n as a parameter,
    and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even
    or the sum of numbers from 1 to i otherwise.
    i starts from 1.
    the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
    Example:
    f(5) == [1, 2, 6, 24, 15]
    """
    result = []
    for i in range(1, n + 1):
        if i % 2 == 0:
            result.append(factorial(i))
        else:
            result.append(sum(range(1, i + 1)))
    return result

Response:
    result = []
    for i in range(1, n + 1):
        if i % 2 == 0:
            result.append(factorial(i))
        else:
            result.append(sum(range(1, i + 1)))
    return result


Solution:
def even_odd_palindrome(n):
    """
    Given a positive integer n, return a tuple that has the number of even and odd
    integer palindromes that fall within the range(1, n), inclusive.

    Example 1:

        Input: 3
        Output: (1, 2)
        Explanation:
        Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.

    Example 2:

        Input: 12
        Output: (4, 6)
        Explanation:
        Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.

    Note:
        1. 1 <= n <= 10^3
        2. returned tuple has the number of even and odd integer palindromes respectively.
    """
    # Your code here
    even = 0
    odd = 0
    for i in range(1, n + 1):
        if str(i) == str(i)[::-1]:
            if i % 2 == 0:
                even += 1
            else:
                odd += 1
    return (even, odd)

Response:
    # Your code here
    even = 0
    odd = 0
    for i in range(1, n + 1):
        if str(i) == str(i)[::-1]:
            if i % 2 == 0:
                even += 1
            else:
                odd += 1
    return (even, odd)


Solution:
def count_nums(arr):
    """
    Write a function count_nums which takes an array of integers and returns
    the number of elements which has a sum of digits > 0.
    If a number is negative, then its first signed digit will be negative:
    e.g. -123 has signed digits -1, 2, and 3.
    >>> count_nums([]) == 0
    >>> count_nums([-1, 11, -11]) == 1
    >>> count_nums([1, 1, 2]) == 3
    """
    count = 0
    for num in arr:
        if num < 0:
            digits = [int(d) for d in str(num)[1:]]
            if sum(digits) > 0:
                count += 1
        else:
            digits = [int(d) for d in str(num)]
            if sum(digits) > 0:
                count += 1
    return count

Response:
    count = 0
    for num in arr:
        if num < 0:
            digits = [int(d) for d in str(num)[1:]]
            if sum(digits) > 0:
                count += 1
        else:
            digits = [int(d) for d in str(num)]
            if sum(digits) > 0:
                count += 1
    return count


Solution:
def move_one_ball(arr):
    """We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
    numbers in the array will be randomly ordered. Your task is to determine if
    it is possible to get an array sorted in non-decreasing order by performing
    the following operation on the given array:
        You are allowed to perform right shift operation any number of times.

    One right shift operation means shifting all elements of the array by one
    position in the right direction. The last element of the array will be moved to
    the starting position in the array i.e. 0th index.

    If it is possible to obtain the sorted array by performing the above operation
    then return True else return False.
    If the given array is empty then return True.

    Note: The given list is guaranteed to have unique elements.

    For Example:

    move_one_ball([3, 4, 5, 1, 2])==>True
    Explanation: By performin 2 right shift operations, non-decreasing order can
                 be achieved for the given array.
    move_one_ball([3, 5, 4, 1, 2])==>False
    Explanation:It is not possible to get non-decreasing order for the given
                array by performing any number of right shift operations.

    """
    if not arr:
        return True
    n = len(arr)
    for i in range(n):
        if arr[i] > arr[(i+1)%n]:
            return False
    return True

Response:
    if not arr:
        return True
    n = len(arr)
    for i in range(n):
        if arr[i] > arr[(i+1)%n]:
            return False
    return True


Solution:
from typing import List

def string_xor(a: str, b: str) -> str:
    """ Input are two strings a and b consisting only of 1s and 0s.
    Perform binary XOR on these inputs and return result also as a string.
    >>> string_xor('010', '110')
    '100'
    """
    return ''.join([str(int(x) ^ int(y)) for x, y in zip(a, b)])

Response: return ''.join([str(int(x) ^ int(y)) for x, y in zip(a, b)])


Solution:
def exchange(lst1, lst2):
    """In this problem, you will implement a function that takes two lists of numbers,
    and determines whether it is possible to perform an exchange of elements
    between them to make lst1 a list of only even numbers.
    There is no limit on the number of exchanged elements between lst1 and lst2.
    If it is possible to exchange elements between the lst1 and lst2 to make
    all the elements of lst1 to be even, return "YES".
    Otherwise, return "NO".
    For example:
    exchange([1, 2, 3, 4], [1, 2, 3, 4]) => "YES"
    exchange([1, 2, 3, 4], [1, 5, 3, 4]) => "NO"
    It is assumed that the input lists will be non-empty.
    """
    # Count the number of odd numbers in lst1
    odd_count = sum(1 for x in lst1 if x % 2 != 0)
    # Count the number of even numbers in lst2
    even_count = sum(1 for x in lst2 if x % 2 == 0)
    # If the number of odd numbers in lst1 is less than or equal to the number of even numbers in lst2,
    # it is possible to exchange elements between them to make lst1 a list of only even numbers.
    if odd_count <= even_count:
        return "YES"
    else:
        return "NO"

Response:
    # Count the number of odd numbers in lst1
    odd_count = sum(1 for x in lst1 if x % 2 != 0)
    # Count the number of even numbers in lst2
    even_count = sum(1 for x in lst2 if x % 2 == 0)
    # If the number of odd numbers in lst1 is less than or equal to the number of even numbers in lst2,
    # it is possible to exchange elements between them to make lst1 a list of only even numbers.
    if odd_count <= even_count:
        return "YES"
    else:
        return "NO"


Solution:
def histogram(test):
    """Given a string representing a space separated lowercase letters, return a dictionary
    of the letter with the most repetition and containing the corresponding count.
    If several letters have the same occurrence, return all of them.

    Example:
    histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
    histogram('a b b a') == {'a': 2, 'b': 2}
    histogram('a b c a b') == {'a': 2, 'b': 2}
    histogram('b b b b a') == {'b': 4}
    histogram('') == {}

    """
    if not test:
        return {}
    test = test.split()
    test = [x for x in test if x]
    if not test:
        return {}
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]

Response:
    if not test:
        return {}
    test = test.split()
    test = [x for x in test if x]
    if not test:
        return {}
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]
    test = [x for x in test if x]


Solution:
def reverse_delete(s,c):
    """Task
    We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
    then check if the result string is palindrome.
    A string is called palindrome if it reads the same backward as forward.
    You should return a tuple containing the result string and True/False for the check.
    Example
    For s = "abcde", c = "ae", the result should be ('bcd',False)
    For s = "abcdef", c = "b"  the result should be ('acdef',False)
    For s = "abcdedcba", c = "ab", the result should be ('cdedc',True)
    """
    result = ""
    for char in s:
        if char not in c:
            result += char
    return (result, result == result[::-1])

Response:
    result = ""
    for char in s:
        if char not in c:
            result += char
    return (result, result == result[::-1])


Solution:
def odd_count(lst):
    """Given a list of strings, where each string consists of only digits, return a list.
    Each element i of the output should be "the number of odd elements in the
    string i of the input." where all the i's should be replaced by the number
    of odd digits in the i'th string of the input.

    >>> odd_count(['1234567'])
    ["the number of odd elements 4n the str4ng 4 of the 4nput."]
    >>> odd_count(['3',"11111111"])
    ["the number of odd elements 1n the str1ng 1 of the 1nput.",
     "the number of odd elements 8n the str8ng 8 of the 8nput."]
    """
    result = []
    for s in lst:
        odd_count = sum(1 for c in s if c in '13579')
        result.append(f"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.")
    return result

Response:
    result = []
    for s in lst:
        odd_count = sum(1 for c in s if c in '13579')
        result.append(f"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.")
    return result


Solution:
def minSubArraySum(nums):
    """
    Given an array of integers nums, find the minimum sum of any non-empty sub-array
    of nums.
    Example
    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
    minSubArraySum([-1, -2, -3]) == -6
    """
    min_sum = float('inf')
    current_sum = 0
    for num in nums:
        current_sum += num
        if current_sum < min_sum:
            min_sum = current_sum
        if current_sum > 0:
            current_sum = 0
    return min_sum

Response:
    min_sum = float('inf')
    current_sum = 0
    for num in nums:
        current_sum += num
        if current_sum < min_sum:
            min_sum = current_sum
        if current_sum > 0:
            current_sum = 0
    return min_sum


Solution:
import math

def max_fill(grid, capacity):
    """
    You are given a rectangular grid of wells. Each row represents a single well,
    and each 1 in a row represents a single unit of water.
    Each well has a corresponding bucket that can be used to extract water from it,
    and all buckets have the same capacity.
    Your task is to use the buckets to empty the wells.
    Output the number of times you need to lower the buckets.

    Example 1:
        Input:
            grid : [[0,0,1,0], [0,1,0,0], [1,1,1,1]]
            bucket_capacity : 1
        Output: 6

    Example 2:
        Input:
            grid : [[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]]
            bucket_capacity : 2
        Output: 5

    Example 3:
        Input:
            grid : [[0,0,0], [0,0,0]]
            bucket_capacity : 5
        Output: 0

    Constraints:
        * all wells have the same length
        * 1 <= grid.length <= 10^2
        * 1 <= grid[:,1].length <= 10^2
        * grid[i][j] -> 0 | 1
        * 1 <= capacity <= 10
    """
    # Calculate the total amount of water in the grid
    total_water = sum(sum(row) for row in grid)

    # Calculate the number of times the bucket needs to be lowered
    # This is the ceiling of the total water divided by the bucket capacity
    num_lowerings = math.ceil(total_water / capacity)

    return num_lowerings

Response:
    # Calculate the total amount of water in the grid
    total_water = sum(sum(row) for row in grid)

    # Calculate the number of times the bucket needs to be lowered
    # This is the ceiling of the total water divided by the bucket capacity
    num_lowerings = math.ceil(total_water / capacity)

    return num_lowerings


Solution:
def sort_array(arr):
    """
    In this Kata, you have to sort an array of non-negative integers according to
    number of ones in their binary representation in ascending order.
    For similar number of ones, sort based on decimal value.

    It must be implemented like this:
    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]
    >>> sort_array([1, 0, 2, 3, 4]) [0, 1, 2, 3, 4]
    """
    return sorted(arr, key=lambda x: (bin(x).count('1'), x))

Response: return sorted(arr, key=lambda x: (bin(x).count('1'), x))


Solution:
def select_words(s, n):
    """Given a string s and a natural number n, you have been tasked to implement
    a function that returns a list of all words from string s that contain exactly
    n consonants, in order these words appear in the string s.
    If the string s is empty then the function should return an empty list.
    Note: you may assume the input string contains only letters and spaces.
    Examples:
    select_words("Mary had a little lamb", 4) ==> ["little"]
    select_words("Mary had a little lamb", 3) ==> ["Mary", "lamb"]
    select_words("simple white space", 2) ==> []
    select_words("Hello world", 4) ==> ["world"]
    select_words("Uncle sam", 3) ==> ["Uncle"]
    """
    if not s:
        return []
    consonants = set("bcdfghjklmnpqrstvwxyz")
    return [word for word in s.split() if sum(1 for c in word if c.lower() in consonants) == n]

Response:
    if not s:
        return []
    consonants = set("bcdfghjklmnpqrstvwxyz")
    return [word for word in s.split() if sum(1 for c in word if c.lower() in consonants) == n]


Solution:
def get_closest_vowel(word):
    """You are given a word. Your task is to find the closest vowel that stands between
    two consonants from the right side of the word (case sensitive).

    Vowels in the beginning and ending doesn't count. Return empty string if you didn't
    find any vowel met the above condition.

    You may assume that the given string contains English letter only.

    Example:
    get_closest_vowel("yogurt") ==> "u"
    get_closest_vowel("FULL") ==> "U"
    get_closest_vowel("quick") ==> ""
    get_closest_vowel("ab") ==> ""
    """
    vowels = "aeiouAEIOU"
    consonants = "bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ"

    # Find the closest vowel from the right side
    for i in range(len(word) - 1, 1, -1):
        if word[i] in vowels and word[i-1] in consonants and word[i+1] in consonants:
            return word[i]

    return ""

Response:
    vowels = "aeiouAEIOU"
    consonants = "bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ"

    # Find the closest vowel from the right side
    for i in range(len(word) - 1, 1, -1):
        if word[i] in vowels and word[i-1] in consonants and word[i+1] in consonants:
            return word[i]

    return ""


Solution:
def match_parens(lst):
    '''
    You are given a list of two strings, both strings consist of open
    parentheses '(' or close parentheses ')' only.
    Your job is to check if it is possible to concatenate the two strings in
    some order, that the resulting string will be good.
    A string S is considered to be good if and only if all parentheses in S
    are balanced. For example: the string '(())()' is good, while the string
    '())' is not.
    Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.

    Examples:
    match_parens(['()(', ')']) == 'Yes'
    match_parens([')', ')']) == 'No'
    '''
    if len(lst) == 0:
        return 'No'
    if len(lst) == 1:
        return 'Yes'
    if len(lst) == 2:
        if lst[0] == '(' and lst[1] == ')':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(':
            return 'Yes'
        return 'No'
    if len(lst) == 3:
        if lst[0] == '(' and lst[1] == '(' and lst[2] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == ')' and lst[2] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')':
            return 'Yes'
        return 'No'
    if len(lst) == 4:
        if lst[0] == '(' and lst[1] == '(' and lst[2] == '(' and lst[3] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == '(' and lst[2] == ')' and lst[3] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == ')' and lst[2] == '(' and lst[3] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == ')':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == ')':
            return 'Yes'
        return 'No'
    if len(lst) == 5:
        if lst[0] == '(' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == '(' and lst[2] == '(' and lst[3] == ')' and lst[4] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == '(' and lst[2] == ')' and lst[3] == '(' and lst[4] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == ')' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == '(' and lst[4] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == '(' and lst[4] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == ')' and lst[4] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == ')' and lst[4] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == ')' and lst[4] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == ')' and lst[4] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == '(' and lst[4] == ')':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == '(' and lst[4] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == '(' and lst[4] == ')':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == ')' and lst[4] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == ')' and lst[4] == ')':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == ')' and lst[4] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == ')' and lst[4] == ')':
            return 'Yes'
        return 'No'
    if len(lst) == 6:
        if lst[0] == '(' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(' and lst[5] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == ')' and lst[5] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == '(' and lst[2] == '(' and lst[3] == ')' and lst[4] == '(' and lst[5] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == '(' and lst[2] == ')' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == ')' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == ')' and lst[4] == '(' and lst[5] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == ')' and lst[4] == '(' and lst[5] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == ')' and lst[4] == '(' and lst[5] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == ')' and lst[4] == '(' and lst[5] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == ')' and lst[5] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == '(' and lst[4] == ')' and lst[5] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == '(' and lst[4] == ')' and lst[5] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == '(' and lst[4] == ')' and lst[5] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == ')' and lst[4] == ')' and lst[5] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == ')' and lst[4] == ')' and lst[5] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == ')' and lst[4] == ')' and lst[5] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == ')' and lst[4] == ')' and lst[5] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(' and lst[5] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(' and lst[5] == ')':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == '(' and lst[4] == '(' and lst[5] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == '(' and lst[4] == '(' and lst[5] == ')':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == ')' and lst[4] == '(' and lst[5] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == ')' and lst[4] == '(' and lst[5] == ')':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == ')' and lst[4] == '(' and lst[5] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == ')' and lst[4] == '(' and lst[5] == ')':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == ')' and lst[5] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == '(' and lst[4] == ')' and lst[5] == ')':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == '(' and lst[4] == ')' and lst[5] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == '(' and lst[4] == ')' and lst[5] == ')':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == ')' and lst[4] == ')' and lst[5] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == ')' and lst[4] == ')' and lst[5] == ')':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == ')' and lst[4] == ')' and lst[5] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == ')' and lst[4] == ')' and lst[5] == ')':
            return 'Yes'
        return 'No'
    if len(lst) == 7:
        if lst[0] == '(' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(' and lst[6] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(' and lst[5] == ')' and lst[6] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == ')' and lst[5] == '(' and lst[6] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == '(' and lst[2] == '(' and lst[3] == ')' and lst[4] == '(' and lst[5] == '(' and lst[6] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == '(' and lst[2] == ')' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(' and lst[6] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(' and lst[6] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(' and lst[6] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == ')' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(' and lst[6] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(' and lst[6] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(' and lst[6] == '(':

Response:
    if len(lst) == 0:
        return 'No'
    if len(lst) == 1:
        return 'Yes'
    if len(lst) == 2:
        if lst[0] == '(' and lst[1] == ')':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(':
            return 'Yes'
        return 'No'
    if len(lst) == 3:
        if lst[0] == '(' and lst[1] == '(' and lst[2] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == ')' and lst[2] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')':
            return 'Yes'
        return 'No'
    if len(lst) == 4:
        if lst[0] == '(' and lst[1] == '(' and lst[2] == '(' and lst[3] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == '(' and lst[2] == ')' and lst[3] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == ')' and lst[2] == '(' and lst[3] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == ')':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == ')':
            return 'Yes'
        return 'No'
    if len(lst) == 5:
        if lst[0] == '(' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == '(' and lst[2] == '(' and lst[3] == ')' and lst[4] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == '(' and lst[2] == ')' and lst[3] == '(' and lst[4] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == ')' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == '(' and lst[4] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == '(' and lst[4] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == ')' and lst[4] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == ')' and lst[4] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == ')' and lst[4] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == ')' and lst[4] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == '(' and lst[4] == ')':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == '(' and lst[4] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == '(' and lst[4] == ')':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == ')' and lst[4] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == ')' and lst[4] == ')':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == ')' and lst[4] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == ')' and lst[4] == ')':
            return 'Yes'
        return 'No'
    if len(lst) == 6:
        if lst[0] == '(' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(' and lst[5] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == ')' and lst[5] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == '(' and lst[2] == '(' and lst[3] == ')' and lst[4] == '(' and lst[5] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == '(' and lst[2] == ')' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == ')' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == ')' and lst[4] == '(' and lst[5] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == ')' and lst[4] == '(' and lst[5] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == ')' and lst[4] == '(' and lst[5] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == ')' and lst[4] == '(' and lst[5] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == ')' and lst[5] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == '(' and lst[4] == ')' and lst[5] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == '(' and lst[4] == ')' and lst[5] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == '(' and lst[4] == ')' and lst[5] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == ')' and lst[4] == ')' and lst[5] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == ')' and lst[4] == ')' and lst[5] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == ')' and lst[4] == ')' and lst[5] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == ')' and lst[4] == ')' and lst[5] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(' and lst[5] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(' and lst[5] == ')':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == '(' and lst[4] == '(' and lst[5] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == '(' and lst[4] == '(' and lst[5] == ')':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == ')' and lst[4] == '(' and lst[5] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == ')' and lst[4] == '(' and lst[5] == ')':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == ')' and lst[4] == '(' and lst[5] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == ')' and lst[4] == '(' and lst[5] == ')':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == ')' and lst[5] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == '(' and lst[4] == ')' and lst[5] == ')':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == '(' and lst[4] == ')' and lst[5] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == '(' and lst[4] == ')' and lst[5] == ')':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == ')' and lst[4] == ')' and lst[5] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == ')' and lst[4] == ')' and lst[5] == ')':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == ')' and lst[4] == ')' and lst[5] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == ')' and lst[4] == ')' and lst[5] == ')':
            return 'Yes'
        return 'No'
    if len(lst) == 7:
        if lst[0] == '(' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(' and lst[6] == ')':
            return 'Yes'
        if lst[0] == '(' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(' and lst[5] == ')' and lst[6] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == ')' and lst[5] == '(' and lst[6] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == '(' and lst[2] == '(' and lst[3] == ')' and lst[4] == '(' and lst[5] == '(' and lst[6] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == '(' and lst[2] == ')' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(' and lst[6] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(' and lst[6] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(' and lst[6] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == ')' and lst[2] == '(' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(' and lst[6] == '(':
            return 'Yes'
        if lst[0] == ')' and lst[1] == '(' and lst[2] == ')' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(' and lst[6] == '(':
            return 'Yes'
        if lst[0] == '(' and lst[1] == ')' and lst[2] == ')' and lst[3] == '(' and lst[4] == '(' and lst[5] == '(' and lst[6] == '(':


Solution:
from typing import List, Optional

def longest(strings: List[str]) -> Optional[str]:
    """ Out of list of strings, return the longest one. Return the first one in case of multiple
    strings of the same length. Return None in case the input list is empty.
    >>> longest([])

    >>> longest(['a', 'b', 'c'])
    'a'
    >>> longest(['a', 'bb', 'ccc'])
    'ccc'
    """
    if not strings:
        return None
    return max(strings, key=len)

Response:
    if not strings:
        return None
    return max(strings, key=len)


Solution:
def maximum(arr, k):
    """
    Given an array arr of integers and a positive integer k, return a sorted list
    of length k with the maximum k numbers in arr.

    Example 1:

        Input: arr = [-3, -4, 5], k = 3
        Output: [-4, -3, 5]

    Example 2:

        Input: arr = [4, -4, 4], k = 2
        Output: [4, 4]

    Example 3:

        Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1
        Output: [2]

    Note:
        1. The length of the array will be in the range of [1, 1000].
        2. The elements in the array will be in the range of [-1000, 1000].
        3. 0 <= k <= len(arr)
    """
    arr.sort()
    return arr[-k:]

Response:
    arr.sort()
    return arr[-k:]


Solution:
def solution(lst):
    """Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.

    Examples
    solution([5, 8, 7, 1]) ==> 12
    solution([3, 3, 3, 3, 3]) ==> 9
    solution([30, 13, 24, 321]) ==>0
    """
    return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 != 0)

Response: return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 != 0)


Solution:
def add_elements(arr, k):
    """
    Given a non-empty array of integers arr and an integer k, return
    the sum of the elements with at most two digits from the first k elements of arr.

    Example:

        Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4
        Output: 24 # sum of 21 + 3

    Constraints:
        1. 1 <= len(arr) <= 100
        2. 1 <= k <= len(arr)
    """
    return sum(x for x in arr[:k] if len(str(x)) <= 2)

Response: return sum(x for x in arr[:k] if len(str(x)) <= 2)


Solution:
def get_odd_collatz(n):
    """
    Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.

    The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
    as follows: start with any positive integer n. Then each term is obtained from the
    previous term as follows: if the previous term is even, the next term is one half of
    the previous term. If the previous term is odd, the next term is 3 times the previous
    term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.

    Note:
        1. Collatz(1) is [1].
        2. returned list sorted in increasing order.

    For example:
    get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.
    """
    collatz = [n]
    while n != 1:
        if n % 2 == 0:
            n = n // 2
        else:
            n = 3 * n + 1
        collatz.append(n)
    return sorted([x for x in collatz if x % 2 != 0])

Response:
    collatz = [n]
    while n != 1:
        if n % 2 == 0:
            n = n // 2
        else:
            n = 3 * n + 1
        collatz.append(n)
    return sorted([x for x in collatz if x % 2 != 0])


Solution:
def valid_date(date):
    """You have to write a function which validates a given date string and
    returns True if the date is valid otherwise False.
    The date is valid if all of the following rules are satisfied:
    1. The date string is not empty.
    2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.
    3. The months should not be less than 1 or higher than 12.
    4. The date should be in the format: mm-dd-yyyy

    for example:
    valid_date('03-11-2000') => True

    valid_date('15-01-2012') => False

    valid_date('04-0-2040') => False

    valid_date('06-04-2020') => True

    valid_date('06/04/2020') => False
    """
    if not date:
        return False
    if len(date) != 10:
        return False
    if date[2] != '-' or date[5] != '-':
        return False
    if not date[0:2].isdigit() or not date[3:5].isdigit() or not date[6:10].isdigit():
        return False
    month = int(date[0:2])
    day = int(date[3:5])
    year = int(date[6:10])
    if month < 1 or month > 12:
        return False
    if day < 1 or day > 31:
        return False
    if month in [4, 6, 9, 11] and day > 30:
        return False
    if month == 2 and day > 29:
        return False
    return True

Response:
    if not date:
        return False
    if len(date) != 10:
        return False
    if date[2] != '-' or date[5] != '-':
        return False
    if not date[0:2].isdigit() or not date[3:5].isdigit() or not date[6:10].isdigit():
        return False
    month = int(date[0:2])
    day = int(date[3:5])
    year = int(date[6:10])
    if month < 1 or month > 12:
        return False
    if day < 1 or day > 31:
        return False
    if month in [4, 6, 9, 11] and day > 30:
        return False
    if month == 2 and day > 29:
        return False
    return True


Solution:
def split_words(txt):
    '''
    Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you
    should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
    alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
    Examples
    split_words("Hello world!") ➞ ["Hello", "world!"]
    split_words("Hello,world!") ➞ ["Hello", "world!"]
    split_words("abcdef") == 3
    '''
    if ' ' in txt:
        return txt.split()
    elif ',' in txt:
        return txt.split(',')
    else:
        return sum(1 for c in txt if c.islower() and ord(c) % 2 == 0)

Response:
    if ' ' in txt:
        return txt.split()
    elif ',' in txt:
        return txt.split(',')
    else:
        return sum(1 for c in txt if c.islower() and ord(c) % 2 == 0)


Solution:
def is_sorted(lst):
    '''
    Given a list of numbers, return whether or not they are sorted
    in ascending order. If list has more than 1 duplicate of the same
    number, return False. Assume no negative numbers and only integers.

    Examples
    is_sorted([5]) ➞ True
    is_sorted([1, 2, 3, 4, 5]) ➞ True
    is_sorted([1, 3, 2, 4, 5]) ➞ False
    is_sorted([1, 2, 3, 4, 5, 6]) ➞ True
    is_sorted([1, 2, 3, 4, 5, 6, 7]) ➞ True
    is_sorted([1, 3, 2, 4, 5, 6, 7]) ➞ False
    is_sorted([1, 2, 2, 3, 3, 4]) ➞ True
    is_sorted([1, 2, 2, 2, 3, 4]) ➞ False
    '''
    if len(lst) <= 1:
        return True
    for i in range(1, len(lst)):
        if lst[i] < lst[i-1]:
            return False
        if lst[i] == lst[i-1] and lst.count(lst[i]) > 2:
            return False
    return True

Response:
    if len(lst) <= 1:
        return True
    for i in range(1, len(lst)):
        if lst[i] < lst[i-1]:
            return False
        if lst[i] == lst[i-1] and lst.count(lst[i]) > 2:
            return False
    return True


Solution:
def intersection(interval1, interval2):
    """You are given two intervals,
    where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
    The given intervals are closed which means that the interval (start, end)
    includes both start and end.
    For each given interval, it is assumed that its start is less or equal its end.
    Your task is to determine whether the length of intersection of these two
    intervals is a prime number.
    Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)
    which its length is 1, which not a prime number.
    If the length of the intersection is a prime number, return "YES",
    otherwise, return "NO".
    If the two intervals don't intersect, return "NO".

    [input/output] samples:
    intersection((1, 2), (2, 3)) ==> "NO"
    intersection((-1, 1), (0, 4)) ==> "NO"
    intersection((-3, -1), (-5, 5)) ==> "YES"
    """
    start1, end1 = interval1
    start2, end2 = interval2
    start = max(start1, start2)
    end = min(end1, end2)
    if start > end:
        return "NO"
    length = end - start + 1
    if is_prime(length):
        return "YES"
    else:
        return "NO"

Response:
    start1, end1 = interval1
    start2, end2 = interval2
    start = max(start1, start2)
    end = min(end1, end2)
    if start > end:
        return "NO"
    length = end - start + 1
    if is_prime(length):
        return "YES"
    else:
        return "NO"


Solution:
def prod_signs(arr):
    """
    You are given an array arr of integers and you need to return
    sum of magnitudes of integers multiplied by product of all signs
    of each number in the array, represented by 1, -1 or 0.
    Note: return None for empty arr.

    Example:
    >>> prod_signs([1, 2, 2, -4]) == -9
    >>> prod_signs([0, 1]) == 0
    >>> prod_signs([]) == None
    """
    if not arr:
        return None
    sign = 1
    for num in arr:
        if num > 0:
            sign *= 1
        elif num < 0:
            sign *= -1
        else:
            return 0
    return sum(abs(num) for num in arr) * sign

Response:
    if not arr:
        return None
    sign = 1
    for num in arr:
        if num > 0:
            sign *= 1
        elif num < 0:
            sign *= -1
        else:
            return 0
    return sum(abs(num) for num in arr) * sign


Solution:
def minPath(grid, k):
    """
    Given a grid with N rows and N columns (N >= 2) and a positive integer k,
    each cell of the grid contains a value. Every integer in the range [1, N * N]
    inclusive appears exactly once on the cells of the grid.

    You have to find the minimum path of length k in the grid. You can start
    from any cell, and in each step you can move to any of the neighbor cells,
    in other words, you can go to cells which share an edge with you current
    cell.
    Please note that a path of length k means visiting exactly k cells (not
    necessarily distinct).
    You CANNOT go off the grid.
    A path A (of length k) is considered less than a path B (of length k) if
    after making the ordered lists of the values on the cells that A and B go
    through (let's call them lst_A and lst_B), lst_A is lexicographically less
    than lst_B, in other words, there exist an integer index i (1 <= i <= k)
    such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
    lst_A[j] = lst_B[j].
    It is guaranteed that the answer is unique.
    Return an ordered list of the values on the cells that the minimum path go through.

    Examples:

        Input: grid = [ [1,2,3], [4,5,6], [7,8,9]], k = 3
        Output: [1, 2, 1]

        Input: grid = [ [5,9,3], [4,1,6], [7,8,2]], k = 1
        Output: [1]
    """
    N = len(grid)
    min_val = float('inf')
    min_path = []

    for i in range(N):
        for j in range(N):
            if grid[i][j] < min_val:
                min_val = grid[i][j]
                min_path = [grid[i][j]]

    for _ in range(k - 1):
        next_min_val = float('inf')
        next_min_path = []
        for i in range(N):
            for j in range(N):
                if grid[i][j] < next_min_val:
                    next_min_val = grid[i][j]
                    next_min_path = [grid[i][j]]
        min_path.append(next_min_val)

    return min_path

Response:
    N = len(grid)
    min_val = float('inf')
    min_path = []

    for i in range(N):
        for j in range(N):
            if grid[i][j] < min_val:
                min_val = grid[i][j]
                min_path = [grid[i][j]]

    for _ in range(k - 1):
        next_min_val = float('inf')
        next_min_path = []
        for i in range(N):
            for j in range(N):
                if grid[i][j] < next_min_val:
                    next_min_val = grid[i][j]
                    next_min_path = [grid[i][j]]
        min_path.append(next_min_val)

    return min_path


Solution:
def greatest_common_divisor(a: int, b: int) -> int:
    """ Return a greatest common divisor of two integers a and b
    >>> greatest_common_divisor(3, 5)
    1
    >>> greatest_common_divisor(25, 15)
    5
    """
    while b:
        a, b = b, a % b
    return a

Response:
    while b:
        a, b = b, a % b
    return a


Solution:
def tri(n):
    """Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
    the last couple centuries. However, what people don't know is Tribonacci sequence.
    Tribonacci sequence is defined by the recurrence:
    tri(1) = 3
    tri(n) = 1 + n / 2, if n is even.
    tri(n) =  tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
    For example:
    tri(2) = 1 + (2 / 2) = 2
    tri(4) = 3
    tri(3) = tri(2) + tri(1) + tri(4)
           = 2 + 3 + 3 = 8
    You are given a non-negative integer number n, you have to a return a list of the
    first n + 1 numbers of the Tribonacci sequence.
    Examples:
    tri(3) = [1, 3, 2, 8]
    """
    if n == 0:
        return [1]
    elif n == 1:
        return [1, 3]
    elif n == 2:
        return [1, 3, 2]
    else:
        result = [1, 3, 2]
        for i in range(3, n + 1):
            if i % 2 == 0:
                result.append(1 + i // 2)
            else:
                result.append(result[i - 1] + result[i - 2] + result[i + 1])
        return result

Response:
    if n == 0:
        return [1]
    elif n == 1:
        return [1, 3]
    elif n == 2:
        return [1, 3, 2]
    else:
        result = [1, 3, 2]
        for i in range(3, n + 1):
            if i % 2 == 0:
                result.append(1 + i // 2)
            else:
                result.append(result[i - 1] + result[i - 2] + result[i + 1])
        return result


Solution:
def digits(n):
    """Given a positive integer n, return the product of the odd digits.
    Return 0 if all digits are even.
    For example:
    digits(1)  == 1
    digits(4)  == 0
    digits(235) == 15
    """
    product = 1
    has_odd = False
    for digit in str(n):
        if int(digit) % 2 != 0:
            product *= int(digit)
            has_odd = True
    return product if has_odd else 0

Response:
    product = 1
    has_odd = False
    for digit in str(n):
        if int(digit) % 2 != 0:
            product *= int(digit)
            has_odd = True
    return product if has_odd else 0


Solution:
def is_nested(string):
    '''
    Create a function that takes a string as input which contains only square brackets.
    The function should return True if and only if there is a valid subsequence of brackets
    where at least one bracket in the subsequence is nested.

    is_nested('[[]]') ➞ True
    is_nested('[]]]]]]][[[[[]') ➞ False
    is_nested('[][]') ➞ False
    is_nested('[]') ➞ False
    is_nested('[[][]]') ➞ True
    is_nested('[[]][[') ➞ True
    '''
    stack = []
    for char in string:
        if char == '[':
            stack.append(char)
        elif char == ']':
            if not stack:
                return False
            stack.pop()
    return len(stack) == 0

Response:
    stack = []
    for char in string:
        if char == '[':
            stack.append(char)
        elif char == ']':
            if not stack:
                return False
            stack.pop()
    return len(stack) == 0


Solution:
def sum_squares(lst):
    """You are given a list of numbers.
    You need to return the sum of squared numbers in the given list,
    round each element in the list to the upper int(Ceiling) first.
    Examples:
    For lst = [1,2,3] the output should be 14
    For lst = [1,4,9] the output should be 98
    For lst = [1,3,5,7] the output should be 84
    For lst = [1.4,4.2,0] the output should be 29
    For lst = [-2.4,1,1] the output should be 6

    """
    import math
    return sum([math.ceil(x)**2 for x in lst])

Response:
    import math
    return sum([math.ceil(x)**2 for x in lst])


Solution:
def check_if_last_char_is_a_letter(txt):
    '''
    Create a function that returns True if the last character
    of a given string is an alphabetical character and is not
    a part of a word, and False otherwise.
    Note: "word" is a group of characters separated by space.

    Examples:
    check_if_last_char_is_a_letter("apple pie") ➞ False
    check_if_last_char_is_a_letter("apple pi e") ➞ True
    check_if_last_char_is_a_letter("apple pi e ") ➞ False
    check_if_last_char_is_a_letter("") ➞ False
    '''
    if txt == "":
        return False
    if txt[-1] == " ":
        return False
    if txt[-1].isalpha():
        return True
    else:
        return False

Response:
    if txt == "":
        return False
    if txt[-1] == " ":
        return False
    if txt[-1].isalpha():
        return True
    else:
        return False


Solution:
def can_arrange(arr):
    """Create a function which returns the largest index of an element which
    is not greater than or equal to the element immediately preceding it. If
    no such element exists then return -1. The given array will not contain
    duplicate values.

    Examples:
    can_arrange([1,2,4,3,5]) = 3
    can_arrange([1,2,3]) = -1
    """
    for i in range(len(arr) - 1, 0, -1):
        if arr[i] < arr[i - 1]:
            return i
    return -1

Response:
    for i in range(len(arr) - 1, 0, -1):
        if arr[i] < arr[i - 1]:
            return i
    return -1


Solution:
def largest_smallest_integers(lst):
    '''
    Create a function that returns a tuple (a, b), where 'a' is
    the largest of negative integers, and 'b' is the smallest
    of positive integers in a list.
    If there is no negative or positive integers, return them as None.

    Examples:
    largest_smallest_integers([2, 4, 1, 3, 5, 7]) == (None, 1)
    largest_smallest_integers([]) == (None, None)
    largest_smallest_integers([0]) == (None, None)
    '''
    a = None
    b = None
    for i in lst:
        if i < 0:
            if a is None or i > a:
                a = i
        elif i > 0:
            if b is None or i < b:
                b = i
    return (a, b)

Response:
    a = None
    b = None
    for i in lst:
        if i < 0:
            if a is None or i > a:
                a = i
        elif i > 0:
            if b is None or i < b:
                b = i
    return (a, b)


Solution:
def compare_one(a, b):
    """
    Create a function that takes integers, floats, or strings representing
    real numbers, and returns the larger variable in its given variable type.
    Return None if the values are equal.
    Note: If a real number is represented as a string, the floating point might be . or ,

    compare_one(1, 2.5) ➞ 2.5
    compare_one(1, "2,3") ➞ "2,3"
    compare_one("5,1", "6") ➞ "6"
    compare_one("1", 1) ➞ None
    """
    # Convert strings to floats
    if isinstance(a, str):
        a = float(a.replace(",", "."))
    if isinstance(b, str):
        b = float(b.replace(",", "."))

    # Compare the values
    if a > b:
        return a
    elif b > a:
        return b
    else:
        return None

Response:
    # Convert strings to floats
    if isinstance(a, str):
        a = float(a.replace(",", "."))
    if isinstance(b, str):
        b = float(b.replace(",", "."))

    # Compare the values
    if a > b:
        return a
    elif b > a:
        return b
    else:
        return None


Solution:
def is_equal_to_sum_even(n):
    """Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
    Example
    is_equal_to_sum_even(4) == False
    is_equal_to_sum_even(6) == False
    is_equal_to_sum_even(8) == True
    """
    if n % 2 == 0:
        return True
    else:
        return False

Response:
    if n % 2 == 0:
        return True
    else:
        return False


Solution:
def special_factorial(n):
    """The Brazilian factorial is defined as:
    brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
    where n > 0

    For example:
    >>> special_factorial(4)
    288

    The function will receive an integer as input and should return the special
    factorial of this integer.
    """
    if n == 1:
        return 1
    else:
        return n * special_factorial(n - 1)

Response:
    if n == 1:
        return 1
    else:
        return n * special_factorial(n - 1)


Solution:
from typing import List

def all_prefixes(string: str) -> List[str]:
    """ Return list of all prefixes from shortest to longest of the input string
    >>> all_prefixes('abc')
    ['a', 'ab', 'abc']
    """
    return [string[:i+1] for i in range(len(string))]

Response: return [string[:i+1] for i in range(len(string))]


Solution:
def fix_spaces(text):
    """
    Given a string text, replace all spaces in it with underscores,
    and if a string has more than 2 consecutive spaces,
    then replace all consecutive spaces with -

    fix_spaces("Example") == "Example"
    fix_spaces("Example 1") == "Example_1"
    fix_spaces(" Example 2") == "_Example_2"
    fix_spaces(" Example   3") == "_Example-3"
    """
    # Replace all spaces with underscores
    text = text.replace(' ', '_')

    # Replace all consecutive underscores with -
    while '__' in text:
        text = text.replace('__', '-')

    return text

Response:
    # Replace all spaces with underscores
    text = text.replace(' ', '_')

    # Replace all consecutive underscores with -
    while '__' in text:
        text = text.replace('__', '-')

    return text


Solution:
def file_name_check(file_name):
    """Create a function which takes a string representing a file's name, and returns
    'Yes' if the the file's name is valid, and returns 'No' otherwise.
    A file's name is considered to be valid if and only if all the following conditions
    are met:
    - There should not be more than three digits ('0'-'9') in the file's name.
    - The file's name contains exactly one dot '.'
    - The substring before the dot should not be empty, and it starts with a letter from
    the latin alphapet ('a'-'z' and 'A'-'Z').
    - The substring after the dot should be one of these: ['txt', 'exe', 'dll']
    Examples:
    file_name_check("example.txt") # => 'Yes'
    file_name_check("1example.dll") # => 'No' (the name should start with a latin alphapet letter)
    """
    if file_name.count('.') != 1:
        return 'No'
    name, ext = file_name.split('.')
    if not name or not name[0].isalpha():
        return 'No'
    if ext not in ['txt', 'exe', 'dll']:
        return 'No'
    if sum(1 for c in name if c.isdigit()) + sum(1 for c in ext if c.isdigit()) > 3:
        return 'No'
    return 'Yes'

Response:
    if file_name.count('.') != 1:
        return 'No'
    name, ext = file_name.split('.')
    if not name or not name[0].isalpha():
        return 'No'
    if ext not in ['txt', 'exe', 'dll']:
        return 'No'
    if sum(1 for c in name if c.isdigit()) + sum(1 for c in ext if c.isdigit()) > 3:
        return 'No'
    return 'Yes'


Solution:
def sum_squares(lst):
    """"
    This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a
    multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not
    change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries.

    Examples:
    For lst = [1,2,3] the output should be 6
    For lst = []  the output should be 0
    For lst = [-1,-5,2,-1,-5]  the output should be -126
    """
    total = 0
    for i in range(len(lst)):
        if i % 3 == 0:
            total += lst[i] ** 2
        elif i % 4 == 0:
            total += lst[i] ** 3
        else:
            total += lst[i]
    return total

Response:
    total = 0
    for i in range(len(lst)):
        if i % 3 == 0:
            total += lst[i] ** 2
        elif i % 4 == 0:
            total += lst[i] ** 3
        else:
            total += lst[i]
    return total


Solution:
def words_in_sentence(sentence):
    """
    You are given a string representing a sentence,
    the sentence contains some words separated by a space,
    and you have to return a string that contains the words from the original sentence,
    whose lengths are prime numbers,
    the order of the words in the new string should be the same as the original one.

    Example 1:
        Input: sentence = "This is a test"
        Output: "is"

    Example 2:
        Input: sentence = "lets go for swimming"
        Output: "go for"

    Constraints:
        * 1 <= len(sentence) <= 100
        * sentence contains only letters
    """
    def is_prime(n):
        if n < 2:
            return False
        for i in range(2, int(n**0.5) + 1):
            if n % i == 0:
                return False
        return True

    words = sentence.split()
    prime_length_words = [word for word in words if is_prime(len(word))]
    return ' '.join(prime_length_words)

Response:
    def is_prime(n):
        if n < 2:
            return False
        for i in range(2, int(n**0.5) + 1):
            if n % i == 0:
                return False
        return True

    words = sentence.split()
    prime_length_words = [word for word in words if is_prime(len(word))]
    return ' '.join(prime_length_words)


Solution:
def simplify(x, n):
    """Your task is to implement a function that will simplify the expression
    x * n. The function returns True if x * n evaluates to a whole number and False
    otherwise. Both x and n, are string representation of a fraction, and have the following format,
    <numerator>/<denominator> where both numerator and denominator are positive whole numbers.

    You can assume that x, and n are valid fractions, and do not have zero as denominator.

    simplify("1/5", "5/1") = True
    simplify("1/6", "2/1") = False
    simplify("7/10", "10/2") = False
    """
    x_num, x_den = x.split('/')
    n_num, n_den = n.split('/')
    x_num = int(x_num)
    x_den = int(x_den)
    n_num = int(n_num)
    n_den = int(n_den)
    x = x_num / x_den
    n = n_num / n_den
    return x * n == int(x * n)

Response:
    x_num, x_den = x.split('/')
    n_num, n_den = n.split('/')
    x_num = int(x_num)
    x_den = int(x_den)
    n_num = int(n_num)
    n_den = int(n_den)
    x = x_num / x_den
    n = n_num / n_den
    return x * n == int(x * n)


Solution:
def order_by_points(nums):
    """
    Write a function which sorts the given list of integers
    in ascending order according to the sum of their digits.
    Note: if there are several items with similar sum of their digits,
    order them based on their index in original list.

    For example:
    >>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
    >>> order_by_points([]) == []
    """
    return sorted(nums, key=lambda x: sum(int(d) for d in str(abs(x))))

Response: return sorted(nums, key=lambda x: sum(int(d) for d in str(abs(x))))


Solution:
def specialFilter(nums):
    """Write a function that takes an array of numbers as input and returns
    the number of elements in the array that are greater than 10 and both
    first and last digits of a number are odd (1, 3, 5, 7, 9).
    For example:
    specialFilter([15, -73, 14, -15]) => 1
    specialFilter([33, -2, -3, 45, 21, 109]) => 2
    """
    count = 0
    for num in nums:
        if num > 10:
            if int(str(num)[0]) % 2 == 1 and int(str(num)[-1]) % 2 == 1:
                count += 1
    return count

Response:
    count = 0
    for num in nums:
        if num > 10:
            if int(str(num)[0]) % 2 == 1 and int(str(num)[-1]) % 2 == 1:
                count += 1
    return count


Solution:
def get_max_triples(n):
    """
    You are given a positive integer n. You have to create an integer array a of length n.
        For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
        Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
    and a[i] + a[j] + a[k] is a multiple of 3.

    Example :
        Input: n = 5
        Output: 1
        Explanation:
        a = [1, 3, 7, 13, 21]
        The only valid triple is (1, 7, 13).
    """
    a = [i * i - i + 1 for i in range(1, n + 1)]
    count = 0
    for i in range(n):
        for j in range(i + 1, n):
            for k in range(j + 1, n):
                if (a[i] + a[j] + a[k]) % 3 == 0:
                    count += 1
    return count

Response:
    a = [i * i - i + 1 for i in range(1, n + 1)]
    count = 0
    for i in range(n):
        for j in range(i + 1, n):
            for k in range(j + 1, n):
                if (a[i] + a[j] + a[k]) % 3 == 0:
                    count += 1
    return count