Update Automated MNLP evaluation report (2026-06-09)

EVAL_REPORT.md

@@ -2,23 +2,23 @@
 
 - **Model repo:** [`cs-552-2026-thinking-tokens/general_knowledge_model`](https://huggingface.co/cs-552-2026-thinking-tokens/general_knowledge_model)
 - **Owner(s):** group **thinking-tokens**
-- **Generated at:** 2026-06-08T04:40:54+00:00 (UTC)
+- **Generated at:** 2026-06-09T08:56:40+00:00 (UTC)
 - **Pipeline:** [mnlp-project-ci](https://github.com/eric11eca/mnlp-project-ci)
 
 _This PR is opened automatically by the course CI. It is **non-blocking** — you do not need to merge it. The next nightly run will refresh this file._
 
 ## Evaluated checkpoint
 
-- **Commit:** [`3dade21`](https://huggingface.co/cs-552-2026-thinking-tokens/general_knowledge_model/commit/3dade21d4454015942e40dab74360bb2fa82960e)
-- **Message:** Update generation_config.json
-- **Committed:** 2026-06-07T21:40:33+00:00
+- **Commit:** [`e1898f3`](https://huggingface.co/cs-552-2026-thinking-tokens/general_knowledge_model/commit/e1898f3acea9101ef00b63b9fb7392e9e67af3b1)
+- **Message:** upload prompt model
+- **Committed:** 2026-06-08T18:27:23+00:00
 
 ## Summary
 
 | Benchmark | Accuracy | Status |
 |---|---:|---|
 | Math | — | not run |
-| Knowledge | 0.3000 | ok |
+| Knowledge | 0.4700 | ok |
 | Multilingual | — | not run |
 | Safety | — | not run |
 
@@ -37,22 +37,107 @@ _Prompts are intentionally omitted to avoid revealing benchmark contents. For mu
 
     ```text
     <think>
-    We need to determine how much insurance will pay for Frank Hartman's car after a $2,350 damage. ThomasSiden has property-damage insurance on his car with a $5,000 limit. This means that the insurance company will cover up to the $5,000 limit, but not more than that. Since the damage is $2,350, which is less than $5,000, the insurance company will pay the full amount of the damage, not less. Therefore, the correct answer is the amount of the damage itself. The options include $2,350 as an option, so that is the correct choice.
+    Okay, let's try to figure out this quantum mechanics problem. So, the question is about a particle in a three-dimensional isotropic harmonic oscillator potential. The potential is given by V(r) = (1/2)mω²r², which makes sense because that's the form for a harmonic oscillator potential, right? The force is Hooke's law, so that's consistent with the potential being quadratic in r.
     
+    The quest
+    
+    ... [truncated 823 chars] ...
+    
+    ic harmonic oscillator. The energy levels of such a system are quantized and given by the formula:
+    
+    $$
+    E = \left(n + \frac{3}{2}\right) \hbar \omega
+    $$
+    
+    where $ n $ is the total number of quanta (i.e., the sum of the quantum numbers in each direction: $ n_x + n_y + n_z $).
+    
+    The **third excited state** corresponds to $ n = 3 $, since the ground state is $ n = 0 $, and the first excited state is $ n = 1 $, the second excited state is $ n = 2 $, and the third excited state is $ n = 3 $.
+    
+    Thus, the energy of the third excited state is:
+    
+    $$
+    E = \left(3 + \frac{3}{2}\right) \hbar \omega = \frac{9}{2} \hbar \omega
+    $$
+    
+    For the number of linearly independent eigenfunctions associated with this energy level, we consider the number of ways to distribute $ n = 3 $ quanta among the three directions $ x, y, z $. This is equivalent to finding the number of non-negative integer solutions to the equation:
+    
+    $$
+    n_x + n_y + n_z = 3
+    $$
+    
+    The number of such solutions is given by the combinatorial formula:
+    
+    $$
+    \text{Number of solutions} = \binom{n + 2}{2} = \binom{3 + 2}{2} = \binom{5}{2} = 10
+    $$
+    
+    Therefore, the number of linearly independent eigenfunctions is 10.
+    
+    ---
+    
+    **Final Answer:**  
+    $$
     \boxed{D}
+    $$
     ```
 
 **Incorrect** (1 shown)
 
-- **reference**: `C`
+- **reference**: `B`
 - **overall** (0/1 completions correct)
-- **extracted** (✗): `H`
+- **extracted** (✗): `C`
 - **completion**:
 
     ```text
     <think>
-    The patient's symptoms of urinary frequency and incontinence that begin a few days before flights and resolve the day after are classic signs of psychosomatic urinary incontinence. These symptoms are often triggered by stress, anxiety, or other psychological factors, particularly when the patient is about to travel. The only medication she takes is an oral contraceptive, which is not indicated for this condition. The other options are either unnecessary (diet change, behavioral therapy, physical therapy, psychoanalytic psychotherapy) or not indicated (neurological examination, sexual history review, stopping contraceptives). Therefore, the most appropriate next step is to advise her to stop taking oral contraceptives, as they are likely the cause of the symptoms.
-    </think>
+    Okay, let's try to figure out this problem. So, the question is about what product is formed when 3,4-dimethylhexanedial is treated with a series of reagents. The choices are A, B, C, D. Let me break it down step by step.
+    
+    First, I need to recall what each of these reagents does. Let's go through each step one by one.
+    
+    The first reagent is KOH, H2O, THF, Heat. I remember that KOH is a stro
+    
+    ... [truncated 823 chars] ...
+    
+    arboxylic acid.
+    
+    ---
+    
+    ### **Step 3: Reaction with PCC, CH₂Cl₂ (Oxidation)**
+    
+    - **Reagent:** PCC is a **reagent for oxidizing alcohols to ketones**.
+    - **Effect:** The ester is now a **secondary alcohol**, and PCC oxidizes it to a **ketone**.
+    
+    **Product after Step 3:**  
+    - The ester is now a **ketone**, with the oxygen atoms from the ester group forming a double bond with the carbonyl group.
+    
+    ---
+    
+    ### **Step 4: Reaction with O₃, H₂O₂ (Ozonolysis)**
+    
+    - **Reagent:** Ozonolysis cleaves the double bonds in the molecule.
+    - **Effect:** The ketone is cleaved into **carboxylic acid groups**.
+    
+    ---
+    
+    ### **Final Product Analysis**
+    
+    Now, we consider the **structure** of the final product:
+    
+    - The original compound is **3,4-dimethylhexanedial**, which has:
+      - Two methyl groups on carbons 3 and 4.
+      - An aldehyde group on carbon 6.
+    - After hydrolysis, the aldehyde becomes a carboxylic acid.
+    - After Grignard addition and oxidation, the molecule becomes a **ketone**.
+    - Ozonolysis cleaves the ketone into **carboxylic acid groups**.
+    
+    The final product is a **carboxylic acid** with the structure:  
+    **3,4-dimethyl-5,6-dioxooctanal**, which matches **Option C**.
+    
+    ---
+    
+    ### ✅ Final Answer:
     
-    \boxed{H}
+    $$
+    \boxed{C}
+    $$
     ```